Given a set of non-overlapping intervals, insert a new interval into the intervals (merge if necessary). You may assume that the intervals were initially sorted according to their start times. Example 1:Given intervals [1,3],[6,9], insert and merge […

LeetCode中,有很多关于一组interval的问题.大体可分为两类: 1.查看是否有区间重叠: 2.合并重叠区间;  3.插入新的区间: 4. 基于interval的其他问题 [ 做题通用的关键步骤]: 1. 按照begin时间排序: 2. 判断两个相邻区间是否重叠: [假设] a. 给定的区间是半开区间 [begin, end); b. 已经按照"begin"排序. c. 当前的区间是begin, end; 要比较/合并的区间:[ intervals[i][0], interv…

Insert Interval Given a set of non-overlapping intervals, insert a new interval into the intervals (merge if necessary). You may assume that the intervals were initially sorted according to their start times. Example 1:Given intervals [1,3],[6,9], in…

一天一道LeetCode系列 (一)题目 Given a set of non-overlapping intervals, insert a new interval into the intervals (merge if necessary). You may assume that the intervals were initially sorted according to their start times. Example 1: Given intervals [1,3],[6,…

56. Merge Intervals是一个无序的,需要将整体合并:57. Insert Interval是一个本身有序的且已经合并好的,需要将新的插入进这个已经合并好的然后合并成新的. 56. Merge Intervals 思路:先根据start升序排序,然后合并 static作用:https://www.cnblogs.com/songdanzju/p/7422380.html 之间写的一个较为复杂的代码 /** * Definition for an interval. * struct…

Given a set of non-overlapping intervals, insert a new interval into the intervals (merge if necessary). You may assume that the intervals were initially sorted according to their start times. Example 1: Input: intervals = [[1,3],[6,9]], newInterval…

lc57 Insert Interval 仔细分析题目,发现我们只需要处理那些与插入interval重叠的interval即可,换句话说,那些end早于插入start以及start晚于插入end的interval都可以保留.我们只需要两个指针,i&j分别保存重叠interval中最早start和最晚end即可,然后将interval [i, j]插入即可 class Solution { public int[][] insert(int[][] intervals, int[] newInte…

Insert Interval  Given a set of non-overlapping intervals, insert a new interval into the intervals (merge if necessary). You may assume that the intervals were initially sorted according to their start times. Example 1: Given intervals [1,3],[6,9],…

Insert interval  题意简述:给定若干个数轴上的闭区间,保证互不重合且有序,要求插入一个新的区间,并返回新的区间集合,保证有序且互不重合. 只想到了一个线性的解法,所有区间端点,只要被其他区间覆盖,就是不合法的,把他们去掉后,就可以直接得到答案.设新区间为[left,right],那么,比left小的端点显然合法,比right大的端点显然也合法,left和right之间的端点显然不合法,然后判断Left和right是否合法即可.难度不大,代码有些细节需要注意. /** * Defi…

1. 原题链接 https://leetcode.com/problems/insert-interval/description/ 2. 题目要求 该题与上一题的区别在于,插入一个新的interval对象,将此对象与所给列表里的Interval对象进行合并. 3. 解题思路 首先遍历Interval对象列表,找到插入位置.将插入位置之前的列表中的Interval对象直接加入结果列表. 然后查找所要插入Interval对象的end属性在列表中的位置. 最后将列表中剩余的Interval对象全部加…