题目链接:https://vjudge.net/problem/UVALive-5107 题目大意:用ABCDE代表不同的数字,给出形如ABBDE___ABCCC = BDBDE的东西: 空格里面可以填入+-*/的运算符,给字母赋予不同的值,问有多少种情况使得 等式成立. 题目分析: 可以直接用大模拟+暴力求解,注意对于重复情况的判重. 给出代码: #include <iostream> #include <set> #include <algorithm> #incl…

A very hard Aoshu problem Problem Description Aoshu is very popular among primary school students. It is mathematics, but much harder than ordinary mathematics for primary school students. Teacher Liu is an Aoshu teacher. He just comes out with a pro…

题目连接:http://acm.hdu.edu.cn/showproblem.php?pid=4403 A very hard Aoshu problem Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 1080    Accepted Submission(s): 742 Problem Description Aoshu is ver…

题目链接:A hard Aoshu Problem DES:给三个字符串,包含的字符是A-E范围内的.长度都不超过8.每个字符可以而且只可以匹配一个数字.两个字符不能匹配相同的数字.前两个式子之间可以有+-*/四中关系.然后=第三个式子.问.会有多少种关系式. #include<stdio.h> #include<string.h> #include<iostream> using namespace std; ][]; ], b[], c[]; // 字符转换成数字后…

Description Math Olympiad is called “Aoshu” in China. Aoshu is very popular in elementary schools. Nowadays, Aoshu is getting more and more difficult. Here is a classic Aoshu problem: ABBDE __ ABCCC = BDBDE In the equation above, a letter stands for…

Description Math Olympiad is called “Aoshu” in China. Aoshu is very popular in elementary schools. Nowadays, Aoshu is getting more and more difficult. Here is a classic Aoshu problem: ABBDE __ ABCCC = BDBDEIn the equation above, a letter stands for a…

A very hard Aoshu problem                           Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Problem Description Aoshu is very popular among primary school students. It is mathematics, but much harder than o…

A very hard Aoshu proble Problem Description Aoshu is very popular among primary school students. It is mathematics, but much harder than ordinary mathematics for primary school students. Teacher Liu is an Aoshu teacher. He just comes out with a prob…

题意:给定一个n,求前 n 个正整数,正奇数,正偶数之和. 析:没什么好说的,用前 n 项和公式即可. 代码如下: #pragma comment(linker, "/STACK:1024000000,1024000000") #include <cstdio> #include <string> #include <cstdlib> #include <cmath> #include <iostream> #include…

HASH+暴力. /* 4403 */ #include <iostream> #include <cstdio> #include <cstring> #include <cstdlib> #include <map> using namespace std; #define MAXN 55 map<]; char s[MAXN]; int get(int b, int e) { ; for (int i=b; i<e; ++i)…