主题链接: http://acm.zju.edu.cn/onlinejudge/showProblem.do? problemId=4535 How Many Sets I Time Limit: 2 Seconds      Memory Limit: 65536 KB Give a set S, |S| = n, then how many ordered set group (S1, S2, ..., Sk) satisfies S1 ∩ S2 ∩ ... ∩ Sk = ∅. (Si is…

How Many Sets I Time Limit: 2 Seconds      Memory Limit: 65536 KB Give a set S, |S| = n, then how many ordered set group (S1, S2, ..., Sk) satisfies S1 ∩ S2 ∩ ... ∩ Sk = ∅. (Si is a subset of S, (1 <= i <= k)) Input The input contains multiple cases…

How Many Sets I Time Limit: 2 Seconds      Memory Limit: 65536 KB Give a set S, |S| = n, then how many ordered set group (S1, S2, ..., Sk) satisfies S1 ∩ S2 ∩ ... ∩ Sk = ∅. (Si is a subset of S, (1 <= i <= k)) Input The input contains multiple cases…

How Many Sets II Time Limit: 2 Seconds      Memory Limit: 65536 KB Given a set S = {1, 2, ..., n}, number m and p, your job is to count how many set T satisfies the following condition: T is a subset of S |T| = m T does not contain continuous numbers…

How Many Sets II Time Limit: 2 Seconds      Memory Limit: 65536 KB Given a set S = {1, 2, ..., n}, number m and p, your job is to count how many set T satisfies the following condition: T is a subset of S |T| = m T does not contain continuous numbers…

终于做出来了,激动.... 这道题隐藏得深啊,但若推导下来,就变简单了. 首先,一个集合的子集的个数为2^n=s.注意了,题目求的是有序集合组,并且每个集合是可以重复使用的,怎么办呢?这就要想到多重集合的排列问题了. 一个多重集合有k种元素,每种元素可以无限次使用,求r-排列个数.答案为 k^r个. 这样,我们使用容斥原理: 总个数为(2^n)^k个 包含一个元素的集合有序组为 C(n,1)(2^(n-1))^k 两个的为.....C(n,2)(2^(n-2))^k .... 于是二项式定理+容…

题目链接:http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemCode=3556 How Many Sets I Time Limit: 2 Seconds      Memory Limit: 65536 KB Give a set S, |S| = n, then how many ordered set group (S1, S2, ..., Sk) satisfies S1 ∩ S2 ∩ ... ∩ Sk = ∅. (Si is…

最近做了不少的组合数的题这里简单总结一下下 1.n,m很大p很小 且p为素数p要1e7以下的 可以接受On的时间和空间然后预处理阶乘 Lucas定理来做以下是代码 /*Hdu3037 Saving Beans*/ #include<cstdio> #include<cstring> #include<iostream> #define ll long long #define maxn 1000010 using namespace std; ll T,n,m,p,f[…

http://acm.zju.edu.cn/onlinejudge/showProblem.do? problemId=4535 一个集合s有n个元素,求满足这种集合序列{s1,s2....sk}使S1 ∩ S2 ∩ ... ∩ Sk = ∅.si是s的子集. 从每一个元素考虑会使问题变得简单. 首先n个元素是相互独立的,单独考虑第i个元素,它在k个子集的全部情况是2^k,当中有一种情况是k个子集都有第i个元素,这一种情况正好不是我们想要的,所以合法的应该是2^k-1.那么n个元素就是( 2^k…

QS Network Time Limit:2000MS     Memory Limit:65536KB     64bit IO Format:%lld & %llu Submit Status Practice ZOJ 1586 Appoint description:  System Crawler  (2015-05-31) Description Sunny Cup 2003 - Preliminary Round April 20th, 12:00 - 17:00 Problem…