Wireless Network Time Limit: 10000MS   Memory Limit: 65536K Total Submissions: 18066   Accepted: 7618 Description An earthquake takes place in Southeast Asia. The ACM (Asia Cooperated Medical team) have set up a wireless network with the lap computer…

Description An earthquake takes place in Southeast Asia. The ACM (Asia Cooperated Medical team) have set up a wireless network with the lap computers, but an unexpected aftershock attacked, all computers in the network were all broken. The computers…

An earthquake takes place in Southeast Asia. The ACM (Asia Cooperated Medical team) have set up a wireless network with the lap computers, but an unexpected aftershock attacked, all computers in the network were all broken. The computers are repaired…

链接:http://poj.org/problem?id=2236 题意: 有一个计算机网络,n台计算机全部坏了,给你两种操作: 1.O x 修复第x台计算机 2.S x,y 判断两台计算机是否联通 联通的条件: 两台都修复好了,求距离小于d 思路: 数据很小,我们可以没修复一台就直接枚举已经修复的计算机找到距离小于d的,放到一个并查集里,查询的话直接查询是否再同一个并查集里就好了 实现代码: //while(scanf("\n%c", &ope) != EOF) #inclu…

An earthquake takes place in Southeast Asia. The ACM (Asia Cooperated Medical team) have set up a wireless network with the lap computers, but an unexpected aftershock attacked, all computers in the network were all broken. The computers are repaired…

水题 #include<cstdio> #include<cstring> #include<queue> #include<set> #include<cstdlib> #include<algorithm> #include<vector> #include<cmath> using namespace std; typedef long long LL; typedef pair<int,int&g…

A very big corporation is developing its corporative network. In the beginning each of the N enterprises of the corporation, numerated from 1 to N, organized its own computing and telecommunication center. Soon, for amelioration of the services, the…

Corporative Network Time Limit: 3000MS   Memory Limit: Unknown   64bit IO Format: %lld & %llu [Submit]   [Go Back]   [Status] Description   A very big corporation is developing its corporative network. In the beginning each of the N enterprises of th…

这题比较简单,注意路径压缩即可. AC代码 //#define LOCAL #include <stdio.h> #include <algorithm> using namespace std; const int maxn = 20000+5; int par[maxn], dis[maxn]; void init(int n) { for(int i = 0; i <= n; i++) { par[i] = i; dis[i] = 0; } } int findRoot…

转自:http://blog.csdn.net/shahdza/article/details/7779230 [HDU]1213 How Many Tables 基础并查集★1272 小希的迷宫 基础并查集★1325&&poj1308 Is It A Tree? 基础并查集★1856 More is better 基础并查集★1102 Constructing Roads 基础最小生成树★1232 畅通工程 基础并查集★2120 Ice_cream's world I 基础并查集★212…