1089 Insert or Merge (25分)】的更多相关文章

PAT甲级:1089 Insert or Merge (25分) 题干 According to Wikipedia: Insertion sort iterates, consuming one input element each repetition, and growing a sorted output list. Each iteration, insertion sort removes one element from the input data, finds the loca…
According to Wikipedia: Insertion sort iterates, consuming one input element each repetition, and growing a sorted output list. Each iteration, insertion sort removes one element from the input data, finds the location it belongs within the sorted li…
题意: 输入一个正整数N(<=100),接着输入两行N个整数,第一行表示初始序列,第二行表示经过一定程度的排序后的序列.输出这个序列是由插入排序或者归并排序得到的,并且下一行输出经过再一次排序操作所得到的序列.数据保证了不会有两种排序方式都可以得到的序列. AAAAAccepted code: #define HAVE_STRUCT_TIMESPEC #include<bits/stdc++.h> using namespace std; ]; ]; int main(){ ios::s…
According to Wikipedia: Insertion sort iterates, consuming one input element each repetition, and growing a sorted output list. Each iteration, insertion sort removes one element from the input data, finds the location it belongs within the sorted li…
题目地址 https://pta.patest.cn/pta/test/16/exam/4/question/675 5-13 Insert or Merge   (25分) According to Wikipedia: Insertion sort iterates, consuming one input element each repetition, and growing a sorted output list. Each iteration, insertion sort rem…
According to Wikipedia: Insertion sort iterates, consuming one input element each repetition, and growing a sorted output list. Each iteration, insertion sort removes one element from the input data, finds the location it belongs within the sorted li…
题目如下: According to Wikipedia: Insertion sort iterates, consuming one input element each repetition, and growing a sorted output list. Each iteration, insertion sort removes one element from the input data, finds the location it belongs within the sor…
判断插入排序很好判断,不是的话那就是归并排序了. 由于归并排序区间是2.4.8开始递增的,所以要判断给出的归并排序执行到哪一步,就要k从2开始枚举. 然后再对每个子区间进行一下sort即可. #include <iostream> #include <cstdio> #include <algorithm> #include <string.h> #include <cmath> using namespace std; ; int num1[m…
简单题.模拟一下即可. #include<cstdio> #include<cstring> #include<cmath> #include<vector> #include<map> #include<queue> #include<stack> #include<algorithm> using namespace std; ; int a[maxn],b[maxn],n; int main() { sc…
一.技术总结 看到是一个two pointers问题,核心是要理解插入排序和归并排序的实现原理,然后判断最后实现 可以知道a数组和b数组怎么样判断是插入排序还是归并排序,因为插入排序是来一个排一个,所以知道当发现有位置当前数比后面大时,进而再判断后面的每一位是否啊a.b数组都相等,如果是那么就是插入排序,再在后面进行一轮排序即可.如果不是就是归并排序.最主要的问题是判断归并排序到哪一轮了,使用while循环模拟归并排序,对数组a进行归并排序,直到与数组b相等,再进行一轮排序就是输出结果了. 二.…