Look-and-say sequence is a sequence of integers as the following: D, D1, D111, D113, D11231, D112213111, ... where D is in [0, 9] except 1. The (n+1)st number is a kind of description of the nth number. For example, the 2nd number means that there is…

Look-and-say sequence is a sequence of integers as the following: D, D1, D111, D113, D11231, D112213111, ... where D is in [0, 9] except 1. The (n+1)st number is a kind of description of the nth number. For example, the 2nd number means that there is…

1140 Look-and-say Sequence(20 分)Look-and-say sequence is a sequence of integers as the following: D, D1, D111, D113, D11231, D112213111, ... where D is in [0, 9] except 1. The (n+1)st number is a kind of description of the nth number. For example, th…

1116 Come on! Let's C (20 分) "Let's C" is a popular and fun programming contest hosted by the College of Computer Science and Technology, Zhejiang University. Since the idea of the contest is for fun, the award rules are funny as the following:…

1116 Come on! Let's C(20 分) "Let's C" is a popular and fun programming contest hosted by the College of Computer Science and Technology, Zhejiang University. Since the idea of the contest is for fun, the award rules are funny as the following: 0…

PAT甲级:1136 A Delayed Palindrome (20分) 题干 Look-and-say sequence is a sequence of integers as the following: D, D1, D111, D113, D11231, D112213111, ... where D is in [0, 9] except 1. The (n+1)st number is a kind of description of the nth number. For ex…

Poiuyt_cyc 博客园首页新随笔联系订阅管理随笔 - 11  文章 - 0  评论 - 111 抛弃EF,20分构建一个属于自己的ORM框架 相信EF大家都不陌生了,因为数据库表跟程序实体是一一对应的原因,我们能够通过lambda这种函数式的编程方式进行操作数据库,感觉非常清晰明了.与我们直接写SQL相比,lambda是强类型,拥有更好的扩展性,伸缩性,而且编程更加的方便,快捷..下面我们就基于Expression和lambda来与大家构建一个属于自己的ORM框架. 思路的话很简单,就是将…

6-2 邻接表存储图的广度优先遍历(20 分) 试实现邻接表存储图的广度优先遍历. 函数接口定义: void BFS ( LGraph Graph, Vertex S, void (*Visit)(Vertex) ); 其中LGraph是邻接表存储的图,定义如下: /* 邻接点的定义 */ typedef struct AdjVNode *PtrToAdjVNode; struct AdjVNode{ Vertex AdjV; /* 邻接点下标 */ PtrToAdjVNode Next; /*…

后面的测试点过不去,两个错误一个超时. 目前未解决   L1-009 N个数求和 (20 分)   本题的要求很简单,就是求N个数字的和.麻烦的是,这些数字是以有理数分子/分母的形式给出的,你输出的和也必须是有理数的形式. 输入格式: 输入第一行给出一个正整数N(≤100).随后一行按格式a1/b1 a2/b2 ...给出N个有理数.题目保证所有分子和分母都在长整型范围内.另外,负数的符号一定出现在分子前面. 输出格式: 输出上述数字和的最简形式 —— 即将结果写成整数部分 分数部分,其中分数部…

L1-023 输出GPLT (20 分) 给定一个长度不超过10000的.仅由英文字母构成的字符串.请将字符重新调整顺序,按GPLTGPLT....这样的顺序输出,并忽略其它字符.当然,四种字符(不区分大小写)的个数不一定是一样多的,若某种字符已经输出完,则余下的字符仍按GPLT的顺序打印,直到所有字符都被输出. 输入格式: 输入在一行中给出一个长度不超过10000的.仅由英文字母构成的非空字符串. 输出格式: 在一行中按题目要求输出排序后的字符串.题目保证输出非空. 输入样例: pcTclnG…