Mobile phones Time Limit: 5000MS Memory Limit: 65536K Total Submissions: 14489 Accepted: 6735 Description Suppose that the fourth generation mobile phone base stations in the Tampere area operate as follows. The area is divided into squares. The…
Mobile phones Time Limit: 5000MS Memory Limit: 65536K Total Submissions: 14391 Accepted: 6685 Description Suppose that the fourth generation mobile phone base stations in the Tampere area operate as follows. The area is divided into squares. The…
Description Suppose that the fourth generation mobile phone base stations in the Tampere area operate as follows. The area is divided into squares. The squares form an S * S matrix with the rows and columns numbered from 0 to S-1. Each square contain…
Description Suppose that the fourth generation mobile phone base stations in the Tampere area operate as follows. The area is divided into squares. The squares form an S * S matrix with the rows and columns numbered from 0 to S-1. Each square contain…
Mobile phones Time Limit: 5000MS Memory Limit: 65536K Total Submissions: 18608 Accepted: 8621 Description Suppose that the fourth generation mobile phone base stations in the Tampere a…
Description Suppose that the fourth generation mobile phone base stations in the Tampere area operate as follows. The area is divided into squares. The squares form an S * S matrix with the rows and columns numbered from 0 to S-1. Each square contain…
Mobile phones Time Limit: 5000MS Memory Limit: 65536K Total Submissions: 16893 Accepted: 7789 Description Suppose that the fourth generation mobile phone base stations in the Tampere area operate as follows. The area is divided into squares. The…
题目链接:http://poj.org/problem?id=1195 [题意] 给出一个全0的矩阵,然后一些操作 0 S:初始化矩阵,维数是S*S,值全为0,这个操作只有最开始出现一次 1 X Y A:对于矩阵的X,Y坐标增加A 2 L B R T:询问(L,B)到(R,T)区间内值的总和 3:结束对这个矩阵的操作 [思路] 二维树状数组单点更新+区域查询,可作为模板题. 注意坐标是从0开始,所以要+1 [代码] #include<cstdio> #include<cstrin…
Cornfields Time Limit: 1000MS Memory Limit: 30000K Total Submissions:8623 Accepted: 4100 Description FJ has decided to grow his own corn hybrid in order to help the cows make the best possible milk. To that end, he's looking to build the cornfiel…
Matrix Time Limit: 3000MS Memory Limit: 65536K Total Submissions: 17880 Accepted: 6709 Description Given an N*N matrix A, whose elements are either 0 or 1. A[i, j] means the number in the i-th row and j-th column. Initially we have A[i, j] = 0 (1…
Matrix Time Limit: 3000MS Memory Limit: 65536K Total Submissions: 17226 Accepted: 6461 Description Given an N*N matrix A, whose elements are either 0 or 1. A[i, j] means the number in the i-th row and j-th column. Initially we have A[i, j] = 0 (1…
题目链接:http://poj.org/problem?id=2155 Matrix Time Limit: 3000MS Memory Limit: 65536K Total Submissions: 32950 Accepted: 11943 Description Given an N*N matrix A, whose elements are either 0 or 1. A[i, j] means the number in the i-th row and j-th col…
D - Beauty Contest Time Limit:3000MS Memory Limit:65536KB 64bit IO Format:%I64d & %I64u Submit Status Description Bessie, Farmer John's prize cow, has just won first place in a bovine beauty contest, earning the title 'Miss Cow World'. As a r…
题意:给你一个n*n的全0矩阵,每次有两个操作: C x1 y1 x2 y2:将(x1,y1)到(x2,y2)的矩阵全部值求反 Q x y:求出(x,y)位置的值 树状数组标准是求单点更新区间求和,但是我们处理一下就可以完美解决此问题.区间更新可以使用区间求和的方法,在更新的(x2,y2)记录+1,在更新的(x1-1,y1-1)-1(向前更新到最前方).单点求和就只需要与区间更新相反,向后求一个区间和.这样做的理由是:如果求和的点在某次更新范围内,我们+1但是不执行-1,否者要么都不执行,要么都…
Matrix Time Limit: 3000MS Memory Limit: 65536K Total Submissions: 17224 Accepted: 6460 Description Given an N*N matrix A, whose elements are either 0 or 1. A[i, j] means the number in the i-th row and j-th column. Initially we have A[i, j] = 0 (1…
