B. Planning The Expedition】的更多相关文章

Description Natasha is planning an expedition to Mars for nn people. One of the important tasks is to provide food for each participant. The warehouse has m daily food packages. Each package has some food type aiai. Each participant must eat exactly…
题目链接:http://codeforces.com/contest/1011/problem/B 题目大意: 输入的n,m代表n个人,m个包裹. 标准就是 每个人一开始只能选定吃哪一个包裹里的食物,刚开始可以和别人吃一样的,也可以和别人吃不一样的.给出的数据代表编号,问你在满足条件的前提下,最多可以让n个人活多少天. 具体思路: 我们可以计算出 i 天这些食物能活下来的最大人数,然后判断的时候,如果说哪一天活下来的最大人数大于n,输出对应的天数就可以了. 代码; #include<bits/s…
已经是水到一定程度了QAQ- Code: #include<cstdio> #include<algorithm> #include<cstring> using namespace std; const int maxn = 105; int tp[maxn], idx[maxn], n,m, spare[maxn], cnt; bool cmp(int i,int j) { return i > j;} inline bool check(int val) {…
题意:有n个人和m个食物,给出每一个食物的种类,每个人只会吃一种食物,每个人一天吃一个食物,问这n个人可以撑多少天. 分析:因为题目给出的天数范围比较小所以我们可以从1到100天开始枚举,我们判断如果是I天了,这些食物够不够N个人吃,够的话继续,不够的话可以跳出循环了,因为这是一种单调关系,如果天数比较大,那可以二分天数: 枚举 #include<stdio.h> ],a[]; ]; int main( ) { ,x; scanf("%d%d",&n,&m)…
Solution 考虑 二分 . 首先要确定二分的对象,显然二分天数较为简单. 每次找到的 \(mid\) 需要判断是否能让整队人吃饱,那就调用一个 check() . 对于 check() ,求出每包食物可供的人数,相加后与 \(n\) 相比较. 具体操作见下. Code #include<iostream> using namespace std; #define ll long long #define max(x,y) x>y?x:y ll n,m,l=1,r,a[1005],q…
Description Natasha is planning an expedition to Mars for nn people. One of the important tasks is to provide food for each participant. The warehouse has mm daily food packages. Each package has some food type ai. Each participant must eat exactly o…
Description Natasha is planning an expedition to Mars for nn people. One of the important tasks is to provide food for each participant. The warehouse has mm daily food packages. Each package has some food type aiai. Each participant must eat exactly…
Natasha is planning an expedition to Mars for nn people. One of the important tasks is to provide food for each participant. The warehouse has mm daily food packages. Each package has some food type aiai . Each participant must eat exactly one food p…
A: Stages 题意: 给你n个字符, 现在需要从中选取m个字符,每个字符的花费为在字母表的第几位,并且如果选了某个字符, 那么下一个选择的字符必须要在字母表的2位之后, 假如选了e 那么 不能选 a-f 可以选择 g-z, 现在求能满足条件的最小花费. 题解: 直接模拟. 代码: #include<bits/stdc++.h> using namespace std; #define Fopen freopen("_in.txt","r",stdi…
我: Tech Leader 团队:团队成员分布在两个城市,我所在的城市包括我有4个成员,另外一个城市包括SM有7个成员.另外由于我们的BA离职了,我暂代IT 的PO 职位.PM和我在一个城市,但他不参于敏捷的运作里面. 迭代: 双周 主要会议: Grooming, Sprint Planning, Daily Standup Meeting, Sprint Review Meeting, Retrospective Meeting. 现在有名外部敏捷教练在带着我们实施敏捷,不过从sprint3…
This is a sample agenda for a sprint planning meeting. Depending on your context you will have to change the details, just make sure the outcomes stay the same. Meeting purpose: Plan and prepare for the upcoming sprintMeeting duration: ca. 1 hour for…
原文链接:http://domaintree.me/?p=1037 By Robert Thibodeau –  Starting a business can be a very daunting adventure if a proper plan is not put in place. Most entrepreneurs start up their businesses without putting adequate plans in place to succeed. No wo…
Employment Planning Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 5292 Accepted Submission(s): 2262 Problem DescriptionA project manager wants to determine the number of the workers needed in eve…
recourse: "Software Engineering", Ian Sommerville Keywords for this chapter: planning scheduling cost estimation Project planning takes place at three stages in a project life cycle: At the proposal stage (When you are bidding for a contract to…
原创博文:转载请标明出处:http://www.cnblogs.com/zxouxuewei 最近有不少人询问有关MoveIt!与OMPL相关的话题,但是大部分问题都集中于XXX功能怎么实现,XXX错误怎么解决.表面上看,解决这些问题的方法就是提供正确的代码,正确的编译方法,正确的运行步骤. 然而,这种解决方法只能解决这个特定的问题,而且解决之后我们也无法学到一些实际的东西.要想彻底明白,需要从源头入手,也就是说,不要问"MoveIt! 怎么把机械手从空间一个点移到另一个点?",而是要…
1. General review. Professor Webster published this article in Urban Planning Forum, one of the top Chinese urban planning academic journals, before he went to take the office as Dean of the Faculty of Architecture in the University of Hong Kong. Obv…
大家都明白这样的一个道理:做事情要有计划,有一个不成熟的计划总比没有计划要好,软件开发这么复杂的活动,更加需要计划.那么应该怎样做好一个计划呢? 如果对项目的范围.规模.性质.任务.工作量.费用等都不了解的情况下,是不可能做出计划的,所以做好计划的第一步就是要把这些东西搞清楚. PP这个PA的第一个Specific Goals,中文大意是:建立和维护用于项目计划的各类参数的估算,英文原文是:Estimates of project planning parameters are establis…
题目链接: 传送门 Expedition Time Limit: 1000MS     Memory Limit: 65536K 题目描述 驾驶一辆卡车行驶L单位距离.最开始有P单位的汽油.卡车每开1单位距离消耗1单位的汽油.在途中一共有N个加油站.假设卡车的燃料箱容量无限大,问如果到达终点最少的加油次数. 思路 在卡车开往终点途中,只有在加油站才可以加油,换做认为"在到达加油站i时,就获得了一次在之后任何时候都可以加油的权利" #include<iostream> #in…
http://blogs.msdn.com/b/sanjaynarang/archive/2013/04/06/sizing-and-capacity-planning-for-sharepoint-2013-resources.aspx   SharePoint 2013 has been out for some time now, and most of new the SharePoint projects are happening on SharePoint 2013. Howeve…
Tourism Planning Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 1051    Accepted Submission(s): 460 Problem Description Several friends are planning to take tourism during the next holiday. Th…
POJ 2431 Expedition(探险) Time Limit: 1000MS   Memory Limit: 65536K [Description] [题目描述] A group of cows grabbed a truck and ventured on an expedition deep into the jungle. Being rather poor drivers, the cows unfortunately managed to run over a rock an…
最近用Swift写了个小工具Scrum Planning Card,如果你也用scrum管理项目, 或许用这个工具可以提高你的工作效率. 另外欢迎提建议和反馈,谢谢. 欢迎关注我的微信公众号 Hope this helps, Michael…
Expedition Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 12980   Accepted: 3705 Description A group of cows grabbed a truck and ventured on an expedition deep into the jungle. Being rather poor drivers, the cows unfortunately managed t…
Expedition Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 8053   Accepted: 2359 Description A group of cows grabbed a truck and ventured on an expedition deep into the jungle. Being rather poor drivers, the cows unfortunately managed to…
Problem Description As far as we known,there are so many people in this world,expecially in china.But many people like LJ always insist on that more people more power.And he often says he will burn as much babies as he could.Unfortunatly,the presiden…
Description Air Bovinia is planning to connect the N farms (1 <= N <= 200) that the cows live on. As with any airline, K of these farms (1 <= K <= 100, K <= N) have been selected as hubs. The farms are conveniently numbered 1..N, with farms…
Expedition 点我 Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 9465   Accepted: 2760 Description A group of cows grabbed a truck and ventured on an expedition deep into the jungle. Being rather poor drivers, the cows unfortunately managed…
City Planning Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 483    Accepted Submission(s): 203 Problem Description After many years, the buildings in HDU has become very old. It need to rebuil…
1.修改planning关系库 1.1--修改Plan_type,例如将type_name “Plan1”修改为”Plan1ts”,提交 SELECT * FROM hsp_plan_type FOR UPDATE; 1.2--修改object中object_name及old_name修改为”Plan1ts”,提交 SELECT * FROM  hsp_object t WHERE  t.object_name='Plan1' FOR UPDATE; 2.重启planning所有服务 3.刷新数…
Employment Planning Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 4782    Accepted Submission(s): 2019 Problem Description A project manager wants to determine the number of the workers needed…