You are given an integer x. Your task is to split the number x into exactly n strictly positive integers such that the difference between the largest and smallest integer among them is as minimal as possible. Can you? Input The first line contains an…

题目描述: time limit per test 2 seconds memory limit per test 512 megabytes input standard input output standard output Dima worked all day and wrote down on a long paper strip his favorite number n consisting of l digits. Unfortunately, the strip turned…

B. Split a Number time limit per test2 seconds memory limit per test512 megabytes inputstandard input outputstandard output Dima worked all day and wrote down on a long paper strip his favorite number n consisting of l digits. Unfortunately, the stri…

Dima worked all day and wrote down on a long paper strip his favorite number nn consisting of ll digits. Unfortunately, the strip turned out to be so long that it didn't fit in the Dima's bookshelf. To solve the issue, Dima decided to split the strip…

Split a Number time limit per test 2 seconds memory limit per test 512 megabytes input standard input output standard output Dima worked all day and wrote down on a long paper strip his favorite number nn consisting of ll digits. Unfortunately, the s…

https://codeforces.com/contest/1181/problem/B 从中间拆开然后用大数搞一波. 当时没想清楚奇偶是怎么弄,其实都可以,奇数长度字符串的中心就在len/2,偶数长度字符串的中心恰好是len/2和len/2-1. 但是要是作为末尾指针的位置来说的话 奇数长度字符串:把中心分给后半串,那么分割点是len/2.把中心分给前半串,那么分割点是len/2+1. 偶数长度字符串:分割点是len/2. 注意子串的取法,其实最方便的还是传头尾指针进去. #include<…

题目传送门 题意: 输入一个只包含数字的字符串,求出是300的倍数的子串的个数(不同位置的0.00.000等都算,并考虑前导零的情况). sample input: 600 123000321013200987000789 sample output: 4 55 题解: O(n)做法:遍历一遍,求前缀和sum取余3,统计sum的个数num[sum],遇到本位和下一位都是0,则把之前统计的个数加上,最后加上单独0的个数. O(300n)DP做法:如下 官方题解: Code: O(n)做法如下: /…

pro:给定N个数的数组a[],其中一个数X的出现次数大于N/2,求X,空间很小. sol:不能用保存数组,考虑其他做法. 由于出现次数较多,我们维护一个栈,栈中的数字相同,所以我们记录栈的元素和个数即可,如果新加入一个数与栈中数不同,则弹出一个元素(tot--),否则加入,最后保留在栈中的就是答案. #include<bits/stdc++.h> #define rep(i,a,b) for(int i=a;i<=b;i++) using namespace std; int D,to…

使用 webpack 编译 Vue 项目时出现报错: index.js:13 Uncaught TypeError: Cannot read property 'split' of undefined 定位错误到事发代码行: version = Vue.version.split('.').map(Number) 这行代码是`vue-hot-reload-api`中的,查阅其官方(说明)[https://github.com/vuejs/vue-hot-reload-api#vue-hot-re…

命令形式: split(str='',number=string.count(str))[n] str 分隔符 number 切分几次,[n] 获取第几个值. 1.如果切分的可迭代对象中包含空元素的解决方法: split() # 不加参数的时候,它会把空格 制表符 换行符都当做为分隔符. l = 'ni hao ma wo shi shui ' print(l) print(l.split()) >>> l='ni hao ma wo shi shui ' >>> l.…