lightoj 1125 - Divisible Group Sums (dp)】的更多相关文章

Given a list of N numbers you will be allowed to choose any M of them. So you can choose in NCM ways. You will have to determine how many of these chosen groups have a sum, which is divisible by D. Input Input starts with an integer T (≤ 20), denotin…
题目链接:http://www.lightoj.com/volume_showproblem.php?problem=1125 题意: 给你n个数,q次询问,每次询问问你取其中m个数是d的整数倍的方案数. 题意: dp[i][j][k] 表示前i个数, %d=j, 取了k个的方案数. ID SUBMISSION TIME PROBLEM SOURCE CPU MEMORY VERDICT 839200 2016-10-15 14:59:00 1125 - Divisible Group Sums…
Divisible Group Sums Given a list of N numbers you will be allowed to choose any M of them. So you can choose in NCM ways. You will have to determine how many of these chosen groups have a sum, which is divisible by D. Input Input starts with an inte…
Divisible Group Sums Given a list of N numbers you will be allowed to choose any M of them. So you can choose in NCM ways. You will have to determine how many of these chosen groups have a sum, which is divisible by D. Input Input starts with an inte…
题目问从N个数中取出M个数,有多少种取法使它们的和能被D整除. dp[i][j][k]表示,前i个数取出j个数模D的余数为k的方案数 我用“我为人人”的方式来转移,就从i到i+1转移,对于第i+1个数有取和不取两种选择,然后确定j和k这两个维度的情况. 另外题目说数字是32位有符号整数,所以是会出现负数的...模D之后加D再模D就行了. #include<cstdio> #include<cstring> using namespace std; ][][]; int main()…
称号:给你n数字.免去m一个,这使得他们可分割d.问:有多少种借贷. 分析:dp,D01背包. 背包整数分区. 首先.整点d.则全部数字均在整数区间[0,d)上: 然后,确定背包容量,最大为20*10 = 200,计算二维01背包: 最后,求出全部能整除d的整数取法的和就可以. 说明:注意使用long long防止溢出:注意数据中的负数. #include <algorithm> #include <iostream> #include <cstdlib> #inclu…
LightOJ 1033  Generating Palindromes(dp) 题目链接:http://acm.hust.edu.cn/vjudge/contest/view.action?cid=87730#problem/A 题目: Description By definition palindrome is a string which is not changed when reversed. "MADAM" is a nice example of palindrome.…
lightOJ 1047   Neighbor House (DP) 题目链接:http://acm.hust.edu.cn/vjudge/contest/view.action?cid=87730#problem/C 题目: Description The people of Mohammadpur have decided to paint each of their houses red, green, or blue. They've also decided that no two n…
Group Projects Description There are n students in a class working on group projects. The students will divide into groups (some students may be in groups alone), work on their independent pieces, and then discuss the results together. It takes the i…
题意:给你n天需要穿的衣服的样式,每次可以套着穿衣服,脱掉的衣服就不能再穿了,问至少要带多少条衣服才能参加所有宴会 思路:dp[i][j]代表i-j天最少要带的衣服 从后向前dp 区间从大到小 更新dp[i][j]时有两种情况 考虑第i天穿的衣服 1:第i天穿的衣服在之后不再穿了 那么 dp[i][j]=dp[i+1][j]+1; 2:第i天穿的衣服与i+1到j的某一天共用,那么dp[i][j]=min(dp[i][j],dp[i+1][k-1],dp[k][j]),前提是第i天和第k天需要的礼…