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http://acm.hdu.edu.cn/showproblem.php?pid=1335 Basically Speaking Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 1885    Accepted Submission(s): 729 Problem Description The Really Neato Calcul…
Basically Speaking Time Limit: 2 Sec  Memory Limit: 200 MB Submit: 19  Solved: 11 [Submit][Status][Web Board] Description The Really Neato Calculator Company, Inc. has recently hired your team to help design their Super Neato Model I calculator. As a…
这道题目不难,是一道简单的进制转换问题,但是发现了自己两个遗漏的知识点: 1.关于scanf (1)scanf函数在输入时是以回车或者空格作为一次输入的结束 (2)scanf函数在输入字符串的过程中是不吸纳空格的,而且如果输入是整数或者浮点数,前面的空格对输入没有影响,如下: ],s2[]; int a,b; scanf("%s%s%d%d",s1,s2,a,b); printf("%s%s%d%d",s1,s2); 如上面这段代码,如果给定输入为:"  …
Problem Description The Really Neato Calculator Company, Inc. has recently hired your team to help design their Super Neato Model I calculator. As a computer scientist you suggested to the company that it would be neato if this new calculator could c…
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1335 Problem Description The Really Neato Calculator Company, Inc. has recently hired your team to help design their Super Neato Model I calculator. As a computer scientist you suggested to the company t…
这道题目还是简单的,但是自己WA了好几次,总结下: 1.对输入的总结,加上上次ZOJ Problem Set - 1334 Basically Speaking ac代码及总结这道题目的总结 题目要求输入的格式: START X Y Z END 这算做一个data set,这样反复,直到遇到ENDINPUT.我们可以先吸纳一个字符串判断其是否为ENDINPUT,若不是进入,获得XYZ后,吸纳END,再进行输出结果 2.注意题目是一个圆周,所以始终用锐角进行计算,即z=360-z; 3.知识点的误…
Log 2016-3-21 网上找的POJ分类,来源已经不清楚了.百度能百度到一大把.贴一份在博客上,鞭策自己刷题,不能偷懒!! 初期: 一.基本算法: (1)枚举. (poj1753,poj2965) (2)贪心(poj1328,poj2109,poj2586) (3)递归和分治法. (4)递推. (5)构造法.(poj3295) (6)模拟法.(poj1068,poj2632,poj1573,poj2993,poj2996) 二.图算法: (1)图的深度优先遍历和广度优先遍历. (2)最短路…
HDU 模拟题, 枚举1002 1004 1013 1015 1017 1020 1022 1029 1031 1033 1034 1035 1036 1037 1039 1042 1047 1048 1049 1050 1057 1062 1063 1064 1070 1073 1075 1082 1083 1084 1088 1106 1107 1113 1117 1119 1128 1129 1144 1148 1157 1161 1170 1172 1177 1197 1200 1201…
初期:一.基本算法:     (1)枚举. (poj1753,poj2965)     (2)贪心(poj1328,poj2109,poj2586)     (3)递归和分治法.     (4)递推.     (5)构造法.(poj3295)     (6)模拟法.(poj1068,poj2632,poj1573,poj2993,poj2996)二.图算法:     (1)图的深度优先遍历和广度优先遍历.     (2)最短路径算法(dijkstra,bellman-ford,floyd,hea…
初期: 一.基本算法:      (1)枚举. (poj1753,poj2965)      (2)贪心(poj1328,poj2109,poj2586)      (3)递归和分治法.      (4)递推.      (5)构造法.(poj3295)      (6)模拟法.(poj1068,poj2632,poj1573,poj2993,poj2996) 二.图算法:      (1)图的深度优先遍历和广度优先遍历.      (2)最短路径算法(dijkstra,bellman-ford…