Code froces 831 A. Unimodal Array】的更多相关文章

A. Unimodal Array time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Array of integers is unimodal, if: it is strictly increasing in the beginning; after that it is constant; after that it is…
A. Unimodal Array time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Array of integers is unimodal, if: it is strictly increasing in the beginning; after that it is constant; after that it is…
A. Unimodal Array time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Array of integers is unimodal, if: it is strictly increasing in the beginning; after that it is constant; after that it is…
[Link]:http://codeforces.com/contest/831/problem/A [Description] 让你判断一个数列是不是这样一个数列: 一开始是严格上升 然后开始全都是一个数字 然后又开始严格下降 [Solution] 枚举中间全部相同的是哪个数字; 假设是i..j这一段 则看看1..i是不是严格上升,以及j+1..n是不是严格下降; 如果所有的这样的i..j都不满足则无解; 找到一组则有解; [NumberOf WA] 0 [Reviw] 找到最特殊的地方: 抓…
Array of integers is unimodal, if: it is strictly increasing in the beginning; after that it is constant; after that it is strictly decreasing. The first block (increasing) and the last block (decreasing) may be absent. It is allowed that both of thi…
http://codeforces.com/contest/831 A. Unimodal Array time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Array of integers is unimodal, if: it is strictly increasing in the beginning; after that…
std::array template < class T, size_t N > class array; Code Example #include <iostream> #include <array> #include <cstring> using namespace std; int main(int argc, char **argv) { array<int, 5> intArr = {1,2,3,4,5}; for(auto i…
Array.prototype.slice.call(document.querySelectorAll('a'), 0)的作用就是将一个DOM NodeList 转换成一个数组. slice()方法可提取字符串的某个部分,并以新的字符串返回被提取的部分.语法为arr.slice([begin[, end]]),其中arr可为string或Array.更多了解可以参考MDN document.querySelectorAll('a')获取了一个NodeList对象,它看起来像一个数组,你可以使用…
1. Introduction. 1.1 In part 1 of this series of blogs we studied how to pass a managed structure (which contains strings) to unmanaged code. The structure was passed as an "in" (by-value) parameter, i.e. the structure was passed to the unmanage…
1. Introduction. 1.1 In part 1 of this series of blogs we studied how to pass a managed structure (which contains strings) to unmanaged code. The structure was passed as an "in" (by-value) parameter, i.e. the structure was passed to the unmanage…