Solve a given equation and return the value of x in the form of string "x=#value". The equation contains only '+', '-' operation, the variable x and its coefficient. If there is no solution for the equation, return "No solution". If th…

Can you solve this equation? Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 25633    Accepted Submission(s): 11018 Problem Description Now,given the equation 8*x^4 + 7*x^3 + 2*x^2 + 3*x + 6 ==…

[LeetCode]640. Solve the Equation 解题报告(Python) 标签(空格分隔): LeetCode 作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.me/ 题目地址:https://leetcode.com/problems/solve-the-equation/description/ 题目描述: Solve a given equation and return the value of x in the…

题目如下: 解题思路:本题的思路就是解析字符串,然后是小学时候学的解方程的思想,以"2x+3x-6x+1=x+2",先把左右两边的x项和非x项进行合并,得到"-x+1=x+2",接下来就是移项,把x项移到左边,常数项移到右边,得到"2x=-1",最后的解就是x=-1/2.对于任意一个表达式ax+b = cx+d来说,最终都能得到解x=(d-b)/(a-c),这里要对(a-c)是否为0做判断,同时根据(d-b)是否为0等到Infinite solu…

传送门: http://acm.hdu.edu.cn/showproblem.php?pid=2199 Can you solve this equation? Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 25039    Accepted Submission(s): 10776 Problem Description Now,gi…

[怪毛匠子=整理] SymPy 库 安装 sudo pip install sympy x = Symbol('x') 解方程 solve([2 * x - y - 3, 3 * x + y - 7],[x, y]) 求极限 limit(x*(sqrt(x**2 + 1) - x), x, oo) oo 无穷大(标识方式是两个小写字母o连接在一起) E e pi 圆周率 integrate函数用于积分问题 求导 diff(f(x),x) 及多阶求导 >>> diff(x**3,x) 3*…

Can you solve this equation? Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 27728    Accepted Submission(s): 11717 Problem Description Now,given the equation 8*x^4 + 7*x^3 + 2*x^2 + 3*x + 6 ==…

解方程  时间限制: 1 s  空间限制: 128000 KB  题目等级 : 钻石 Diamond       题目描述 Description 输入描述 Input Description 输入文件名为equation.in. 输入共n+2行. 第一行包含2个整数n.m,每两个整数之间用一个空格隔开. 接下来的n+1行每行包含一个整数,依次为a0,a1,a2,……,an. 输出描述 Output Description 输出文件名为equation.out. 第一行输出方程在[1, m]内的…

解题思路:给出一个方程 8*x^4 + 7*x^3 + 2*x^2 + 3*x + 6 == Y,求方程的解. 首先判断方程是否有解,因为该函数在实数范围内是连续的,所以只需使y的值满足f(0)<=y<=f(100),就一定能找到该方程的解,否则就无解. 然后是求解过程, 假设一个区间[a,b],mid=(a+b)/2,如果f(a)*f(b)<0,那么函数f(x)在区间[a,b]至少存在一个零点,如果f(a)<0,说明0点在其右侧,那么将a的值更新为当前mid的值,如果f(a)&g…

Can you solve this equation? Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 7493    Accepted Submission(s): 3484 Problem Description Now,given the equation 8*x^4 + 7*x^3 + 2*x^2 + 3*x + 6 == Y,…