传送门: http://acm.hdu.edu.cn/showproblem.php?pid=1014 Uniform Generator Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 33120    Accepted Submission(s): 13137 Problem Description Computer simulati…

Uniform Generator Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 35190 Accepted Submission(s): 14002 Problem Description Computer simulations often require random numbers. One way to generate pseu…

Uniform Generator Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 29336    Accepted Submission(s): 11694 Problem Description Computer simulations often require random numbers. One way to generat…

Uniform Generator Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 24381    Accepted Submission(s): 9642 Problem Description Computer simulations often require random numbers. One way to generat…

Uniform Generator Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 32990    Accepted Submission(s): 13081 Problem Description Computer simulations often require random numbers. One way to generat…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1014 题目意思:给出 STEP 和 MOD,然后根据这个公式:seed(x+1) = [seed(x) + STEP] % MOD,问是否在一个周期里可以产生 0 - mod-1 的数.可以的话输出 "Good Choice", 否则输出 "Bad Choice". 好久以前留下来的问题了,以前觉得题目意思又长,以为是很难的题目......今天看<短码之美>…

Problem Description Computer simulations often require random numbers. One way to generate pseudo-random numbers is via a function of the form seed(x+1) = [seed(x) + STEP] % MOD where '%' is the modulus operator. Such a function will generate pseudo-…

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 28661    Accepted Submission(s): 11402 Problem Description Computer simulations often require random numbers. One way to generate pseudo-random nu…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1014 解题思路: 1. 把题目意思读懂后,明白会输入两个数,然后根据题中的公式产生一系列伪随机数,看这些数是不是能够包含0~MOD-1.如果产生不了就输出“Good Choice”,否则输出“Bad Choice”. 2. 全部假使x从0开始,设STEP为a,MOD为b.如果说a,b存在倍数关系,即假设最小存在2倍关系,那么就会有b=2a.x初始为0,第一步之后为a,第二步之后为0,之后a.0交替出…

http://acm.hdu.edu.cn/showproblem.php?pid=1014 题目的英文实在是太多了 ,搞不懂. 最后才知道是用公式seed(x+1) = [seed(x) + STEP] % MOD 来计算随机数 ,问是否满足随机数. 初级版本: 思路:把所有的用该公式计算出来的数(存在数组中)都遍历出来,然后排序.由于数字是在0 到mod-1 之间,所以数组的下标必然等于数组的值,有一个不等于,就是bad chioce #include <stdio.h> #include…