1105 Spiral Matrix(25 分) This time your job is to fill a sequence of N positive integers into a spiral matrix in non-increasing order. A spiral matrix is filled in from the first element at the upper-left corner, then move in a clockwise spiral. The…

此文同步发布在CSDN:https://blog.csdn.net/weixin_44385565/article/details/90484058 1105 Spiral Matrix (25 分)   This time your job is to fill a sequence of N positive integers into a spiral matrix in non-increasing order. A spiral matrix is filled in from the…

This time your job is to fill a sequence of N positive integers into a spiral matrix in non-increasing order. A spiral matrix is filled in from the first element at the upper-left corner, then move in a clockwise spiral. The matrix has m rows and n c…

This time your job is to fill a sequence of N positive integers into a spiral matrix in non-increasing order. A spiral matrix is filled in from the first element at the upper-left corner, then move in a clockwise spiral. The matrix has m rows and n c…

https://pintia.cn/problem-sets/994805342720868352/problems/994805363117768704 This time your job is to fill a sequence of N positive integers into a spiral matrix in non-increasing order. A spiral matrix is filled in from the first element at the upp…

This time your job is to fill a sequence of N positive integers into a spiral matrix in non-increasing order. A spiral matrix is filled in from the first element at the upper-left corner, then move in a clockwise spiral. The matrix has m rows and n c…

This time your job is to fill a sequence of N positive integers into a spiral matrix in non-increasing order. A spiral matrix is filled in from the first element at the upper-left corner, then move in a clockwise spiral. The matrix has m rows and n c…

题意:给定N,以及N个数.找出满足m*n=N且m>=n且m-n最小的m.n值,建立大小为m*n矩阵,将N个数从大到下顺时针填入矩阵中. #include <iostream> #include <cstdio> #include <algorithm> #include <string.h> #include <cmath> #define LEFT 1 #define RIGHT 2 #define UP 3 #define DOWN 4…

简单模拟. #include<cstdio> #include<cstring> #include<cmath> #include<map> #include<queue> #include<string> #include<algorithm> using namespace std; +; int N,a[maxn]; int ans[maxn]; int m,n; ][]; void f() { dir[][]=;d…

题意:输入一个正整数N(实则<=1e5),接着输入一行N个正整数(<=1e4).降序输出螺旋矩阵. trick: 测试点1,3运行超时原因:直接用sqrt(N)来表示矩阵的宽会在N是素数时出错,直接扫一遍找一个最大因子即可,简单粗暴. AAAAAccepted code: #define HAVE_STRUCT_TIMESPEC #include<bits/stdc++.h> using namespace std; ]; ][]; int main(){ ios::sync_wi…