题目 There are two sorted arrays nums1 and nums2 of size m and n respectively. Find the median of the two sorted arrays. The overall run time complexity should be O(log (m+n)). 分析 给定两个有序序列,要求两个序列综合后的中位数.关键:算法复杂度T(n)=O(log(m+n)) 该问题的关键就在于复杂度的限制,有了这个限制,就…
题目Median of Two Sorted Arrays(难度Hard) 方案1,数组合并&排序调用Java方法 import java.util.* class Solution { fun findMedianSortedArrays(nums1: IntArray, nums2: IntArray): Double { val lenNums1 = nums1.size val lenNums2 = nums2.size val array = Arrays.copyOf(nums1,…
题目 There are two sorted arrays nums1 and nums2 of size m and n respectively. Find the median of the two sorted arrays. The overall run time complexity should be O(log (m+n)). You may assume nums1 and nums2 cannot be both empty. Example 1: nums1 = [1,…
题目等级:Hard 题目描述: There are two sorted arrays nums1 and nums2 of size m and n respectively. Find the median of the two sorted arrays. The overall run time complexity should be O(log (m+n)). You may assume nums1 and nums2 cannot be both empty. E…
题目:There are two sorted arrays A and B of size m and n respectively. Find the median of the two sorted arrays. The overall run time complexity should be O(log (m+n)). 刚开始的时候理解有误,以为是求中位数.其实不是.这里所谓的"median of the two sorted arrays"指的是:如果A.length +…
There are two sorted arrays nums1 and nums2 of size m and n respectively. Find the median of the two sorted arrays. The overall run time complexity should be O(log (m+n)). Example 1: nums1 = [1, 3] nums2 = [2] The median is 2.0 Example 2: nums1 = [1,…
题目 Given a sorted linked list, delete all duplicates such that each element appear only once. For example, Given 1->1->2, return 1->2. Given 1->1->2->3->3, return 1->2->3. 分析 该题目与LeetCode 83题目类似,都是删除链表中重复元素的题目. 该题目要求只保存不重复的结点! 详…
题目: Given a sorted array, remove the duplicates in place such that each element appear only once and return the new length. Do not allocate extra space for another array, you must do this in place with constant memory. For example, Given input array…
题目 Given a sorted linked list, delete all duplicates such that each element appear only once. For example, Given 1->1->2, return 1->2. Given 1->1->2->3->3, return 1->2->3. 分析 删除链表中反复元素结点. 该题目本质非常easy.仅仅需一次遍历.须要注意的是.要释放删除的结点空间. A…
题目 Follow up for "Remove Duplicates": What if duplicates are allowed at most twice? For example, Given sorted array nums = [1,1,1,2,2,3], Your function should return length = 5, with the first five elements of nums being 1, 1, 2, 2 and 3. It doe…