原文地址http://www.vogella.com/tutorials/EclipseRCP/article.html Table of Contents 1. Eclipse 4 1.1. What is Eclipse 4? 1.2. Eclipse 4 vs. Eclipse 3.x 1.3. Terminology 2. The Architecture of Eclipse 2.1. Eclipse based applications 2.2. Core components of…

本文是一篇笔记,大部分内容取自 CLRS 第三版,第 24.1 节. Exercise 24.1-4 Modify the Bellman-Ford algorithm so that it sets $v.d$ to $-\infty$ for all vertices $v$ for which there is a negative-weight cycle on some path from the source to $v$. Theorem 24.4 (Correctness of…

https://www.ted.com/talks/emily_balcetis_why_some_people_find_exercise_harder_than_others/transcript 00:12Vision is the most important and prioritized[praɪˈɔ:rətaɪz]优先处理 sense that we have. We are constantly looking at the world around us, and quickl…

/* Write a program to print the corresponding Celsius to Fahrenheit table. */ #include <stdio.h> /* print Celsius-Fahrenheit table for celsius = 0, 20, ..., 300; floating-point version */ main() { float fahr, celsius; int lower, upper, step; lower =…

Lab 1 Exercise 3 设置一个断点在地址0x7c00处,这是boot sector被加载的位置.然后让程序继续运行直到这个断点.跟踪/boot/boot.S文件的每一条指令,同时使用boot.S文件和系统为你反汇编出来的文件obj/boot/boot.asm.你也可以使用GDB的x/i指令来获取去任意一个机器指令的反汇编指令,把源文件boot.S文件和boot.asm文件以及在GDB反汇编出来的指令进行比较. 追踪到bootmain函数中,而且还要具体追踪到readsect()子函数…

这是一个家族谱: ;child(define-struct child (father mother name date eyes)) #lang racket ;child (define-struct child (father mother name date eyes)) ;; Oldest Generation: (define Carl (make-child empty empty 'Carl 1926 'green)) (define Bettina (make-child em…

CMSC 216 Exercise #5 Spring 2019Shell Jr (”Shellito”) Due: Tue Apr 23, 2019, 11:30PM1 ObjectivesTo practice fork() and exec by implementing a very simple shell.2 OverviewThe first thing you need to do is to copy the directory shelljr we have left in…

软件测试:3.Exercise Section 2.3 /************************************************************ * Finds and prints n prime integers * Jeff Offutt, Spring 2003 *************************************************************/ private static void printPrimes(in…

1.在一条含有 N 个点的封闭轮廓中,我们可以通过比较每个点与其它点的距离,找出最外层的点.(这个翻译有问题,而且这个问题是实际问题) a.这样一个算法的复杂度是多少? b.怎样用更快的速度完成这个任务?   1. We can find the extremal points (i.e., the two points that are farthest apart) in a closed contour of N points by comparing the distance of ea…

A GIF decoder: an exercise in Go interfaces  一个GIF解码器:go语言接口训练 25 May 2011 Introduction At the Google I/O conference in San Francisco on May 10, 2011, we announced that the Go language is now available on Google App Engine. Go is the first language t…