PAT甲级——A1074 Reversing Linked List】的更多相关文章

Given a constant K and a singly linked list L, you are supposed to reverse the links of every K elements on L. For example, given L being 1→2→3→4→5→6, if K=3, then you must output 3→2→1→6→5→4; if K=4, you must output 4→3→2→1→5→6. Input Specification:…
1074 Reversing Linked List (25 分)   Given a constant K and a singly linked list L, you are supposed to reverse the links of every K elements on L. For example, given L being 1→2→3→4→5→6, if K=3, then you must output 3→2→1→6→5→4; if K=4, you must outp…
[程序思路] 先根据地址按顺序读入节点,入栈,当栈里的元素个数等于k时全部出栈,并按出栈顺序保存,最后若栈不为空,则全部出栈并按出栈的稀饭顺序保存,最后输出各节点 注意:输入的节点中有可能存在无用节点需要过滤,这里我使用map映射来实现过滤 [代码实现] #include<bits/stdc++.h> using namespace std; struct node{ int addrest,data,next; }t; int stk[100005]; int main(){ map<…
Given a constant K and a singly linked list L, you are supposed to reverse the links of every K elements on L. For example, given L being 1→2→3→4→5→6, if K=3, then you must output 3→2→1→6→5→4; if K=4, you must output 4→3→2→1→5→6. Input Specification:…
Given a constant K and a singly linked list L, you are supposed to reverse the links of every K elements on L. For example, given L being 1→2→3→4→5→6, if K = 3, then you must output 3→2→1→6→5→4; if K = 4, you must output 4→3→2→1→5→6. Input Specificat…
题目 Given a constant K and a singly linked list L, you are supposed to reverse the links of every K elements on L. For example, given L being 1→2→3→4→5→6, if K = 3, then you must output 3→2→1→6→5→4; if K = 4, you must output 4→3→2→1→5→6. Input Specifi…
题意: 输入一个正整数N(<=100000),和一个链表的头结点地址.接着输入N行,每行包括一个结点的地址,结点存放的值(-1e5~1e5),指向下一个结点的地址.地址由五位包含前导零的正整数组成.以头结点地址开始的这条链表以值排序后得到的链表的长度和头结点,接着以升序按行输出每个结点的地址和值以及指向下一个结点的地址. trick: 题干说的postive N可是数据点4出现了N==0的数据,有些不解如果N==0应该包含的话不应该用nonnegative N吗... 数据点1包含有些结点并非在…
Source: PAT A1074 Reversing Linked List (25 分) Description: Given a constant K and a singly linked list L, you are supposed to reverse the links of every Kelements on L. For example, given L being 1→2→3→4→5→6, if K=3, then you must output 3→2→1→6→5→4…
1074 Reversing Linked List (25)(25 分) Given a constant K and a singly linked list L, you are supposed to reverse the links of every K elements on L. For example, given L being 1→2→3→4→5→6, if K = 3, then you must output 3→2→1→6→5→4; if K = 4, you mus…
1001. A+B Format (20) 注意负数,没别的了. 用scanf来补 前导0 和 前导的空格 很方便. #include <iostream> #include <cstdio> using namespace std; ]; int main() { int A,B; cin>>A>>B; A+=B; ) { A=-A; cout<<"-"; } ; while(A) { a[n++]=A%; A/=; } ;…