题目:我们会传递给你一个包含两个数字的数组.返回这两个数字和它们之间所有数字的和. 最小的数字并非总在最前面. /*方法一: 公式法 (首+末)*项数/2 */ /*两个数比较大小的函数*/ function compare(value1,value2){ if(value1 < value2){ return -1; }else if(value1 > value2){ return 1; }else{ return 0; } } function sumAll(arr) { arr.sor…

我们会传递给你一个包含两个数字的数组.返回这两个数字和它们之间所有数字的和. 最小的数字并非总在最前面. 这是一些对你有帮助的资源: Math.max() Math.min() Array.reduce() 感觉这些有用的资源对我来说没什么用..不就是等差数列求和么,于是 function sumAll(arr) { var nArr=arr.sort(function(x,d){ return x-d; }); return (nArr[0]+nArr[1])*(nArr[1]-nArr[0]…

Sum All Numbers in a Range 要求 给你一个包含两个数字的数组.返回这两个数字和它们之间所有数字的和. 最小的数字并非总在最前面. 思路 定义结果变量num 在for循环中,i从arr中最小的数字开始,到最大的数结束 利用累加实现返回这两个数字和它们之间所有数字的和 代码 function sumAll(arr) { var num=0; for(var i=Math.min(arr[0],arr[1]);i<=Math.max(arr[0],arr[1]);i++){…

#include <stdio.h> int main() { int a,b,sum; printf("输入一个数字: "); scanf("%d",&a); //输入数字a sum = ; ;b<=a;b++){ //设置b=1 使用for loop,用b相加,一直加到输入的数字a的数值 sum = sum + b; } printf("%d",sum); }…

我们之前生成的随机数是在0到某个数之间,现在我们要生成的随机数是在两个指定的数之间. 我们需要定义一个最小值和一个最大值. 下面是我们将要使用的方法,仔细看看并尝试理解这行代码到底在干嘛: Math.floor(Math.random() * (max - min + 1)) + min 任务 创建一个叫randomRange的函数,参数为myMin和myMax,返回一个在myMin(包括myMin)和myMax(包括myMax)之间的随机数.…

freecodecamp 中级算法地址戳这里 Sum All Numbers in a Range 我们会传递给你一个包含两个数字的数组.返回这两个数字和它们之间所有数字的和. function sumAll(arr) { arr.sort(function(a,b){ return a-b; }); var a=arr[0]; var sum=arr[0]; while( a<arr[1] ){ a++; sum+=a; } return sum; } sumAll([1, 4]); Diff…

在学习FCC中级算法这一块,自己遇到了很多问题,通过RSA也慢慢把问题解决了,发现每一个问题都会有很多的解决思路,因此把自己想到的一些思路记录到这里. 1. Sum All Numbers in a Range 我们会传递给你一个包含两个数字的数组.返回这两个数字和它们之间所有数字的和. 思路1:定位最大和最小的值,进行累和相加,用到函数:Math.max(),Math.min(),Function.apply() function sumAll(arr) { var sum=0; var ma…

题目链接:https://learn.freecodecamp.org/javascript-algorithms-and-data-structures/intermediate-algorithm-scripting 1. Sum All Numbers in a Range 传入的参数是包含两个数字的数组,要求计算两数之间(包含边界)所有数字的和,较小的数字不一定在数组第一位: function sumAll(arr) { var start = arr[0] ,end = arr[1];…

介绍 FCC: 全称为freeCodeCamp,是一个非盈利性的.面向全世界的编程练习网站.这次的算法题来源于FCC的中级算法题. FCC中级算法篇共分为(上).(中).(下)三篇.每篇各介绍7道算法题.每道算法题都会介绍相应的思路和详细的解答过程. 目录 1. Sum All Numbers in a Range 2. Diff Two Arrays 3. Roman Numberal Converter 4. Where art thou 5. Search and Replace 6. P…

Given an integer array nums, return the number of range sums that lie in [lower, upper] inclusive.Range sum S(i, j) is defined as the sum of the elements in nums between indices i and j (i ≤ j), inclusive. Note:A naive algorithm of O(n2) is trivial.…

一:Number of 1 Bits 题目: Write a function that takes an unsigned integer and returns the number of '1' bits it has (also known as the Hamming weight). For example, the 32-bit integer '11' has binary representation 00000000000000000000000000001011, so t…

Given an integer array nums, return the number of range sums that lie in [lower, upper] inclusive.Range sum S(i, j) is defined as the sum of the elements in nums between indices i and j (i ≤ j), inclusive. Note:A naive algorithm of O(n2) is trivial.…

在Java位运算总结-leetcode题目博文中总结了Java提供的按位运算操作符,今天又碰到LeetCode中一道按位操作的题目 Given a range [m, n] where 0 <= m <= n <= 2147483647, return the bitwise AND of all numbers in this range, inclusive. For example, given the range [5, 7], you should return 4. 题意:…

Given a range [m, n] where 0 <= m <= n <= 2147483647, return the bitwise AND of all numbers in this range, inclusive. For example, given the range [5, 7], you should return 4. Credits:Special thanks to @amrsaqr for adding this problem and creatin…

Given a binary tree containing digits from 0-9 only, each root-to-leaf path could represent a number. An example is the root-to-leaf path 1->2->3 which represents the number 123. Find the total sum of all root-to-leaf numbers. For example, 1 / \ 2 3…

Given a range [m, n] where 0 <= m <= n <= 2147483647, return the bitwise AND of all numbers in this range, inclusive. For example, given the range [5, 7], you should return 4. 思路: 先找前面二进制相同的位,后面不相同的位相与一定为0. 比如: 1111001 1110011 从0011 - 1001 中间一定会经…

Bitwise AND of Numbers Range Given a range [m, n] where 0 <= m <= n <= 2147483647, return the bitwise AND of all numbers in this range, inclusive. For example, given the range [5, 7], you should return 4. Credits: Special thanks to @amrsaqr for a…

Given a range [m, n] where 0 <= m <= n <= 2147483647, return the bitwise AND of all numbers in this range, inclusive. For example, given the range [5, 7], you should return 4. 分析:http://www.cnblogs.com/grandyang/p/4431646.html 我们先从题目中给的例子来分析,[5,…

Given a range [m, n] where 0 <= m <= n <= 2147483647, return the bitwise AND of all numbers in this range, inclusive. For example, given the range [5, 7], you should return 4. 解题思路: 本题有很多思路,最简单的方法: result就是m和n二进制前面相同的部分!!! JAVA实现如下: public int ra…

Given a range [m, n] where 0 <= m <= n <= 2147483647, return the bitwise AND of all numbers in this range, inclusive. For example, given the range [5, 7], you should return 4. int rangeBitwiseAnd(int m, int n) { int mask = 0xffffffff; /* find out…

Given a range [m, n] where 0 <= m <= n <= 2147483647, return the bitwise AND of all numbers in this range, inclusive. For example, given the range [5, 7], you should return 4. 题意: 给定 [m, n] 范围内个数,返回范围内所有数相与的结果. 思路: 如果打着暴力的旗号,那么这个题是会超时的 - -!.最后也是没…

题目: Given a range [m, n] where 0 <= m <= n <= 2147483647, return the bitwise AND of all numbers in this range, inclusive. For example, given the range [5, 7], you should return 4. 链接: http://leetcode.com/problemset/algorithms/ 题解: 一开始采用暴力解,自然超时了.…

Problem: Given a range [m, n] where 0 <= m <= n <= 2147483647, return the bitwise AND of all numbers in this range, inclusive. For example, given the range [5, 7], you should return 4. Analysis: The idea behind this problem is not hard, you could…

题目: Given a range [m, n] where 0 <= m <= n <= 2147483647, return the bitwise AND of all numbers in this range, inclusive. For example, given the range [5, 7], you should return 4. 解答: 假如说5:101  7:111  连续几个数相与的规律:一,仅仅要是同样的位置的数字不同样最后那个位置的结果一定是0 .二,…

Given a range [m, n] where 0 <= m <= n <= 2147483647, return the bitwise AND of all numbers in this range, inclusive. For example, given the range [5, 7], you should return 4. 题目大意:给一个范围,返回这个范围中所有的数按位相与最后的结果. 解题思路:当拿到这个题目的时候,我是拒绝的,这么简单的题,直接与然后返回不…

Given a range [m, n] where 0 <= m <= n <= 2147483647, return the bitwise AND of all numbers in this range, inclusive. Example 1: Input: [5,7] Output: 4 Example 2: Input: [0,1] Output: 0 给定范围 [m, n],其中 0 <= m <= n <= 2147483647,返回此范围内所有数字…

https://leetcode.com/problems/bitwise-and-of-numbers-range/discuss/56729/Bit-operation-solution(JAVA) 面试官,你再问我 Bit Operation 试试? 描述 Given a range [m, n] where 0 <= m <= n <= 2147483647, return the bitwise AND of all numbers in this range, inclusi…

Given a range [m, n] where 0 <= m <= n <= 2147483647, return the bitwise AND(按位与) of all numbers in this range, inclusive. For example, given the range [5, 7], you should return 4. 思路:序列是按1递增的,所以必定先影响低位,按位与为1的情况必定发生在高位.两个数向右移,当两数相等,剩余的1便是按位与得到的1.…

Bitwise AND of Numbers Range  Given a range [m, n] where 0 <= m <= n <= 2147483647, return the bitwise AND of all numbers in this range, inclusive. For example, given the range [5, 7], you should return 4. Credits:Special thanks to @amrsaqr for a…

1. Number of Islands Given a 2d grid map of '1's (land) and '0's (water), count the number of islands. An island is surrounded by water and is formed by connecting adjacent lands horizontally or vertically. You may assume all four edges of the grid a…