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1096 Consecutive Factors (20 分) Among all the factors of a positive integer N, there may exist several consecutive numbers. For example, 630 can be factored as 3×5×6×7, where 5, 6, and 7 are the three consecutive numbers. Now given any positive N, yo…
本文同步发布在CSDN:https://blog.csdn.net/weixin_44385565/article/details/91349859 1096 Consecutive Factors (20 分)   Among all the factors of a positive integer N, there may exist several consecutive numbers. For example, 630 can be factored as 3×5×6×7, wher…
http://www.patest.cn/contests/pat-a-practise/1096 Among all the factors of a positive integer N, there may exist several consecutive numbers. For example, 630 can be factored as 3*5*6*7, where 5, 6, and 7 are the three consecutive numbers. Now given…
Among all the factors of a positive integer N, there may exist several consecutive numbers. For example, 630 can be factored as 3*5*6*7, where 5, 6, and 7 are the three consecutive numbers. Now given any positive N, you are supposed to find the maxim…
https://pintia.cn/problem-sets/994805342720868352/problems/994805370650738688 Among all the factors of a positive integer N, there may exist several consecutive numbers. For example, 630 can be factored as 3×5×6×7, where 5, 6, and 7 are the three con…
Among all the factors of a positive integer N, there may exist several consecutive numbers. For example, 630 can be factored as 356*7, where 5, 6, and 7 are the three consecutive numbers. Now given any positive N, you are supposed to find the maximum…
题目 Among all the factors of a positive integer N, there may exist several consecutive numbers. For example, 630 can be factored as 3*5*6*7, where 5, 6, and 7 are the three consecutive numbers. Now given any positive N, you are supposed to find the ma…
如果是素数直接输出1与素数,否则枚举长度和起始数即可. #include<cstdio> #include<cstring> #include<cmath> #include<vector> #include<map> #include<queue> #include<stack> #include<algorithm> using namespace std; long long n; bool prime(…
题意:一个正整数n可以分解成一系列因子的乘积,其中会存在连续的因子相乘,如630=3*5*6*7,5*6*7即为连续的因子.给定n,让你求最大的连续因子个数,并且输出其中最小的连续序列. 比如一个数可以分解2*3*4*6*7*8,最大的连续个数为3,因为存在两个,输出最小的那个即2*3*4. 首先,一个数如果是合数,那么它的因子必定不会超过sqrt(n)或者sqrt(n)+1.如果为质数,那么只可能为自己,因为题目说了不包括1. 我们先将2~sqrt(n)+1中为n的因子存到factor数组中,…
题意: 给出一个正整数N,找到最长的连续的可分解因子.如N=630,可被分解为630=3*5*6*7,其中5*6*7是3个连续的因子. 思路: 首先,需要明确,对于任何一个整数,如果它是素数,则不可被分解,因子只有1和其本身:如果它是合数,则除了1和本身之外,它的因子必然是在sqrt(n)两侧成对出现的,此时,这些质因子要么全部小于等于sqrt(n):要么只存在一个质因子大于sqrt(n),而其他质因子全部小于sqrt(n).因此我们只需要考虑2~sqrt(N)的范围即可.对于每一个i∈[2,s…