CF293B Distinct Paths 题意 给定一个\(n\times m\)的矩形色板,有kk种不同的颜料,有些格子已经填上了某种颜色,现在需要将其他格子也填上颜色,使得从左上角到右下角的任意路径经过的格子都不会出现两种及以上相同的颜色.路径只能沿着相邻的格子,且只能向下或者向右. 计算所有可能的方案,结果对 \(1000000007 (10^9 + 7)\) 输入及输出格式 输入格式 第一行,三个整数$ n, m, k (1 \le n, m \le 1000, 1 \le k \le…
B. Distinct Paths time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output You have a rectangular n × m-cell board. Some cells are already painted some of k colors. You need to paint each uncolored…
[codeforces 293]B. Distinct Paths 试题描述 You have a rectangular n × m-cell board. Some cells are already painted some of k colors. You need to paint each uncolored cell one of the k colors so that any path from the upper left square to the lower right…
Unique Paths 题解 原创文章,拒绝转载 题目来源:https://leetcode.com/problems/unique-paths/description/ Description A robot is located at the top-left corner of a m x n grid (marked 'Start' in the diagram below). The robot can only move either down or right at any po…
Problem A. Two distinct points [题解] 显然 , 当l1不等于r2时 , (l1 , r2)是一组解 否则 , (l1 , l2)是一组合法的解 时间复杂度 : O(1) [代码] #include<bits/stdc++.h> using namespace std; typedef long long ll; typedef long double ld; typedef unsigned long long ull; template <typena…
E. Berland Local Positioning System Time Limit: 1 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/534/problem/E Description In Berland a bus travels along the main street of the capital. The street begins from the main square and looks l…
Problem FPaths through the HourglassInput: Standard Input Output: Standard Output Time Limit: 2 Seconds In the hourglass to the right a path is marked. A path always starts at the first row and ends at the last row. Each cell in the path (except the…
What is Arrow Functor? Arrow is a Profunctor that lifts a function of type a -> b and allows for lazy execution of the function. Arrow can be considered a Strong Profunctorif the underlying data running through the Arrow is a Pair, typically in the f…
Go 1.4 Release Notes Introduction to Go 1.4 Changes to the language For-range loops Method calls on **T Changes to the supported operating systems and architectures Android NaCl on ARM Plan9 on AMD64 Changes to the compatibility guidelines Changes to…
题目: Follow up for N-Queens problem. Now, instead outputting board configurations, return the total number of distinct solutions. 题解: 这道题跟NQueens的解法完全一样(具体解法参照N QueensN Queens leetcode java),只不过要求的返回值不同了..所以要记录的result稍微改一下就好了... 因为涉及到递归,result传进去引用类型(…
Follow up for N-Queens problem. Now, instead outputting board configurations, return the total number of distinct solutions. 题解:参见http://www.cnblogs.com/sunshineatnoon/p/3853170.html 只要求求出解的个数,稍微改一下代码就可以了:用私有变量result记录解的数目,当搜索到一个解的时候,result+1即可. 代码如下…
题目: Follow up for N-Queens problem. Now, instead outputting board configurations, return the total number of distinct solutions. Example For n=4, there are 2 distinct solutions. 题解: Solution 1 () class Solution { public: void dfs(int &res, int n, vec…
二叉树基础 满足这样性质的树称为二叉树:空树或节点最多有两个子树,称为左子树.右子树, 左右子树节点同样最多有两个子树. 二叉树是递归定义的,因而常用递归/DFS的思想处理二叉树相关问题,例如LeetCode题目 104. Maximum Depth of Binary Tree: // 104. Maximum Depth of Binary Tree int maxDepth(TreeNode* root) { ; +max(maxDepth(root->left),maxDepth(roo…
