网址:https://leetcode.com/problems/coin-change/ 典型的动态规划问题,类比背包问题,这就是完全背包问题 问题的阶段:对数值 i 凑硬币 问题的状态:对数值 i 凑硬币,使得硬币数最少 问题的决策:第 j 枚硬币使用还是不使用 class Solution { public: int coinChange(vector<int>& coins, int amount) { vector<, amount+); ans[] = ; ; i&l…

给定不同面额的硬币(coins)和一个总金额(amount).写一个函数来计算可以凑成总金额所需的最少的硬币个数.如果没有任何一种硬币组合方式能组成总金额,返回-1.示例 1:coins = [1, 2, 5], amount = 11return 3 (11 = 5 + 5 + 1)示例 2:coins = [2], amount = 3return -1.注意:你可以认为每种硬币的数量是无限的. 详见:https://leetcode.com/problems/coin-change/des…

给定不同面额的硬币 coins 和一个总金额 amount.编写一个函数来计算可以凑成总金额所需的最少的硬币个数.如果没有任何一种硬币组合能组成总金额,返回 -1. 示例 1: 输入: coins = [1, 2, 5], amount = 11 输出: 3 解释: 11 = 5 + 5 + 1 示例 2: 输入: coins = [2], amount = 3 输出: -1 说明: 你可以认为每种硬币的数量是无限的. 动态规划 class Solution { public: int coin…

题目链接:https://leetcode.com/problems/coin-change/ 322. Coin Change My Submissions Question Total Accepted: 15289 Total Submissions: 62250 Difficulty: Medium You are given coins of different denominations and a total amount of money amount. Write a func…

You are given coins of different denominations and a total amount of money amount. Write a function to compute the fewest number of coins that you need to make up that amount. If that amount of money cannot be made up by any combination of the coins,…

https://leetcode.com/problems/coin-change/ You are given coins of different denominations and a total amount of money amount. Write a function to compute the fewest number of coins that you need to make up that amount. If that amount of money cannot…

动态规划里例题,硬币问题. p[i] = dp[i - coin[j]] + 1; 注意i < coin[j] dp[i-coin[j]]无解都要跳过. public class Solution { public int coinChange(int[] coins, int amount) { int[] dp = new int[amount+1]; Arrays.fill(dp,Integer.MAX_VALUE); //dp[i] = dp[i - coin[j]] + 1; dp[0…

原题 You are given coins of different denominations and a total amount of money amount. Write a function to compute the fewest number of coins that you need to make up that amount. If that amount of money cannot be made up by any combination of the coi…

首先需要明白 0-1 背包问题中的放置表格,见 “玩转算法面试 从真题到思维全面提升算法思维” 9-5 节,本题思路类似表格纵向为:只考虑第 [0 …,… index] 种硬币(物品)表格横向为:需要兑换的金额(背包容量)为 j表格内容为:在横向和纵向的条件下,最少的硬币(物品)数即:通过表格列举出,当硬币种类为 [0 …,… index] 种,兑换金额为 j 时,最少的硬币数量 以 Example 1 为例,可以画出下面的表格 Input: coins = [1, 2, 5], amount…

You are given coins of different denominations and a total amount of money amount. Write a function to compute the fewest number of coins that you need to make up that amount. If that amount of money cannot be made up by any combination of the coins,…