Given an array and a value, remove all instances of that value in-place and return the new length. Do not allocate extra space for another array, you must do this by modifying the input array in-place with O(1) extra memory. The order of elements can…

Given an array and a value, remove all instances of that value in place and return the new length. Do not allocate extra space for another array, you must do this in place with constant memory. The order of elements can be changed. It doesn't matter…

题目链接: https://leetcode.com/problems/remove-element/?tab=Description   Problem : 移除数组中给定target的元素,返回剩余数组中元素个数   首先对数组进行排序,之后对数组进行遍历操作 当遇到不等于val的值是对下标i进行++操作.   参考代码:  package leetcode_50; import java.util.Arrays; /*** * * @author pengfei_zheng * 移除数组中…

题目描述 给定一个大小为 n 的数组,找到其中的众数.众数是指在数组中出现次数大于 ⌊ n/2 ⌋ 的元素. 你可以假设数组是非空的,并且给定的数组总是存在众数. 示例 1: 输入: [3,2,3] 输出: 3 示例 2: 输入: [2,2,1,1,1,2,2] 输出: 2 思路 思路一: 利用哈希表的映射,储存数组中的数字以及它们出现的次数,当众数出现时,返回这个数字. 思路二: 因为众数是出现次数大于n/2的数字,所以排序之后中间的那个数字一定是众数.即nums[n/2]为众数.但是在计算比…

Remove Element Given an array and a value, remove all instances of that value in place and return the new length. The order of elements can be changed. It doesn't matter what you leave beyond the new length. 思路:此题和26题一脉相承,算法上不难,详细如代码所看到的: public clas…

1. 原题链接 https://leetcode.com/problems/remove-element/description/ 2. 题目要求 给定一个整数数组 nums[ ] 和一个整数 val,删除数组中与val相同的元素,并返回删除后的数组长度 注意:不能定义新的数组,只能使用O(1)空间大小 3. 解题思路 遍历一次,将每个元素与给定的value进行比较,不同则给nums[count++]赋予当前元素的值:相同则直接跳过,最后返回count,即为删除后数组的长度. 4. 代码实现 p…

Given an array and a value, remove all instances of that value in place and return the new length. The order of elements can be changed. It doesn't matter what you leave beyond the new length. 思路: s记录下一个判断位置, e记录结束位置,把前面的待排除元素与后面要保留的元素互换. int removeE…

Given an array nums and a value val, remove all instances of that value in-place and return the new length. Do not allocate extra space for another array, you must do this by modifying the input array in-place with O(1) extra memory. The order of ele…

Problem: Given an array and a value, remove all instances of that value in place and return the new length. Do not allocate extra space for another array, you must do this in place with constant memory. The order of elements can be changed. It doesn'…

和remove zero类似的方法完成该题 class Solution { public: int removeElement(vector<int>& nums, int val) { vector<; ; i < nums.size(); ++i){ if(nums[i] != val) nums[j++] = nums[i]; } return j; } };…