POJ 3207 Ikki's Story IV - Panda's Trick id=3207" target="_blank" style="">题目链接 题意:一个圆上顺序n个点,然后有m组连线,连接两点,要求这两点能够往圆内或圆外.问能否构造出使得满足全部线段不相交 思路:2-sat,推断相交的建边,一个在内.一个在外,然后跑一下2-sat就可以 代码: #include <cstdio> #include <cstring…

题目链接: id=3207">http://poj.org/problem? id=3207 Ikki's Story IV - Panda's Trick Time Limit: 1000MS   Memory Limit: 131072K Total Submissions: 8063   Accepted: 2969 Description liympanda, one of Ikki's friend, likes playing games with Ikki. Today af…

职务地址:id=3207">POJ 3207 找好矛盾关系.矛盾关系是(2,5)和(3,6)这两个仅仅能一个在外边,一个在里边.利用这个矛盾关系来建图. 能够用在外边和里边来当1和0,最后推断每对是否出现矛盾. 代码例如以下: #include <iostream> #include <cstdio> #include <string> #include <cstring> #include <stdlib.h> #include…

Language: Default Ikki's Story IV - Panda's Trick Time Limit: 1000MS   Memory Limit: 131072K Total Submissions: 8796   Accepted: 3241 Description liympanda, one of Ikki's friend, likes playing games with Ikki. Today after minesweeping with Ikki and w…

POJ 3207 Ikki's Story IV - Panda's Trick(2-sat问题) Description liympanda, one of Ikki's friend, likes playing games with Ikki. Today after minesweeping with Ikki and winning so many times, he is tired of such easy games and wants to play another game…

http://poj.org/problem?id=3207 Ikki's Story IV - Panda's Trick Time Limit: 1000MS   Memory Limit: 131072K Total Submissions: 7021   Accepted: 2604 Description liympanda, one of Ikki’s friend, likes playing games with Ikki. Today after minesweeping wi…

Ikki's Story IV - Panda's Trick Time Limit: 1000MS   Memory Limit: 131072K Total Submissions: 7296   Accepted: 2705 Description liympanda, one of Ikki’s friend, likes playing games with Ikki. Today after minesweeping with Ikki and winning so many tim…

Ikki's Story IV - Panda's Trick Time Limit: 1000MS   Memory Limit: 131072K Total Submissions: 6691   Accepted: 2496 Description liympanda, one of Ikki’s friend, likes playing games with Ikki. Today after minesweeping with Ikki and winning so many tim…

题意: 有一个环,环上n个点,现在在m个点对之间连一条线,线可以往圆外面绕,也可以往里面绕,问是否必定会相交? 思路: 根据所给的m条边可知,假设给的是a-b,那么a-b要么得绕环外,要么只能在环内,除非a和b是连续的点才不会影响到任何弧,否则一定会多少影响其他弧的走势.比如样例所举出的 0-2和 1-3,就必须有一条弧选择外环,一个选择内环. 如何使他们有序不冲突呢?其实这题跟环上的点没多大关系,而且给的点数n也没什么用,而倒是边才重要.我们要做的是让边不冲突.那么肯定是要先选出可能冲突的边来…

注意到相交的点对一定要一里一外,这样就变成了2-SAT模型 然后我建边的时候石乐志,实际上不需要考虑这个点对的边是正着连还是反着连,因为不管怎么连,能相交的总会相交,所以直接判相交即可 然后tarjan缩点,再判是否合法即可 #include<iostream> #include<cstdio> using namespace std; const int N=100005; int n,m,h[N],cnt,l[N],r[N],dfn[N],low[N],tot,s[N],top…