此题是一道线段树的裸题,这里只是为了保存我的zkw线段树模板 #include <cstdio> #include <cstring> #include <iostream> using namespace std; typedef long long LL; inline int geti() { static int Ina; static char Inc; static bool InSign; InSign = false; while ((Inc = get…
poj3468 A Simple Problem with Integers 题意:O(-1) 思路:O(-1) 线段树功能:update:成段增减 query:区间求和 Sample Input 10 5 1 2 3 4 5 6 7 8 9 10 Q 4 4 Q 1 10 Q 2 4 C 3 6 3 Q 2 4 Sample Output 4 55 9 15 Hint The sums may exceed the range of 32-bit integers. 题目大意:   N个数 M…
A Simple Problem with Integers Time Limit: 5000MS   Memory Limit: 131072K Total Submissions: 92127   Accepted: 28671 Case Time Limit: 2000MS 描述 You have N integers, A1, A2, ... , AN. You need to deal with two kinds of operations. One type of operatio…
A Simple Problem with Integers Time Limit: 5000MS   Memory Limit: 131072K Total Submissions: 60745   Accepted: 18522 Case Time Limit: 2000MS Description You have N integers, A1, A2, ... , AN. You need to deal with two kinds of operations. One type of…
A Simple Problem with Integers Time Limit: 5000MS   Memory Limit: 131072K Total Submissions: 140120   Accepted: 43425 Case Time Limit: 2000MS Description You have N integers, A1, A2, ... , AN. You need to deal with two kinds of operations. One type o…
题目传送门 A Simple Problem with Integers Time Limit: 5000MS   Memory Limit: 131072K Total Submissions: 142198   Accepted: 44136 Case Time Limit: 2000MS Description You have N integers, A1, A2, ... , AN. You need to deal with two kinds of operations. One…
A Simple Problem with Integers Time Limit: 5000MS   Memory Limit: 131072K Total Submissions: 57666   Accepted: 17546 Case Time Limit: 2000MS Description You have N integers, A1, A2, ... , AN. You need to deal with two kinds of operations. One type of…
A Simple Problem with Integers Time Limit: 5000MS   Memory Limit: 131072K Total Submissions: 149972   Accepted: 46526 题目链接:http://poj.org/problem?id=3468 Description: You have N integers, A1, A2, ... , AN. You need to deal with two kinds of operation…
A Simple Problem with Integers 这个题目首先要打表找规律,这个对2018取模最后都会进入一个循环节,这个循环节的打表要用到龟兔赛跑. 龟兔赛跑算法 floyed判环算法 这个算法我觉得还是很有意思的,可以学习一下. 不过这个题目这个算法打表还是有点难写的. 由这个算法可以得到这个循环节的最大长度是6 最大入环距离是4. 为什么有些循环节不是6,还是可以用6呢,因为每个元素平方最大周期为6,且6是其他所有周期的公倍数. 然后学完之后还是不太会这个题目怎么写,2018…
You have N integers, A1, A2, ... , AN. You need to deal with two kinds of operations. One type of operation is to add some given number to each number in a given interval. The other is to ask for the sum of numbers in a given interval. Input The firs…