题目链接:https://vjudge.net/contest/210334#problem/B 题目大意:Given a sequence of integers S = {S1, S2, . . . , Sn}, you should determine what is the value of the maximum positive product involving consecutive terms of S. If you cannot find a positive sequen…

[题意]:乘积最大的子序列.n∈[1,10],s∈[-10,10] [代码]: #include<bits/stdc++.h> using namespace std; int a[105]; #define LL long long int main() { int n,f=0; LL s,ma; while(~scanf("%d",&n)) { f++; ma=0; for(int i=0;i<n;i++) scanf("%d",&am…

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注意long long  long long  longlong !!!!!!   还有 printf的时候 明明longlong型的答案 用了%d  WA了也看不出,这个细节要注意!!! #include <cstdio> ]; int main() { ;long long ans,sum; while(~scanf("%d",&n)) { ;i<n;i++) scanf("%d",&a[i]); ans=; ;i<n;i…

UVA.10305 Maximum Product (暴力) 题意分析 直接枚举起点和重点,然后算出来存到数组里面,sort然后取最大值即可. 代码总览 #include <iostream> #include <iostream> #include <cstdio> #include <algorithm> #include <cstring> #include <sstream> #include <set> #inc…

找出一个序列中乘积最大的连续子序列(该序列至少包含一个数).例如, 给定序列 [2,3,-2,4],其中乘积最大的子序列为 [2,3] 其乘积为 6.详见:https://leetcode.com/problems/maximum-product-subarray/description/ Java实现: 方法一: 用两个dp数组,其中f[i]表示子数组[0, i]范围内并且一定包含nums[i]数字的最大子数组乘积,g[i]表示子数组[0, i]范围内并且一定包含nums[i]数字的最小子数组…

给定一个整数数组 nums ,找出一个序列中乘积最大的连续子序列(该序列至少包含一个数). 示例 1: 输入: [2,3,-2,4] 输出: 6 解释: 子数组 [2,3] 有最大乘积 6. 示例 2: 输入: [-2,0,-1] 输出: 0 解释: 结果不能为 2, 因为 [-2,-1] 不是子数组. 维护三个变量:局部最大值,局部最小值,总最大值 class Solution { public: int maxProduct(vector<int>& nums) { int len…

最大乘积 Maximum Product 题目链接:http://acm.hust.edu.cn/vjudge/contest/view.action?cid=84562#problem/B 解题思路: 题目意思是输入n个元素组成的序列S,找出一个乘积最大的连续子序列.若这个数不是正数,则输出0(表示无解).分析 ,连续子序列有两个要素:起点和终点,因此只需要枚举起点和终点即可.分析最大可能的乘积不会超过10的18次方,所以用 long long 来存储即可. 程序代码: #include <c…

Problem D - Maximum Product Time Limit: 1 second Given a sequence of integers S = {S1, S2, ..., Sn}, you should determine what is the value of the maximum positive product involving consecutive terms ofS. If you cannot find a positive sequence, you s…

Given a sequence of integers S = {S1, S2, . . . , Sn}, you should determine what is the value of themaximum positive product involving consecutive terms of S. If you cannot find a positive sequence,you should consider 0 as the value of the maximum pr…