leetcode-easy-math-13 Roman to Integer】的更多相关文章

1.题目13. Roman to Integer Roman numerals are represented by seven different symbols: I, V, X, L, C, D and M. Symbol Value I 1 V 5 X 10 L 50 C 100 D 500 M 1000 For example, two is written as II in Roman numeral, just two one's added together. Twelve is…
Roman numerals are represented by seven different symbols: I, V, X, L, C, D and M. Symbol Value I 1 V 5 X 10 L 50 C 100 D 500 M 1000 For example, two is written as II in Roman numeral, just two one's added together. Twelve is written as, XII, which i…
能力有限,这道题采用的就是暴力方法,也只超过了39%的用户.需要注意的就是罗马数字如果IXC的后一位比前一位大的采取的是减的方式. Given a roman numeral, convert it to an integer. Input is guaranteed to be within the range from 1 to 3999. 给定一个罗马数字,将其转换为整数. 输入保证在1到3999之间. class Solution { public int romanToInt(Stri…
#-*- coding: UTF-8 -*-#从前向后遍历罗马数字,#如果某个数比前一个数小,则加上该数.反之,减去前一个数的两倍然后加上该数###-----技术规则-----#-------------------------------------------------------------------------------------##1.相同的数字连写,所表示的数等于这些数字相加得到的数,例如:III = 3##2.小的数字在大的数字右边,所表示的数等于这些数字相加得到的数,例如…
13. Roman to Integer Easy Roman numerals are represented by seven different symbols: I, V, X, L, C, D and M. Symbol Value I 1 V 5 X 10 L 50 C 100 D 500 M 1000 For example, two is written as II in Roman numeral, just two one's added together. Twelve i…
题目描述 罗马数字包含以下七种字符:I, V, X, L,C,D 和 M. 字符 数值 I 1 V 5 X 10 L 50 C 100 D 500 M 1000 例如, 罗马数字 2 写做 II ,即为两个并列的 1.12 写做 XII ,即为 X + II . 27 写做 XXVII, 即为 XX + V + II . 通常情况下,罗马数字中小的数字在大的数字的右边.但也存在特例,例如 4 不写做 IIII,而是 IV.数字 1 在数字 5 的左边,所表示的数等于大数 5 减小数 1 得到的数…
13.Roman to Integer Roman numerals are represented by seven different symbols: I, V, X, L, C, D and M. Symbol Value I 1 V 5 X 10 L 50 C 100 D 500 M 1000 For example, two is written as II in Roman numeral, just two one's added together. Twelve is writ…
Roman to Integer Given a roman numeral, convert it to an integer. Input is guaranteed to be within the range from 1 to 3999. public class Solution { public int romanToInt(String s) { if (s == null || s.length()==0) { return 0; } Map<Character, Intege…
Roman to Integer Given a roman numeral, convert it to an integer. Input is guaranteed to be within the range from 1 to 3999. 解法一:非递归 从左到右遍历每个字符,并记录上个字符来处理双字符情况即可. class Solution { public: int romanToInt(string s) { ; ; ; i < s.size(); i ++) { switch(…
我现在在做一个叫<leetbook>的免费开源书项目,力求提供最易懂的中文思路,目前把解题思路都同步更新到gitbook上了,需要的同学可以去看看 书的地址:https://hk029.gitbooks.io/leetbook/ 013. Roman to Integer 问题 Given a roman numeral, convert it to an integer. Input is guaranteed to be within the range from 1 to 3999. S…
Roman numerals are represented by seven different symbols: I, V, X, L, C, D and M. Symbol Value I 1 V 5 X 10 L 50 C 100 D 500 M 1000 For example, two is written as II in Roman numeral, just two one's added together. Twelve is written as, XII, which i…
一天一道LeetCode系列 (一)题目 Given a roman numeral, convert it to an integer. Input is guaranteed to be within the range from 1 to 3999. (二)解题 和上一题相反,这题将罗马数字转换成整形数. 注意到 4,9,40,90,400,900这些特殊的数字的区别就不难写出代码了. class Solution { public: int romanToInt(string s) {…
1.题目: 原题:Given a roman numeral, convert it to an integer. Input is guaranteed to be within the range from 1 to 3999. Subscribe to see which companies asked this questio 解析:给出一个罗马数字,要求把其转换为一个整数.输入范围在1到3999内. 罗马数字的规则如下: 罗马数字 I V X L C D M 代表的阿拉伯数字 1 5…
https://leetcode.com/problems/roman-to-integer/ 原题: Given a roman numeral, convert it to an integer. Input is guaranteed to be within the range from 1 to 3999. 思路: 关键是要搞清罗马数字规则.PS:不用考虑错误输入. 核心: 遍历一遍,相同字母合并成对应数,然后比较如果比它后面的小就减去,否则就加上.时间复杂度O(n). 具体解析: 基…
如果某一个字母代表的数字大于上一个字母代表的数字小,那么加上这个数字,否则,减去两倍的前一个数字,然后加上这一位数字. public class Solution { private static char[][] chars = {{'I', 'V'}, {'X', 'L'}, {'C', 'D'}, {'M', 'O'}}; private static HashMap<Character, Integer> map = null; private static void init() {…
题目: Given a roman numeral, convert it to an integer. Input is guaranteed to be within the range from 1 to 3999. 思路:与12题正好相反,罗马数字基本字符集:I V X L C D M (1, 5, 10, 50, 100, 500, 1000).思路是从字符串最低位开始匹配,累加相应字符对应的阿拉伯数字,要注意的就是I,X,L(1,10,100)要判断是在左还是在右,在左就减在右就加.…
题目描述: Given a roman numeral, convert it to an integer. 解题分析: 这道题只要百度一下转换的规则,然后着这解释写代码即可.实现上并没有什么难度,直接看代码即可 具体代码: public class Solution { public int romanToInt(String s){ int[] value={1000,500,100,50,10,5,1}; char[] array ="MDCLXVI".toCharArray()…
问题描述: Given a roman numeral, convert it to an integer. Input is guaranteed to be within the range from 1 to 3999. 解题思路: 上一题反过来就可以了,其实觉得这两道题很没有意思. 代码如下: public class Solution { public int romanToInt(String s) { int result; if (s == null || s.length()…
题目: Given a roman numeral, convert it to an integer. Input is guaranteed to be within the range from 1 to 3999. 题目分析: 将罗马数字转换成阿拉伯数字,规则如下:罗马数字共有七个,即I(1),V(5),X(10),L(50),C(100),D(500),M(1000). 按照下面的规则可以表示任意正整数. 重复数次:一个罗马数字重复几次,就表示这个数的几倍.右加左减:在一个较大的罗马数…
题意: Roman numerals are represented by seven different symbols: I, V, X, L, C, D and M. Symbol Value I 1 V 5 X 10 L 50 C 100 D 500 M 1000 For example, two is written as II in Roman numeral, just two one's added together. Twelve is written as, XII, whi…
题目要求 Roman numerals are represented by seven different symbols: I, V, X, L, C, Dand M. Symbol Value I 1 V 5 X 10 L 50 C 100 D 500 M 1000 For example, two is written as II in Roman numeral, just two one's added together. Twelve is written as, XII, whi…
Roman numerals are represented by seven different symbols: I, V, X, L, C, D and M. Symbol Value I 1 V 5 X 10 L 50 C 100 D 500 M 1000 For example, two is written as II in Roman numeral, just two one's added together. Twelve is written as, XII, which i…
Roman numerals are represented by seven different symbols: I, V, X, L, C, D and M. Symbol Value I 1 V 5 X 10 L 50 C 100 D 500 M 1000 For example, two is written as II in Roman numeral, just two one's added together. Twelve is written as, XII, which i…
Given a roman numeral, convert it to an integer. Input is guaranteed to be within the range from 1 to 3999. 解法: 只要考虑两种情况即可: 第一,如果当前数字是最后一个数字,或者之后的数字比它小的话,则加上当前数字 第二,其他情况(即为4或者9,这种情况下才可能出现后面的罗马数字比前面的大),则减去这个数字 public class Solution { public int romanT…
一.题目链接:https://leetcode.com/problems/roman-to-integer/ 二.题目大意: 给定一个罗马数字,返回它的整数形式. 三.题解: 这道题与12题恰好相反,关键之处在于罗马数字的组成规律.首先,弄清楚每个罗马字母对应的数字大小: 实质上,对于一个罗马数字,只需遍历它的每个字母,然后将字母对应的数字逐一相加即可,但是如果后一个字母对应的数字比相邻的前一个字母对应的数字大的话,那么这两个字母对应的数值实际上是大的数字减去小的数字,而不是两个数字的和.举个例…
题目链接 https://leetcode.com/problems/roman-to-integer/?tab=Description   int toNumber(char ch) { switch (ch) { case 'I': return 1; case 'V': return 5; case 'X': return 10; case 'L': return 50; case 'C': return 100; case 'D': return 500; case 'M': retur…
题意:将罗马数字1到3999转化成自然数字,这里用了STL库map将罗马字符映射到自然数字. I,V,X,L,C,D,M -> 1,5,10,50,100,500,1000 m[s[i]]<m[s[i+1]//如IV 就需要减去1 class Solution { public: map<char,int> m; Solution(){ ; ] = "IVXLCDM"; ,,,,,,}; ; i < N; ++i){ m[str[i]] = num[i];…
题目意思:罗马数字转int 思路:字符串从最后一位开始读,IV:+5-1 class Solution { public: int romanToInt(string s) { map<char,int> mymap; mymap[; mymap[; mymap[; mymap[; mymap[; mymap[; mymap[; ]]; ;i>=;--i){ ]]) ans-=mymap[s[i]]; else ans+=mymap[s[i]]; } return ans; } };…
思路:罗马计数转阿拉伯数字.罗马数字构造规则:http://www.cnblogs.com/glorywu/p/5256968.html.从右至左,用max记录当前最大数的符号,若当前索引处的数字比max大,则将总数加上当前索引字符所代表的的数,如果小,则将总数减去当前索引所代表的数字. 阿拉伯数转罗马计数…
描述: 将一个字符串表示的罗马数字转为整数,范围0~3999 解决: 如果后一个比前一个大,则表示减,没什么技巧. map<}, {}, {}, {}, {}, {}, {}}; int romanToInt(string s) { ; ; for (auto i : s) { if (m[i] > last) { ret = ret - last - last + m[i]; last = ; } else ret = ret + m[i]; last = m[i]; } return re…