Mysterious For(hdu4373)】的更多相关文章

Mysterious For Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 694    Accepted Submission(s): 264 Problem Description MatRush is an ACMer from ZJUT, and he always love to create some special pro…
in script,i use HttpWebRequest to get service from network.but it comes a mysterious problem. the source code: string url = "http://apis.baidu.com/apistore/vop/baiduvopjson"; HttpWebRequest request = (HttpWebRequest)WebRequest.Create(url); print…
这个题和求最长递增序列的题类似,为了能输出一组可行的数据,我还用了一点儿链表的知识. Description Peter decided to wish happy birthday to his friend from Australia and send him a card. To make his present more mysterious, he decided to make a chain. Chain here is such a sequence of envelopes …
H. Mysterious Photos Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/gym/100187/problem/H Description Everyone probably heard the rumours about the constellation of Bermuda Triangle: any person who looks to this constellation of th…
描述 GFW had intercepted billions of illegal links successfully. It has much more effect. Today, GFW intercepted a message of a mysterious organization. This mysterious organization package the message in legitimate URL. To find the Black Hand behind t…
D. Mysterious Present time limit per test 2 seconds memory limit per test 64 megabytes input standard input output standard output Peter decided to wish happy birthday to his friend from Australia and send him a card. To make his present more mysteri…
https://www.ted.com/talks/tabetha_boyajian_the_most_mysterious_star_in_the_universe/transcript00:12Extraordinary claims require extraordinary evidence, and it is my job, my responsibility, as an astronomer to remind people that alien hypotheses[haɪˈp…
  一直都觉得Mysterious Town pooka特别好听,但是酷狗音乐和网上直接搜搜不到,于是我直接从源文件中找了出来.虽然是.ogg格式,但是在酷狗音乐里还是可以播放的.貌似是<奥丁领域>的背景音乐,但我没玩过这游戏.   百度网盘链接   提取码: n6jr…
http://lightoj.com/volume_showproblem.php?problem=1220 Mysterious Bacteria Time Limit:500MS     Memory Limit:32768KB     64bit IO Format:%lld & %llu Submit Status Practice LightOJ 1220 Description Dr. Mob has just discovered a Deathly Bacteria. He na…
这是 meelo 原创的 IEEEXtreme极限编程大赛题解 Xtreme 10.0 - Mysterious Maze 题目来源 第10届IEEE极限编程大赛 https://www.hackerrank.com/contests/ieeextreme-challenges/challenges/mysterious-maze There is a valuable treasure that is hidden below a complex maze. The maze is made…
D. Mysterious Present 题目连接: http://www.codeforces.com/contest/4/problem/D Description Peter decided to wish happy birthday to his friend from Australia and send him a card. To make his present more mysterious, he decided to make a chain. Chain here i…
题目传送门 题目大意: 给出m个1-n的全排列,问这m个全排列中有几个公共子串. 思路: 首先单个的数字先计算到答案中,有n个. 然后考虑多个数字,如果有两个数字相邻,那么在m个串中必定都能找到这两个数字并且位置相邻.那么我们枚举1-n所有的数字,比如先枚举p1是1,那p2就是在全排列1中p1后面的数字,然后往下面找,看看下面的全排列,p2是不是也在p1的后面,如果是的话,再看p3是不是在p2的后面. 要注意的是,如果我们发现p2在p1的后面,那么我们就把p1p2连起来,合并到dp[1][p1]…
题目链接 参考博客Ritchie丶的博客 - UVALive 7267 Mysterious Antiques in Sackler Museum (判断长方形) 题意:大概意思就是判断四个矩形能不能从中选取三个矩形组成一个大的矩形. 题解: 从四个矩形中任选三个,这样有四种选法. 三个矩形能凑成一个矩形首先是两个矩形有一条边相等,第三个矩形要么有边跟他们相等的边相等,要么有边跟他们不相等的边的和相等(有点绕). 想明白这两点之后直接暴力就可以了,当时训练赛的时候因为读错题然后一直WA烦躁一直没…
C - Mysterious Present Peter decided to wish happy birthday to his friend from Australia and send him a card. To make his present more mysterious, he decided to make a chain. Chain here is such a sequence of envelopes A = {a1,  a2,  ...,  an}, where…
CodeChef-RNDRATIO Mysterious Ratio 题意简述: 对每个 \(1 \le i \le n\) ,随机选择一个数 \(A_i\) ,满足 \(L_i \le A_i \le R_i\) ,求 \(\mathrm{lcm}_{i=1}^n A_i\) 的期望. \(1 \le n \le 10^5\) , \(1 \le L_i \le R_i \le 10^5\) . Example Input: 2 1 1 3 2 2 4 5 5 Example Output:…
Mysterious  BUUCTF-2019 int __stdcall sub_401090(HWND hWnd, int a2, int a3, int a4) { char v5; // [esp+50h] [ebp-310h] CHAR Text[4]; // [esp+154h] [ebp-20Ch] char v7; // [esp+159h] [ebp-207h] __int16 v8; // [esp+255h] [ebp-10Bh] char v9; // [esp+257h…
Mysterious For-HDU 4373 题目描述 MatRush is an ACMer from ZJUT, and he always love to create some special programs. Here we will talk about one of his recent inventions. This special program was called "Mysterious For", it was written in C++ languag…
[题目] D. Mysterious Crime [描述] 有m个n排列,求一共有多少个公共子段. 数据范围:1<=n<=100000,1<=m<=10 [思路] 对于第一个排列来说,如果第k个位置开始往后L长的子段是一个公共的子段,那么从k开始往后数1,2,...,L-1长的子段都是公共的子段:如果第k个位置开始往后L长的子段是一个公共的子段,但第k个位置开始往后L+1长的子段不是一个公共的子段,那么位置k到位置k+L中任一位置j开始往后直到位置k+L的子段都不是公共的子段.这就…
http://lightoj.com/volume_showproblem.php?problem=1220 题目大意: 给你一个x,求出满足 x=b^p, p最大是几. 分析:x=p1^a1*p2^a2*...*pn^an; p最大是gcd(a1,a2,...,an). ///他该诉你x,b,p都是整数,所以x,b有可能是负数.当x是负数时,p不能是偶数. #include<stdio.h> #include<string.h> #include<stdlib.h>…
题目链接:http://lightoj.com/volume_showproblem.php?problem=1220 题意:已知 x=bp 中的 x 求最大的 p,其中 x b p 都为整数 x = (p1a1*p2a2*p3a3*...*pkak), pi为素数;则结果就是gcd(a1, a2, a3,...,ak); 当x为负数时,要把ans缩小为奇数; #include <stdio.h> #include <string.h> #include <iostream&…
link:http://codeforces.com/problemset/problem/4/D #include <iostream> #include <cstdio> #include <cstdlib> #include <cstring> #include <cmath> #include <cctype> #include <algorithm> #include <queue> #include…
Sackler Museum of Art and Archaeology at Peking University is located on a beautiful site near the West Gate of Peking University campus, and its architecture takes the inspiration from buildings that already exist on campus. The collection of Chines…
走迷宫 ~ 不同的是题目给了你转向的方向序列 dis[x][y]表示到(x,y) 使用了最少的转向次数 #include<cstdio> #include<cstring> #include<cmath> #include<algorithm> #include <queue> using namespace std; const int maxn = 1010; const int inf = (1<<30); int dx[4]…
题意:给定四个矩形,要求从中选出三个,能不能拼成一个矩形. 析:说到这个题,我还坑了队友一次,读题读错了,我直接看的样例,以为是四个能不能组成,然后我们三个就拼命想有什么简便方法,后来没办法了,直接暴力. 康神写了6000多B的代码,全是循环和if-else,我们画出五种情况....然而并不是这样, 只要几个if-else就够,因为就3个,两种情况. 代码如下; #pragma comment(linker, "/STACK:1024000000,1024000000") #inclu…
1. 题目描述有两种不同类型的循环,并给出一个由1.2组成的序列,表示嵌套的循环类型.问这样组着的循环一共需要多少次循环?并将结果模364875103. 2.基本思路显然,每当遇到一个类型1的序列,即可以判定12...2的嵌套循环共多少次,而1类型的循环次数为常亮.因此,将原序列从1分开,并将每个子序列的循环次数相乘即为总的循环次数.1     共循环n次 = C[n][1]12   共循环n*(n+1)/2次 = C[n+1][2]122 共循环n*(n+1)*(n+2)/6次 = C[n+2…
暴力就行了,找出素因子,正的最多是30,然后负的最多是31(这一点wa了一次) #include <cstdio> #include <iostream> #include <ctime> #include <vector> #include <cmath> #include <map> #include <queue> #include <algorithm> #include <cstring>…
题目大意 给你一张宽为w,长为h的的贺卡,然后给你n个信封,每个信封宽为wi,长为hi,问你最多能在贺卡上嵌套多少个信封,如果某个信封i如果能够装在信封j里,当且仅当w[i]<w[j]&&h[i]<h[j] 题解 就是LIS嘛,没啥好说的... 代码: #include <iostream> #include <algorithm> #include <cstdio> #include <cstring> using namesp…
http://codeforces.com/contest/4/problem/D 题目大意: 给出n个信封,这n个信封有长和宽,给出卡片的尺寸,求取能够装入卡片的最长的序列,序列满足后一个的长和宽一定大于前一个,求最长的这个序列的长度,并且给出一组可行解. 思路:最长上升子序列 #include<cstdio> #include<cmath> #include<cstring> #include<algorithm> #include<iostrea…
2015北京区域赛现场赛第2题. 题面:http://media.hihocoder.com/contests/icpcbeijing2015/problems.pdf OJ链接:http://hihocoder.com/problemset/problem/1255 题意:给4个矩形的宽和高,问能否选出3个拼成一个大矩形. 解法:可以称之为构造.暴力.枚举.搜索 当时场上写了个很无脑的版本,变量a,b,c一个个枚举,没有可扩展性. 其实稍加分析,把判断和枚举的两个模块独立开来: 1. 判断的过…
题目链接:http://media.hihocoder.com/contests/icpcbeijing2015/problems.pdf 题目大意:给你四个矩形,判断是否能取其中任意三个组成一个大矩形 思路:模拟暴力 #include <stdio.h> #include <string.h> #include <stdlib.h> #include <iostream> #include <algorithm> using namespace…