Hdu 5274 Dylans loves tree (树链剖分模板) 题目传送门 #include <queue> #include <cmath> #include <cstdio> #include <cstring> #include <cstdlib> #include <iostream> #include <algorithm> #include <vector> #define ll long…

Dylans loves tree Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others)Total Submission(s): 1444    Accepted Submission(s): 329 Problem Description Dylans is given a tree with N nodes. All nodes have a value A[i].Nodes…

Dylans loves tree http://acm.hdu.edu.cn/showproblem.php?pid=5274 Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others) Problem Description Dylans is given a tree with N nodes. All nodes have a value A[i] .Nodes on tree…

Do use segment tree Time Limit: 1 Sec Memory Limit: 256 MB 题目连接 http://www.bnuoj.com/v3/problem_show.php?pid=39566 Description Given a tree with n (1 ≤ n ≤ 200,000) nodes and a list of q (1 ≤ q ≤ 100,000) queries, process the queries in order and out…

Description You are given a tree with N nodes. The tree’s nodes are numbered 1 through N and its edges are numbered 1 throughN − 1. Each edge is associated with a weight. Then you are to execute a series of instructions on the tree. The instructions…

HDU 2460 Network 题目链接 题意:给定一个无向图,问每次增加一条边,问个图中还剩多少桥 思路:先双连通缩点,然后形成一棵树,每次增加一条边,相当于询问这两点路径上有多少条边,这个用树链剖分+线段树处理 代码: #include <cstdio> #include <cstring> #include <algorithm> #include <vector> using namespace std; #pragma comment(linke…

欢迎访问~原文出处——博客园-zhouzhendong 去博客园看该题解 题目传送门 - POJ3237 题意概括 Description 给你由N个结点组成的树.树的节点被编号为1到N,边被编号为1到N-1.每一条边有一个权值.然后你要在树上执行一系列指令.指令可以是如下三种之一: CHANGE i v:将第i条边的权值改成v. NEGATE a b:将点a到点b路径上所有边的权值变成其相反数. QUERY a b:找出点a到点b路径上各边的最大权值. Input多组数据,数据为T<=20,对…

[CF725G]Messages on a Tree 题意:给你一棵n+1个节点的树,0号节点是树根,在编号为1到n的节点上各有一只跳蚤,0号节点是跳蚤国王.现在一些跳蚤要给跳蚤国王发信息.具体的信息传输过程如下: 1.信息的发起者把信息上传给他父亲节点处的跳蚤,然后自身进入等待状态.3.跳蚤国王在收到信息时会将信息立刻下传到发来信息的那个儿子,跳蚤国王可以在同一时刻下传多份信息.4.上传:a把信息传给b.如果b正处于等待状态,则b会立刻将a发来的信息下传回去.如果同时有好多个信息传给b,则b会…

You are given a tree (an acyclic undirected connected graph) with N nodes, and edges numbered 1, 2, 3-N-1. We will ask you to perfrom some instructions of the following form: CHANGE i ti : change the cost of the i-th edge to ti or QUERY a b : ask for…

Water Tree CodeForces 343D 树链剖分+线段树 题意 给定一棵n个n-1条边的树,起初所有节点权值为0. 然后m个操作, 1 x:把x为根的子树的点的权值修改为1: 2 x:把x结点到根路径上的点修改为0: 3 x:查询结点x的值. 解题思路 这个因为是在树上进行的操作,所以首先需要把树进行一些转化,比如使用dfs序列转变成一维的,这样方便使用线段树或则树状数组来进行操作.但是因为这里的操作2需要把x节点和它的父节点赋值为0,所以需要树链剖分来进行处理. 关于树链剖分的讲…