题目: Given an integer array with no duplicates. A maximum tree building on this array is defined as follow: The root is the maximum number in the array. The left subtree is the maximum tree constructed from left part subarray divided by the maximum nu…

网址:https://leetcode.com/problems/maximum-binary-tree/ 参考: https://leetcode.com/problems/maximum-binary-tree/discuss/106146/C%2B%2B-O(N)-solution 我自己的做法是依照题意的逻辑,逐一递归的做法. O(n2) /** * Definition for a binary tree node. * struct TreeNode { * int val; * T…

Given an integer array with no duplicates. A maximum tree building on this array is defined as follow: The root is the maximum number in the array. The left subtree is the maximum tree constructed from left part subarray divided by the maximum number…

654. Maximum Binary Tree 题目大意: 意思就是给你一组数,先选一个最大的作为根,这个数左边的数组作为左子树,右边的数组作为右子树,重复上一步. 读完就知道是递归了. 这个题真尼玛恶心,对JavaScript的友好度简直为0,用Js的可以直接放弃了. function TreeNode(val) { this.val = val this.left = this.right = null } var constructMaximumBinaryTree = function…

作者: 负雪明烛 id: fuxuemingzhu 个人博客:http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 递归 日期 题目地址:https://leetcode.com/problems/maximum-binary-tree/description/ 题目描述 Given an integer array with no duplicates. A maximum tree building on this array is defined as fol…

Given an integer array with no duplicates. A maximum tree building on this array is defined as follow: The root is the maximum number in the array. The left subtree is the maximum tree constructed from left part subarray divided by the maximum number…

［抄题］: Given an integer array with no duplicates. A maximum tree building on this array is defined as follow: The root is the maximum number in the array. The left subtree is the maximum tree constructed from left part subarray divided by the maximum…

题目如下: Given an integer array with no duplicates. A maximum tree building on this array is defined as follow: The root is the maximum number in the array. The left subtree is the maximum tree constructed from left part subarray divided by the maximum…

每次找到数组中的最大值,然后递归的构建左右树 public TreeNode constructMaximumBinaryTree(int[] nums) { if (nums.length==0) return null; return builder(nums,0,nums.length-1); } public TreeNode builder(int[] nums,int sta,int end) { /* 思路就是每次找到最大值,然后分为两个子数组递归构建左右树 */ if (sta>…

Given an integer array with no duplicates. A maximum tree building on this array is defined as follow: The root is the maximum number in the array. The left subtree is the maximum tree constructed from left part subarray divided by the maximum number…

用一个整型数组构建一个二叉树,根结点是数组中的最大值,左右子树分别是根结点的值在数组中左右两边的部分. 分析,这是二叉树中比较容易想到的问题了,直接使用递归就行了,代码如下: class Solution(object): def constructMaximumBinaryTree(self, nums): """ :type nums: List[int] :rtype: TreeNode """ if not nums: return No…

题目如下: We are given the root node of a maximum tree: a tree where every node has a value greater than any other value in its subtree. Just as in the previous problem, the given tree was constructed from an list A (root = Construct(A)) recursively with…

https://leetcode.com/problems/maximum-binary-tree-ii/ 在654. Maximum Binary Tree版本的建树基础上,在最后插入一个数. 新节点要么为根节点,原树为其左子树:要么将新节点插在右子树中. class Solution { public: TreeNode* insertIntoMaxTree(TreeNode* root, int val) { if(root == NULL) { root = new TreeNode(v…

Leetcode之分治法专题-654. 最大二叉树(Maximum Binary Tree) 给定一个不含重复元素的整数数组.一个以此数组构建的最大二叉树定义如下: 二叉树的根是数组中的最大元素. 左子树是通过数组中最大值左边部分构造出的最大二叉树. 右子树是通过数组中最大值右边部分构造出的最大二叉树. 通过给定的数组构建最大二叉树,并且输出这个树的根节点. 示例 : 输入:[3,2,1,6,0,5] 输出:返回下面这棵树的根节点: 6 / \ 3 5 \ / 2 0 \ 1 提示: 给定的数组…

Given n points on a 2D plane, find the maximum number of points that lie on the same straight line. Example Given 4 points: (1,2), (3,6), (0,0), (1,3). The maximum number is 3. LeeCode上的原题,可参见我之前的博客Invert Binary Tree 翻转二叉树. 解法一: // Recursion class So…

Maximum Binary Tree 题解 原创文章,拒绝转载 题目来源:https://leetcode.com/problems/maximum-binary-tree/description/ Description Given an integer array with no duplicates. A maximum tree building on this array is defined as follow: The root is the maximum number in…

[104-Maximum Depth of Binary Tree(二叉树的最大深度)] [LeetCode-面试算法经典-Java实现][全部题目文件夹索引] 原题 Given a binary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. 题目大意 给…

遍历二叉树   traversing binary tree 线索二叉树 threaded binary tree 线索链表 线索化 1. 二叉树3个基本单元组成:根节点.左子树.右子树 以L.D.R分别表示遍历左子树.访问根节点.遍历右子树 可能的情况6种 排列A3 2 LDR LRD DLR DRL RLD RDL 若限定先左后右 LDR LRD  中根序遍历  后根序遍历 DLR  先根序遍历 先/中/后 序遍历…

Given a binary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. 分析:求二叉树的最大深度 解法一:很容易想到的便是递归(深度优先搜索) (1)如果根节点是空,则返回0:否则转到(2) (2)  l = 左子树的最大深度; r = 右子树的最大深…

Given a binary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. 题目标签:Tree 这道题目给了我们一个二叉树,要我们找到最大深度,就是从root点到最深的那个点之间点的数量.利用post order 来遍历二叉树,对于每一个点,它的两个chi…

Given an integer array with no duplicates. A maximum tree building on this array is defined as follow: The root is the maximum number in the array. The left subtree is the maximum tree constructed from left part subarray divided by the maximum number…

Given a binary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. 求二叉树深度,直接看代码: /** * Definition for a binary tree node. * struct TreeNode { * int val; * Tr…

We are given the root node of a maximum tree: a tree where every node has a value greater than any other value in its subtree. Just as in the previous problem, the given tree was constructed from an list A (root = Construct(A)) recursively with the f…

求二叉树的最大深度 /** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { public: int maxDepth(TreeNode* root) { int l,r; ; l…

Given a binary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. 思路:非常基础的一个题.DFS就可以.代码例如以下: /** * Definition for a binary tree node. * public class TreeNod…

Given a binary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. Note: A leaf is a node with no children. Example: Given binary tree [3,9,20,null,null,15,7…

来源:https://leetcode.com/problems/maximum-depth-of-binary-tree Given a binary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. 1. 深度遍历,递归 Java /** * Defini…

Given a binary tree, find all leaves and then remove those leaves. Then repeat the previous steps until the tree is empty. Example: Given binary tree 1 / \ 2 3 / \ 4 5 Returns [4, 5, 3], [2], [1]. Explanation: 1. Remove the leaves [4, 5, 3] from the…

Given a binary tree, find all leaves and then remove those leaves. Then repeat the previous steps until the tree is empty. Example:Given binary tree 1 / \ 2 3 / \ 4 5 Returns [4, 5, 3], [2], [1]. Explanation: 1. Remove the leaves [4, 5, 3] from the t…

One way to serialize a binary tree is to use pre-oder traversal. When we encounter a non-null node, we record the node's value. If it is a null node, we record using a sentinel value such as #. _9_ / \ 3 2 / \ / \ 4 1 # 6 / \ / \ / \ # # # # # # For…