Friend Chains Time Limit : 2000/1000ms (Java/Other)   Memory Limit : 32768/32768K (Java/Other) Total Submission(s) : 4   Accepted Submission(s) : 2 Font: Times New Roman | Verdana | Georgia Font Size: ← → Problem Description For a group of people, th…

题意:问给定的一张图中,相距最远的两个点的距离为多少.解法:跟求树的直径差不多,从1 开始bfs,得到一个最远的点,然后再从该点bfs一遍,得到的最长距离即为答案. 代码: #include <iostream> #include <cstdio> #include <cstring> #include <cstdlib> #include <cmath> #include <algorithm> #include <strin…

题意:给定 n 个人,和关系,问你这个朋友圈里任意两者之间最短的距离是多少. 析:很明显的一个BFS,只要去找最长距离就好.如果不能全找到,就是-1. 代码如下: #pragma comment(linker, "/STACK:1024000000,1024000000") #include <cstdio> #include <string> #include <cstdlib> #include <cmath> #include &l…

Problem Description For a group of people, there is an idea that everyone is equals to or less than 6 steps away from any other person in the group, by way of introduction. So that a chain of "a friend of a friend" can be made to connect any 2 p…

http://acm.hdu.edu.cn/showproblem.php?pid=4460 水题一道,oj时间卡的非常奇怪,把spfa的queue开成全局卡线过,别的全挂了,迪杰斯特拉的手写堆都超时,可能是卡了map? #include <iostream> #include <cstdio> #include <cstring> #include <map> #include <queue> using namespace std ; con…

类似于树的直径,从随意一个点出发,找到距离该点最远的且度数最少的点. 然后再做一次最短路 Friend Chains Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 4227    Accepted Submission(s): 1359 Problem Description For a group of people, there…

题意:一些小伙伴之间有朋友关系,比如a和b是朋友,b和c是朋友,a和c不是朋友,则a和c之间存在朋友链,且大小为2,给出一些关系,求出这些关系中最大的链是多少? 求最短路的最大距离 #include<cstdio> #include<iostream> #include<algorithm> #include<cstring> #include<cmath> #include<queue> #include<map> us…

Cyclic Nacklace Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 5663    Accepted Submission(s): 2557 Problem Description CC always becomes very depressed at the end of this month, he has checke…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=3487 YaoYao is fond of playing his chains. He has a chain containing n diamonds on it. Diamonds are numbered from 1 to n.At first, the diamonds on the chain is a sequence: 1, 2, 3, …, n.He will perform t…

Problem Description CC always becomes very depressed at the end of this month, he has checked his credit card yesterday, without any surprise, there are only 99.9 yuan left. he is too distressed and thinking about how to tide over the last days. Bein…