How many integers can you find Time Limit: 12000/5000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 6001 Accepted Submission(s): 1722 Problem Description Now you get a number N, and a M-integers set, you shou…
Eddy's爱好 Time Limit: 3000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 2037 Accepted Submission(s): 857 Problem Description Ignatius 喜欢收集蝴蝶标本和邮票,但是Eddy的爱好很特别,他对数字比较感兴趣,他曾经一度沉迷于素数,而现在他对于一些新的特殊数比较有兴趣. 这些特殊数…
How many integers can you find Time Limit: 12000/5000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 6048 Accepted Submission(s): 1735 Problem Description Now you get a number N, and a M-integers set, you shou…
Problem F: 我是好人4 Description 众所周知,我是好人!所以不会出太难的题,题意很简单 给你n个数,问你1000000000(含1e9)以内有多少个正整数不是这n个数任意一个的倍数 最后友情提供解题代码(我真是太好人了) void solve(int p[], int n) { int ans = 0; for (int i = 1; i <= 1e9; i++) { int fl = 0; for (int j = 0; j < n; j++) { if (i % p[…
Visible TreesTime Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 2213 Accepted Submission(s): 908 Problem Description There are many trees forming a m * n grid, the grid starts from (1,1). Farme…
Problem F: 我是好人4 Description 众所周知,我是好人!所以不会出太难的题,题意很简单 给你n个数,问你1000000000(含1e9)以内有多少个正整数不是这n个数任意一个的倍数 最后友情提供解题代码(我真是太好人了) void solve(int p[], int n) { int ans = 0; for (int i = 1; i <= 1e9; i++) { int fl = 0; for (int j = 0; j < n; j++) { if (i % p[…
Eddy's爱好 Time Limit: 3000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Problem Description Ignatius 喜欢收集蝴蝶标本和邮票,但是Eddy的爱好很特别,他对数字比较感兴趣,他曾经一度沉迷于素数,而现在他对于一些新的特殊数比较有兴趣.这些特殊数是这样的:这些数都能表示成M^K,M和K是正整数且K>1.正当他再度沉迷的时候,他发现不知道什么时候才能知道这样的数…
Yada Number Problem Description: Every positive integer can be expressed by multiplication of prime integers. Duoxida says an integer is a yada number if the total amount of 2,3,5,7,11,13 in its prime factors is even. For instance, 18=2 * 3 * 3 is no…
题目链接:BZOJ - 3129 题目分析 使用隔板法的思想,如果没有任何限制条件,那么方案数就是 C(m - 1, n - 1). 如果有一个限制条件是 xi >= Ai ,那么我们就可以将 m 减去 Ai - 1 ,相当于将这一部分固定分给 xi,就转化为无限制的情况了. 如果有一些限制条件是 xi <= Ai 呢?直接来求就不行了,但是注意到这样的限制不超过 8 个,我们可以使用容斥原理来求. 考虑容斥:考虑哪些限制条件被违反了,也就是说,有哪些限制为 xi <= Ai 却是 xi…
Eddy's爱好 Time Limit: 3000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 1266 Accepted Submission(s): 541 Problem Description Ignatius 喜欢收集蝴蝶标本和邮票,但是Eddy的爱好很特别,他对数字比较感兴趣,他曾经一度沉迷于素数,而现在他对于一些新的特殊数比较有兴趣.这些特殊数是这…