https://vjudge.net/problem/CodeForces-510D题目可以转化为花最小代价选一些数,然后这些数可以经过加减运算得到1或-1,不然1你就凑不出来,一旦凑出来1,其他的都有了.由贝祖定理,ax+by=gcd(a,b)=1,贝祖定理能推广到n个,ax+by+cz+…=gcd(a,b,c,…).令m[i]为得到的gcd为i的最小代价,spfa暴力更新,最后输出m[1] #include <iostream> #include <cstdio> #inclu…

Fox And Jumping CodeForces - 510D Fox Ciel is playing a game. In this game there is an infinite long tape with cells indexed by integers (positive, negative and zero). At the beginning she is standing at the cell 0. There are also n cards, each card…