Remove Nth Node From End of List Total Accepted: 46720 Total Submissions: 168596My Submissions Question Solution  Given a linked list, remove the nth node from the end of list and return its head. For example, Given linked list: 1->2->3->4->5,…

Given a linked list, remove the nth node from the end of list and return its head. For example, Given linked list: 1->2->3->4->5, and n = 2. After removing the second node from the end, the linked list becomes 1->2->3->5. Note: Given…

原题地址:http://oj.leetcode.com/problems/remove-nth-node-from-end-of-list/ 题意: Given a linked list, remove the nth node from the end of list and return its head. For example, Given linked list: 1->2->3->4->5, and n = 2. After removing the second n…

Given a linked list, remove the nth node from the end of list and return its head. For example, Given linked list: 1->2->3->4->5, and n = 2. After removing the second node from the end, the linked list becomes 1->2->3->5. Note: Given …

Given a linked list, remove the nth node from the end of list and return its head. For example, Given linked list: 1->2->3->4->5, and n = 2. After removing the second node from the end, the linked list becomes 1->2->3->5. Note:Given n…

Given a linked list, remove the nth node from the end of list and return its head. For example, Given linked list: 1->2->3->4->5, and n = 2. After removing the second node from the end, the linked list becomes 1->2->3->5. Note:Given n…

Given a linked list, remove the n th node from the end of list and return its head. For example, Given linked list: 1->2->3->4->5, and n = 2. After removing the second node from the end, the linked list becomes 1->2->3->5. Note:  Give…

# Definition for singly-linked list. # class ListNode(object): # def __init__(self, x): # self.val = x # self.next = None class Solution(object): def removeNthFromEnd(self, head, n): """ :type head: ListNode :type n: int :rtype: ListNode &q…

/** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ class Solution { public: ListNode *removeNthFromEnd(ListNode *head, int n) { ,*w=,*e=; ; ) return head; //无需修改…

题目要求 Write a function to delete a node (except the tail) in a singly linked list, given only access to that node. 题目分析及思路 要求写一个函数,删除一个单链表中的一个结点(除了最后一个).函数不需要返回值,只需要原地修改给定删除结点.我们可以将要删除结点的两个属性用该结点的下一个结点的两个属性来替代. python代码 # Definition for singly-linked…