【leetcode刷题笔记】Search in Rotated Sorted Array II

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刷题33. Search in Rotated Sorted Array

一.题目说明这个题目是33. Search in Rotated Sorted Array,说的是在一个"扭转"的有序列表中,查找一个元素,时间复杂度O(logn). 二.我的解答这是一个查找,根据复杂度,我们知道只能用二分查找.但由于这个不是一个完全的有序列表,故需要改造.先写出二分查找(来源于数据结构): 二分查找: int search(vector<int>& nums, int target){ if(nums.size()<0) return…

LeetCode 新题: Find Minimum in Rotated Sorted Array II 解题报告-二分法模板解法

Find Minimum in Rotated Sorted Array II Follow up for "Find Minimum in Rotated Sorted Array":What if duplicates are allowed? Would this affect the run-time complexity? How and why?Suppose a sorted array is rotated at some pivot unknown to you be…

LeetCode 新题: Find Minimum in Rotated Sorted Array 解题报告-二分法模板解法

Find Minimum in Rotated Sorted Array Question Solution Suppose a sorted array is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). Find the minimum element. You may assume no duplicate exists in the ar…

LeetCode: Search in Rotated Sorted Array II 解题报告

Search in Rotated Sorted Array II Follow up for "LeetCode: Search in Rotated Sorted Array 解题报告":What if duplicates are allowed? Would this affect the run-time complexity? How and why? Write a function to determine if a given target is in the arr…

[LeetCode] Search in Rotated Sorted Array II [36]

称号 Follow up for "Search in Rotated Sorted Array": What if duplicates are allowed? Would this affect the run-time complexity? How and why? Write a function to determine if a given target is in the array. 原题链接(点我) 解题思路这题和Search in Rotated Sorted…

LeetCode 81 Search in Rotated Sorted Array II [binary search] <c++>

LeetCode 81 Search in Rotated Sorted Array II [binary search] <c++> 给出排序好的一维有重复元素的数组,随机取一个位置断开,把前半部分接到后半部分后面,得到一个新数组,在新数组中查找给定数是否存在,时间复杂度限制\(O(log_2n)\) C++ 因为有重复元素存在,nums[l] <= nums[mid]不能说明[l,mid]区间内一定是单调的,比如数组[1,2,3,1,1,1,1],但是严格小于和严格大于的情况还是可以…

leetcode 153. Find Minimum in Rotated Sorted Array 、154. Find Minimum in Rotated Sorted Array II 、33. Search in Rotated Sorted Array 、81. Search in Rotated Sorted Array II 、704. Binary Search

这4个题都是针对旋转的排序数组.其中153.154是在旋转的排序数组中找最小值,33.81是在旋转的排序数组中找一个固定的值.且153和33都是没有重复数值的数组,154.81都是针对各自问题的版本1增加了有重复数值的限制条件. 153.154都需要考虑是否旋转成和原数组一样的情况,特别的,154题还需要考虑10111和11101这种特殊情况无法使用二分查找. 33.81则不用考虑这些情况. 找最小值的题主要是利用最小值小于他前一个位置的数,同时也小于后一个位置的数 153. Find Mini…