题目:swap nodes in pairs <span style="font-size:18px;">/** * LeetCode Swap Nodes in Pairs * 题目:输入一个链表,要求将链表每相邻的两个节点交换位置后输出 * 思路:遍历一遍就可以,时间复杂度O(n) * Definition for singly-linked list. * public class ListNode { * int val; * ListNode next; * Li…

Swap Nodes in Pairs [LeetCode] https://leetcode.com/problems/swap-nodes-in-pairs/ Total Accepted: 95332 Total Submissions: 270806 Difficulty: Easy Question Given a linked list, swap every two adjacent nodes and return its head. For example, Given 1->…

Swap Nodes in Pairs  Given a linked list, swap every two adjacent nodes and return its head. For example, Given 1->2->3->4, you should return the list as 2->1->4->3. Your algorithm should use only constant space. You may not modify the v…

Swap Nodes in Pairs 描述 给定一个链表,两两交换其中相邻的节点,并返回交换后的链表. 示例: 给定 1->2->3->4, 你应该返回 2->1->4->3. 说明: 你的算法只能使用常数的额外空间. 你不能只是单纯的改变节点内部的值,而是需要实际的进行节点交换. 思路 该题属于基本的链表操作题. 设置一个虚拟头结点dummyHead 设置需要交换的两个节点分别为node1.node2,同时设置node2的下一个节点next 在这一轮操作中 将nod…

题目描述:Swap Nodes in Pairs Given a linked list, swap every two adjacent nodes and return its head. For example,Given 1->2->3->4, you should return the list as 2->1->4->3. Your algorithm should use only constant space. You may not modify th…

Given a linked list, swap every two adjacent nodes and return its head. For example,Given 1->2->3->4, you should return the list as 2->1->4->3. Your algorithm should use only constant space. You may not modify the values in the list, onl…

Given a linked list, swap every two adjacent nodes and return its head. You may not modify the values in the list's nodes, only nodes itself may be changed. Example: Given 1->2->3->4, you should return the list as 2->1->4->3. 这道题不算难,是基本的…

Given a linked list, swap every two adjacent nodes and return its head. For example,Given 1->2->3->4, you should return the list as 2->1->4->3. Your algorithm should use only constant space. You may not modify the values in the list, onl…

Given a linked list, swap every two adjacent nodes and return its head. For example, Given 1->2->3->4, you should return the list as 2->1->4->3. Your algorithm should use only constant space. You may not modify the values in the list, on…

Given a linked list, swap every two adjacent(相邻的) nodes and return its head. For example,Given 1->2->3->4, you should return the list as 2->1->4->3. Your algorithm should use only constant space. You may not modify the values in the list…

题目描述: Given a linked list, swap every two adjacent nodes and return its head. For example, Given 1->2->3->4, you should return the list as 2->1->4->3. Your algorithm should use only constant space. You may not modify the values in the li…

Given a linked list, swap every two adjacent nodes and return its head. For example, Given 1->2->3->4, you should return the list as 2->1->4->3. Your algorithm should use only constant space. You may not modify the values in the list, on…

Given a linked list, swap every two adjacent nodes and return its head. For example, Given 1->2->3->4, you should return the list as 2->1->4->3. Your algorithm should use only constant space. You may not modify the values in the list, on…

Given a linked list, swap every two adjacent nodes and return its head. For example, Given 1->2->3->4, you should return the list as 2->1->4->3. Your algorithm should use only constant space. You may not modify the values in the list, on…

Given a linked list, swap every two adjacent nodes and return its head. You may not modify the values in the list's nodes, only nodes itself may be changed. Example: Given ->->->, you should ->->->. 奇数位和偶数位互换,若是奇数个,不用管最后一个 解法一:(C++) List…

Given a linked list, swap every two adjacent nodes and return its head. You may not modify the values in the list's nodes, only nodes itself may be changed. Example: Given 1->2->3->4, you should return the list as 2->1->4->3. -----------…

Given a linked list, swap every two adjacent nodes and return its head. You may not modify the values in the list's nodes, only nodes itself may be changed. Example: Given 1->2->3->4, you should return the list as 2->1->4->3. 题意: 给定一个链表,…

题目链接: https://leetcode.com/problems/swap-nodes-in-pairs/?tab=Description   Problem: 交换相邻的两个节点     如上图所示,递归进行交换.从最尾端开始,当最尾端只有一个节点时,停止交换 否则执行 swap(head.next)    参考代码:   package leetcode_50; /** * * @author pengfei_zheng * 交换相邻节点 */ public class Solutio…

Given a linked list, swap every two adjacent nodes and return its head. For example, Given 1->2->3->4, you should return the list as 2->1->4->3. Your algorithm should use only constant space. You may not modify the values in the list, on…

Given a linked list, swap every two adjacent nodes and return its head. Example: Given 1->2->3->4, you should return the list as 2->1->4->3. Note: Your algorithm should use only constant extra space. You may not modify the values in the…

Given a linked list, swap every two adjacent nodes and return its head.For example,Given 1->2->3->4, you should return the list as 2->1->4->3.Your algorithm should use only constant space. You may not modify the values in the list, only…

题目: Given a linked list, swap every two adjacent nodes and return its head. For example,Given 1->2->3->4, you should return the list as 2->1->4->3. Your algorithm should use only constant space. You may not modify the values in the list,…

题目标签:Linked List 题目给了我们一组 linked list,让我们把每对nodes 互换位置. 新键一个dummy node,然后遍历list,每次建立 s1 和 s2 记录两个点,然后互换位置,具体看code. Java Solution: Runtime:  0 ms, faster than 100 % Memory Usage: 34 MB, less than 100 % 完成日期:05/22/2019 关键点:换位置时候先后顺序 /** * Definition fo…

题目内容 Given a linked list, swap every two adjacent nodes and return its head. You may not modify the values in the list’s nodes, only nodes itself may be changed.大概意思是说每两个节点为一组交换位置.只使用常量空间,不能修改链表的值,只能修改链表的指针 解法(迭代) class Solution { public: ListNode* s…

这是LeetCode里的第24题. 题目要求: 给定一个链表,两两交换其中相邻的节点,并返回交换后的链表. 示例: 给定1->2->3->4, 你应该返回2->1->4->3. 说明: 你的算法只能使用常数的额外空间. 你不能只是单纯的改变节点内部的值,而是需要实际的进行节点交换. 这道题还是很简单的,题目说明也很清晰.画画图就能完成题目了. 设计思路: 首先是判断链表是否为空(被空链表弄出了潜意识),然后两节点,一个front前节点,一个back后节点.再一个节点记录…

不允许通过值来交换,在更新指针时需要小心. ListNode *swapNodes(ListNode* head) { ListNode dummy(-); dummy.next = head; for (ListNode *prev = &dummy, *cur = prev->next, *pnext = cur->next; pnext; prev = cur, cur = cur->next, pnext = cur->next) { prev->next =…

我的代码是这样的: class Solution { public: ListNode *swapPairs(ListNode *head) { ; ; ListNode *listA; ListNode *listB; ListNode *listFront; ListNode *listTail; bool bFirstTime = TRUE; listFront = head; while(listFront != NULL) { listA = listFront; if(bFirstT…

题意:交换链表中每两个相邻节点,不能修改节点的val值. 分析:递归.如果以第三个结点为头结点的链表已经两两交换完毕(这一步递归实现---swapPairs(head -> next -> next)),则接下来,只需交换前两个节点,再将第一个节点的next指向“以第三个结点为头结点的链表两两交换后”的链表. /** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * L…

感觉这个题后台的运行程序有问题,一开始自己想的是反转链表那道题的方法,只是隔一个节点执行一次,但是没有通过,TLE了,但是很奇怪,并没有死循环,就是最后返回的时候超时. 最后的思路就是很简单的进行交换,设置一个头结点前边的0节点先把第三个节点接到第一个上边,然后把第一个接到第二个上,然后把第二个节点接到0节点上,然后把当前节点设置成第一个节点(现在是第二个,而且是下次交换的0节点) public ListNode swapPairs(ListNode head) { if (head==null…

Swap Nodes in Pairs: Given a linked list, swap every two adjacent nodes and return its head. For example, Given 1->2->3->4, you should return the list as 2->1->4->3. Your algorithm should use only constant space. You may not modify the v…