/* HDU 6034 - Balala Power! [ 大数进位,贪心 ] 题意: 给一组字符串(小写英文字母),将上面的字符串考虑成26进制数,每个字母分配一个权值,问这组数字加起来的和最大是多少? 要求每个数字不能有前导0,即每个字符串首位字符不能赋0 分析: 对于每个字符,将每个字符串按位相加,得到这个字符的一个每位上的数量的数组 将其看成一个大数,满26进位,然后排序,从高到低赋值,注意考虑0 */ #include <bits/stdc++.h> using namespace…

题目链接 Problem Description Talented Mr.Tang has n strings consisting of only lower case characters. He wants to charge them with Balala Power (he could change each character ranged from a to z into each number ranged from 0 to 25, but each two differen…

Balala Power! Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others) Total Submission(s): 1411    Accepted Submission(s): 239 Problem Description Talented Mr.Tang has n strings consisting of only lower case characters.…

Balala Power! Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others)Total Submission(s): 2668    Accepted Submission(s): 562 Problem Description Sample Input 1 a 2 aa bb 3 a ba abc Sample Output Case #1: 25 Case #2: 132…

Balala Power! Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others)Total Submission(s): 3555    Accepted Submission(s): 844 Problem Description Talented Mr.Tang has n strings consisting of only lower case characters. H…

Balala Power![排序/进制思维] Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others)Total Submission(s): 6703    Accepted Submission(s): 1680 Problem Description Talented Mr.Tang has n strings consisting of only lower case cha…

Talented Mr.Tang has nn strings consisting of only lower case characters. He wants to charge them with Balala Power (he could change each character ranged from a to z into each number ranged from 0 to 25, but each two different characters should not…

题目大意:给出的字符串,每个字符建立一种与0-25的对应关系.然后每个字符串看成是一个26进制的数.问能获得的数的总和的最大值.(最后对1e9+7取模). 题目思考:把每个字符的贡献值看做一个26进制数字,贪心排序后,确保没有前导零.写的要规范点,卡时间. #include <stdio.h> #include <string.h> #include <vector> #include<math.h> #include <algorithm> #…

题意:给定一个 n 个字符串,然后问你怎么给 a-z赋值0-25,使得给定的字符串看成26进制得到的和最大,并且不能出现前导0. 析:一个很恶心的题目,细节有点多,首先是思路,给定个字符一个权值,然后要注意的进位,然后排序,从大到小,给每个字符赋值,如果最后一个出现前导0,就得向前找一个最小的不在首字符的来交换,但不能动了相对的顺序. 代码如下: #pragma comment(linker, "/STACK:1024000000,1024000000") #include <c…

Problem Description Talented Mr.Tang has n strings consisting of only lower case characters. He wants to charge them with Balala Power (he could change each character ranged from a to z into each number ranged from 0 to 25, but each two different cha…