Uva----------(11078)Open Credit System】的更多相关文章

Open Credit System In an open credit system, the students can choose any course they like, but there is a problem. Some of the students are more senior than other students. The professor of such a course has found quite a number of such students who…
题意:给出n个数,找出两个整数a[i],a[j](i < j),使得a[i] - a[j]尽量大 从小到大枚举j,在这个过程中维护a[i]的最大值 maxai晚于ans更新, 可以看这个例子 1 8 9 10 11 正确的应该是-1 如果更早更新的话,算出来就是0 用数组来存的 #include<iostream> #include<cstdio> #include<cstring> #include <cmath> #include<stack…
11078 - Open Credit System Time limit: 3.000 seconds Problem E Open Credit System Input: Standard Input Output: Standard Output In an open credit system, the students can choose any course they like, but there is a problem. Some of the students are m…
http://acm.hust.edu.cn/vjudge/contest/view.action?cid=102419#problem/A In an open credit system, the students can choose any course they like, but there is a problem. Some of the students are more senior than other students. The professor of such a c…
Open Credit SystemInput: Standard Input Output: Standard Output In an open credit system, the students can choose any course they like, but there is a problem. Some of the students are more senior than other students. The professor of such a course h…
Open Credit System Input:Standard Input Output: Standard Output In an open credit system, the students can choose any course they like, but there is a problem. Some of the students are more senior than other students. The professor of such a course h…
题目大意:给长度N的A1.....An 求(Ai-Aj)MAX 枚举n^2 其实动态维护最大值就好了 #include<iostream> #include<cstdio> using namespace std; ],n,ans,MAX; int main() { scanf("%d",&t); while (t--) { scanf("%d",&n); ;i<=n;i++) scanf("%d",…
题目链接:http://uva.onlinejudge.org/external/110/11078.pdf a[i] - a[j] 的最大值. 这个题目马毅问了我,O(n^2)超时,记忆化一下当前最大值. #include <bits/stdc++.h> using namespace std; ],n; int main() { int t; cin>>t; while(t--) { cin>>n; ;i<n;i++) { cin>>A[i]; }…
题文: You are given the task to design a lighting system for a huge conference hall. After doing a lot of calculation and sketching, you have figured out the requirements for an energy-efficient design that can properly illuminate the entire hall. Acco…
这道题使用暴力解法O(n*n)会超时,那么用动态维护最大值可以优化到O(n).这种思想非常实用. #include<iostream> #include<cstdio> #include<cstdlib> #include<cstring> #include<string> #include<cmath> #include<map> #include<set> #include<vector> #i…