题目 有n(n<=30)种立方体,每种有无穷多个,摞成尽量高的柱子,要求上面的立方体要严格小于下面的立方体. 原题链接 分析 顶面的大小会影响后续的决策,但不能直接用d[a][b]来表示,因为可能有多个立方体长宽相等,因此用d[i][j](i<n,j<3)表示第i个立方体的第j条边,为了方便比较大小,边按照从小大到排序. 每增加一个立方体后顶面的长宽都会严格减小,因此是一个DAG图上的最长路问题. AC代码 #include "bits/stdc++.h" using…

UVA437 The Tower of Babylon 题解 初始时给了 \(n\) 种长方体方块,每种有无限个,对于每一个方块,我们可以选择一面作为底.然后用这些方块尽可能高地堆叠成一个塔,要求只有一个方块的底的两条边严格小于另一个方块的底的两条边,这个方块才能堆在另一个上面. 问题的思考在于每种方块有无限个,如果我们直接利用该条件问题会变得比较复杂.其实仔细考虑方块堆叠的要求,会发现这是一个约束很强的条件. 注意到,方块堆叠的要求描述的对象不只是方块本身,更细地说,它应该描述的是方块摆放方式…

 The Tower of Babylon  Perhaps you have heard of the legend of the Tower of Babylon. Nowadays many details of this tale have been forgotten. So now, in line with the educational nature of this contest, we will tell you the whole story: The babylonian…

https://odzkskevi.qnssl.com/5e1fdf8cae5d11a8f572bae96d6095c0?v=1507521965 Perhaps you have heard of the legend of the Tower of Babylon. Nowadays many details of this tale have been forgotten. So now, in line with the educational nature of this contes…

传送门 Description Input Output Sample Input Sample Output Case : maximum height = Case : maximum height = Case : maximum height = Case : maximum height = Hint n<=30. Solution 一眼看出这是个DAG上的DP,一个信息分成三个方块存储.然后开始读入,拓扑,输出,过样例,提交,WA…… 这里的关键是拓扑序应该怎么求.首先我的比较函数写…

据说是DAG的dp,可用spfa来做,松弛操作改成变长.注意状态的表示. 影响决策的只有顶部的尺寸,因为尺寸可能很大,所以用立方体的编号和高的编号来表示,然后向尺寸更小的转移就行了. #include<bits/stdc++.h> using namespace std; #define MP make_pair #define fi first #define se second typedef pair<int,int> pii; ; ]; ]; ]; ][]; int mai…

题意:有n(n≤30)种立方体,每种有无穷多个.要求选一些立方体摞成一根尽量高的柱子(可以自行选择哪一条边作为高),使得每个立方体的底面长宽分别严格小于它下方立方体的底面长宽. 评测地址:http://acm.hust.edu.cn/vjudge/problem/19214 AC代码: #include<cstdio> #include<cstring> #include<algorithm> using namespace std; #define N 50010 i…

传送门 Description Perhaps you have heard of the legend of the Tower of Babylon. Nowadays many details of this tale have been forgotten. So now, in line with the educational nature of this contest, we will tell you the whole story: The babylonians had n…

题目:The Tower of Babylon 这是一个DAG 模型,有两种常规解法 1.记忆化搜索, 写函数,去查找上一个符合的值,不断递归 2.递推法 方法一:记忆化搜索 #include <iostream> #include <cstdio> #include <cstdlib> #include <cstring> #include <algorithm> using namespace std; struct node { int x…

转自:https://mp.weixin.qq.com/s/oZVj8lxJH6ZqL4sGCXuxMw The Tower of Babylon(巴比伦塔) Perhaps you have heard of the legend of the Tower of Babylon. Nowadays many details of this tale have been forgotten. So now, in line with the educational nature of this…