Super Jumping! Jumping! Jumping! Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 56574    Accepted Submission(s): 26248 Problem Description Nowadays, a kind of chess game called “Super Jumping!…

#include <bits/stdc++.h> #define PI acos(-1.0) #define mem(a,b) memset((a),b,sizeof(a)) #define TS printf("!!!\n") #define pb push_back //std::ios::sync_with_stdio(false); using namespace std; //priority_queue<int,vector<int>,grea…

Super Jumping! Jumping! Jumping! Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 32134    Accepted Submission(s): 14467 Problem Description Nowadays, a kind of chess game called “Super Jumping!…

Super Jumping! Jumping! Jumping! Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 23328    Accepted Submission(s): 10266 Problem Description Nowadays, a kind of chess game called “Super Jumping!…

思路和LIS差不多,dp[i]为i结尾最大值 #include <iostream> #include <string> #include <cstring> #include <cstdlib> #include <cstdio> #include <cmath> #include <algorithm> #include <stack> #include <queue> #include <…

Super Jumping! Jumping! Jumping! Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 33384    Accepted Submission(s): 15093 Problem Description Nowadays, a kind of chess game called “Super Jumping!…

Super Jumping! Jumping! Jumping! Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 32564    Accepted Submission(s): 14692 Problem Description Nowadays, a kind of chess game called “Super Jumping!…

Super Jumping! Jumping! Jumping! Time Limit:1000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64u Submit Status Practice HDU 1087 Appoint description:  System Crawler  (2017-04-13) Description Nowadays, a kind of chess game called “Super…

HDU 1257 最少拦截系统 最长递增子序列 题意 这个题的意思是说给你\(n\)个数,让你找到他最长的并且递增的子序列\((LIS)\).这里和最长公共子序列一样\((LCS)\)一样,子序列只要满足前后关系即可,不需要相邻. 解题思路 解法一:这个可以用动态规划来实现,\(dp[i]\)代表前\(i\)个数列中以第\(i\)个数为结尾的\(LIS\)的长度.递推关系如下: \[ dp[i] = \begin{aligned} & max(dp[k])+1 & \text{k=1,2.…

http://acm.hdu.edu.cn/showproblem.php?pid=1087   Super Jumping! Jumping! Jumping! Time Limit:1000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64u Submit Status Practice HDU 1087 Description Nowadays, a kind of chess game called “Super Ju…

最少拦截系统 Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 80802    Accepted Submission(s): 31005 Problem Description 某国为了防御敌国的导弹袭击,发展出一种导弹拦截系统.但是这种导弹拦截系统有一个缺陷:虽然它的第一发炮弹能够到达任意的高度,但是以后每一发炮弹都不能超过前一发的高…

H - Super Jumping! Jumping! Jumping! Time Limit:1000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64u Submit Status Practice HDU 1087 Appoint description:  System Crawler  (2015-11-18) Description Nowadays, a kind of chess game called “Su…

题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=1087 Super Jumping! Jumping! Jumping! Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 47055    Accepted Submission(s): 21755 Problem Description N…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1087 Super Jumping! Jumping! Jumping! Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 24452    Accepted Submission(s): 10786 Problem Description No…

HDU 1087 题目大意:给定一个序列,只能走比当前位置大的位置,不可回头,求能得到的和的最大值.(其实就是求最大上升(可不连续)子序列和) 解题思路:可以定义状态dp[i]表示以a[i]为结尾的上升子序列的和的最大值,那么便可以得到状态转移方程 dp[i] = max(dp[i], dp[j]+a[i]), 其中a[j]<a[i]且j<i; 另外每个dp[i]可以先初始化为a[i] 理解:以a[i]为结尾的上升子序列可以由前面比a[i]小的某个序列加上a[i]来取得,故此有dp[j]+a[…

Problem Description Nowadays, a kind of chess game called "Super Jumping! Jumping! Jumping!" is very popular in HDU. Maybe you are a good boy, and know little about this game, so I introduce it to you now. The game can be played by two or more t…

Nowadays, a kind of chess game called “Super Jumping! Jumping! Jumping!” is very popular in HDU. Maybe you are a good boy, and know little about this game, so I introduce it to you now. The game can be played by two or more than two players. It consi…

Problem Description Nowadays, a kind of chess game called “Super Jumping! Jumping! Jumping!” is very popular in HDU. Maybe you are a good boy, and know little about this game, so I introduce it to you now.The game can be played by two or more than tw…

最长公共子序列(LCS) [问题] 求两字符序列的最长公共字符子序列 问题描述:字符序列的子序列是指从给定字符序列中随意地(不一定连续)去掉若干个字符(可能一个也不去掉)后所形成的字符序列.令给定的字符序列X=“x0,x1,…,xm-1”,序列Y=“y0,y1,…,yk-1”是X的子序列,存在X的一个严格递增下标序列<i0,i1,…,ik-1>,使得对所有的j=0,1,…,k-1,有xij=yj.例如,X=“ABCBDAB”,Y=“BCDB”是X的一个子序列. 考虑最长公共子序列问题如何分解成…

Super Jumping! Jumping! Jumping! Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 56910    Accepted Submission(s): 26385 Problem Description Nowadays, a kind of chess game called “Super Jumping!…

原博文:传送门 最长递增子序列(Longest Increasing Subsequence) 下面我们简记为 LIS. 定义d[k]:长度为k的上升子序列的最末元素,若有多个长度为k的上升子序列,则记录最小的那个最末元素.注意d中元素是单调递增的,下面要用到这个性质.首先len = 1,d[1] = a[1],然后对a[i]:若a[i]>d[len],那么len++,d[len] = a[i];否则,我们要从d[1]到d[len-1]中找到一个j,满足d[j-1]<a[i]<d[j],…

单调递增最长子序列 时间限制:3000 ms  |  内存限制:65535 KB 难度:4   描述 求一个字符串的最长递增子序列的长度 如:dabdbf最长递增子序列就是abdf,长度为4   输入 第一行一个整数0<n<20,表示有n个字符串要处理 随后的n行,每行有一个字符串,该字符串的长度不会超过10000 输出 输出字符串的最长递增子序列的长度 样例输入 3 aaa ababc abklmncdefg 样例输出 1 3 7 来源 经典题目 上传者 iphxer 先用之前学过的方法做过…

一.最长公共子序列 经典的动态规划问题,大概的陈述如下: 给定两个序列a1,a2,a3,a4,a5,a6......和b1,b2,b3,b4,b5,b6.......,要求这样的序列使得c同时是这两个序列中的部分(不要求连续),这个就叫做公共子序列,然后最长公共子序列自然就是所有的子序列中最长的啦. 既然是动态规划,难点肯定是在转移方程那了.首先我们用一张网上流传的图: 我个人觉得这张图最好的阐述了这个问题的解法.下面说一下我的理解:首先我们要考虑怎么表示LCS中的各个状态,这个知道的可能觉得很…

转自:点击打开链接 最长递增子序列,Longest Increasing Subsequence 下面我们简记为 LIS. 排序+LCS算法 以及 DP算法就忽略了,这两个太容易理解了. 假设存在一个序列d[1..9] = 2 1 5 3 6 4 8 9 7,可以看出来它的LIS长度为5. 下面一步一步试着找出它. 我们定义一个序列B,然后令 i = 1 to 9 逐个考察这个序列. 此外,我们用一个变量Len来记录现在最长算到多少了 首先,把d[1]有序地放到B里,令B[1] = 2,就是说当…

Give an integer array,find the longest increasing continuous subsequence in this array. An increasing continuous subsequence: Can be from right to left or from left to right. Indices of the integers in the subsequence should be continuous. Notice O(n…

题目链接:51nod 1134 最长递增子序列 #include<cstdio> #include<cstring> #include<algorithm> using namespace std; ; int a[N]; int b[N]; int Search(int num, int low, int high){ int mid; while(low <= high){ mid = (low + high)/; ; ; } return low; } in…

最长递增子序列是动态规划中经典的问题,详细如下: 在一个已知的序列{a1,a2,...,an}中,取出若干数组组成新的序列{ai1,ai2,...,aim},其中下标i1,i2,...,im保持递增,即新数列中的各个数之间依旧保持原数列中的先后顺序,那么我们称新的序列{ai1,ai2,...,aim}为原序列的一个子序列.若在子序列中,当下标ix > iy时,aix > aiy,那么我们称这个子序列为原序列的一个递增子序列.最长递增子序列问题,就是在一个给定的原序列中,求得最长递增子序列长度.…

大致题意:给出一队士兵的身高,一开始不是按身高排序的.要求最少的人出列,使原序列的士兵的身高先递增后递减. 求递增和递减不难想到递增子序列,要求最少的人出列,也就是原队列的人要最多. 1 2 3 4 5 4 3 2 1 这个序列从左至右看前半部分是递增,从右至左看前半部分也是递增.所以我们先把从左只右和从右至左的LIS分别求出来. 如果结果是这样的: A[i]={1.86 1.86 1.30621 2 1.4 1 1.97 2.2} //原队列 a[i]={1 1 1 2 2 1 3 4} b[…

Bridging signals Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 12251   Accepted: 6687 Description 'Oh no, they've done it again', cries the chief designer at the Waferland chip factory. Once more the routing designers have screwed up c…

题意: 求解最大递增子序列. 例如:3 1 3 2 输入 3  个数 1 3 2 则递增子序列有 {1} {3} {2} {1 3} {1 2} ,故输出子序列的最大和 4 解题思路: x[n](n个数) 数组存储 输入的数据 dp[i] 用来记录 前 i+1 {数据从下标为0开始存储}个数的 最大结果 遍历dp[] 找到最大值即可. 因 G20 网站暂停提交 明天测试代码. 2016.08.27 代码提交成功! 代码如下: #include<bits/stdc++.h> using name…