A1048 Find Coins (25 分)】的更多相关文章

一.技术总结 首先初看题目有点没读懂,题目大致意思是小明有很多个硬币不同面值的,但是现在他要到商家这里换新的面值, 且商家有一个规定,一个新的硬币必须要你两个硬币面值相加等于的来换,这一有第一个问题产生,就是会出现两两组合产生新硬币有多种 其中这里取最小的,然后输出小的面值在前.第二个问题是可能出现两个一样的硬币. 所以,我开始使用bool类型的数组,不行要采用int类型的看看是否可能出现同一个硬币面值两次.所以当时第一次提交时有一个测试点没通过. 改正后问题解决. 二.参考代码 #includ…
1048 Find Coins (25 分)   Eva loves to collect coins from all over the universe, including some other planets like Mars. One day she visited a universal shopping mall which could accept all kinds of coins as payments. However, there was a special requ…
Eva loves to collect coins from all over the universe, including some other planets like Mars. One day she visited a universal shopping mall which could accept all kinds of coins as payments. However, there was a special requirement of the payment: f…
Eva loves to collect coins from all over the universe, including some other planets like Mars. One day she visited a universal shopping mall which could accept all kinds of coins as payments. However, there was a special requirement of the payment: f…
题意: 输入两个正整数N和M(N<=10000,M<=1000),然后输入N个正整数(<=500),输出两个数字和恰好等于M的两个数(小的数字尽可能小且输出在前),如果没有输出"No Solution". AAAAAccepted code: #define HAVE_STRUCT_TIMESPEC #include<bits/stdc++.h> using namespace std; ]; int main(){ ios::sync_with_stdi…
1048 Find Coins (25 分) Eva loves to collect coins from all over the universe, including some other planets like Mars. One day she visited a universal shopping mall which could accept all kinds of coins as payments. However, there was a special requir…
1048. Find Coins (25) Eva loves to collect coins from all over the universe, including some other planets like Mars. One day she visited a universal shopping mall which could accept all kinds of coins as payments. However, there was a special require…
06-图1 列出连通集   (25分) 给定一个有NN个顶点和EE条边的无向图,请用DFS和BFS分别列出其所有的连通集.假设顶点从0到N-1N−1编号.进行搜索时,假设我们总是从编号最小的顶点出发,按编号递增的顺序访问邻接点. 输入格式: 输入第1行给出2个整数NN(0<N\le 100<N≤10)和EE,分别是图的顶点数和边数.随后EE行,每行给出一条边的两个端点.每行中的数字之间用1空格分隔. 输出格式: 按照"{ v_1v​1​​ v_2v​2​​ ... v_kv​k​​ …
01-复杂度2 Maximum Subsequence Sum   (25分) Given a sequence of K integers { N​1​​,N​2​​, ..., N​K​​ }. A continuous subsequence is defined to be { N​i​​,N​i+1​​, ..., N​j​​ } where 1≤i≤j≤K. The Maximum Subsequence is the continuous subsequence which has…
7-17 字符串关键字的散列映射(25 分) 给定一系列由大写英文字母组成的字符串关键字和素数P,用移位法定义的散列函数H(Key)将关键字Key中的最后3个字符映射为整数,每个字符占5位:再用除留余数法将整数映射到长度为P的散列表中.例如将字符串AZDEG插入长度为1009的散列表中,我们首先将26个大写英文字母顺序映射到整数0~25:再通过移位将其映射为3×32​2​​+4×32+6=3206:然后根据表长得到,即是该字符串的散列映射位置. 发生冲突时请用平方探测法解决. 输入格式: 输入第…