861. Score After Flipping Matrix】的更多相关文章

We have a two dimensional matrix A where each value is 0 or 1. A move consists of choosing any row or column, and toggling each value in that row or column: changing all 0s to 1s, and all 1s to 0s. After making any number of moves, every row of this…
We have a two dimensional matrix A where each value is 0 or 1. A move consists of choosing any row or column, and toggling each value in that row or column: changing all 0s to 1s, and all 1s to 0s. After making any number of moves, every row of this…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 日期 题目地址:https://leetcode.com/problems/score-after-flipping-matrix/description/ 题目描述 We have a two dimensional matrix A where each value is 0 or 1. A move consists of choosing a…
题目如下: 解题思路:本题需要知道一个数字规律,即pow(2,n) > sum(pow(2,0)+pow(2,1)+...+pow(2,n-1)).所以,为了获得最大值,要保证所有行的最高位是1,即需要优先进行行变换,把最高位变成1.接下来就是列变换,把0多于1的列做变换变成1多于0的列即可. 代码如下: class Solution(object): def matrixScore(self, A): """ :type A: List[List[int]] :rty…
We have a two dimensional matrix A where each value is 0 or 1. A move consists of choosing any row or column, and toggling each value in that row or column: changing all 0s to 1s, and all 1s to 0s. After making any number of moves, every row of this…
We have a two dimensional matrix A where each value is 0 or 1. A move consists of choosing any row or column, and toggling each value in that row or column: changing all 0s to 1s, and all 1s to 0s. After making any number of moves, every row of this…
贪心基础 贪心(Greedy)常用于解决最优问题,以期通过某种策略获得一系列局部最优解.从而求得整体最优解. 贪心从局部最优角度考虑,只适用于具备无后效性的问题,即某个状态以前的过程不影响以后的状态.紧接下来的状态仅与当前状态有关.和分治.动态规划一样,贪心是一种思路,不是解决某类问题的具体方法. 应用贪心的关键,是甄别问题是否具备无后效性.找到获得局部最优的策略.有的问题比较浅显,例如一道找零钱的题目 LeetCode 860. Lemonade Change: // 860. Lemonad…
All LeetCode Questions List(Part of Answers, still updating) 题目汇总及部分答案(持续更新中) Leetcode problems classified by company 题目按公司分类(Last updated: October 2, 2017) .   Top Interview Questions # Title Difficulty Acceptance 1 Two Sum Medium 17.70% 2 Add Two N…
请点击页面左上角 -> Fork me on Github 或直接访问本项目Github地址:LeetCode Solution by Swift    说明:题目中含有$符号则为付费题目. 如:[Swift]LeetCode156.二叉树的上下颠倒 $ Binary Tree Upside Down 请下拉滚动条查看最新 Weekly Contest!!! Swift LeetCode 目录 | Catalog 序        号 题名Title 难度     Difficulty  两数之…
Contest 91 (2018年10月24日,周三) 链接:https://leetcode.com/contest/weekly-contest-91/ 模拟比赛情况记录:第一题柠檬摊的那题6分钟AC,然后是第二题树的距离K的结点那题比较久,大概写了30分钟,第三题翻转矩阵那题第一次提交错误了,列的优化方法思路错了,WA.后来比赛时间到了才改过来.最后一题最短子数组的和比K大的这题不会做. [860]Lemonade Change   (第一题) 一个柠檬摊,有一队人排队要买柠檬,一个5刀,…