Remember the story of Little Match Girl? By now, you know exactly what matchsticks the little match girl has, please find out a way you can make one square by using up all those matchsticks. You should not break any stick, but you can link them up, a…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 回溯法 日期 题目地址:https://leetcode.com/problems/matchsticks-to-square/description/ 题目描述 Remember the story of Little Match Girl? By now, you know exactly what matchsticks the little…

A trickier DFS, with a little bit complex recursion param tweak, and what's more important is pruning strategies.. or your code will TLE. class Solution { bool go(vector<bool> &m, int edge, int eleft, int etgt, vector<int> &in, int tak…

还记得童话<卖火柴的小女孩>吗?现在,你知道小女孩有多少根火柴,请找出一种能使用所有火柴拼成一个正方形的方法.不能折断火柴,可以把火柴连接起来,并且每根火柴都要用到.输入为小女孩拥有火柴的数目,每根火柴用其长度表示.输出即为是否能用所有的火柴拼成正方形.示例 1:输入: [1,1,2,2,2]输出: true解释: 能拼成一个边长为2的正方形,每边两根火柴. 示例 2:输入: [3,3,3,3,4]输出: false解释: 不能用所有火柴拼成一个正方形.注意:    给定的火柴长度和在 0 到…

题目如下: 解题思路:居然把卖火柴的小女孩都搬出来了.题目的意思是输入一个数组,判断能否把数组分成四个子数组,使得每个子数组的和相等.首先我们可以很容易的求出每个子数组的和应该是avg = sum(nums)/4,接下来我的思路是求出nums中所有和等于avg的子数组,子数组中保存元素下标,然后找出四个不存在相同下标的子数组求并集,如果并集长度刚好等于len(nums),那么就是符合条件的,返回true.如果在子数组列表中找到四个符合条件的子数组,我用的是DFS,为什么不用BFS?因为题目要求是…

Leetcode之深度优先搜索(DFS)专题-473. 火柴拼正方形(Matchsticks to Square) 深度优先搜索的解题详细介绍,点击 还记得童话<卖火柴的小女孩>吗?现在,你知道小女孩有多少根火柴,请找出一种能使用所有火柴拼成一个正方形的方法.不能折断火柴,可以把火柴连接起来,并且每根火柴都要用到. 输入为小女孩拥有火柴的数目,每根火柴用其长度表示.输出即为是否能用所有的火柴拼成正方形. 示例 1: 输入: [1,1,2,2,2] 输出: true 解释: 能拼成一个边长为2的…

Remember the story of Little Match Girl? By now, you know exactly what matchsticks the little match girl has, please find out a way you can make one square by using up all those matchsticks. You should not break any stick, but you can link them up, a…

Remember the story of Little Match Girl? By now, you know exactly what matchsticks the little match girl has, please find out a way you can make one square by using up all those matchsticks. You should not break any stick, but you can link them up, a…

Remember the story of Little Match Girl? By now, you know exactly what matchsticks the little match girl has, please find out a way you can make one square by using up all those matchsticks. You should not break any stick, but you can link them up, a…

一开始想求所有结果为target的组合来着,但是所选元素不能重叠.用这个递归思想很简单,分成四个桶,每次把元素放在任意一个桶里面,最后如果四个桶相等就可以放进去,有一个地方可以剪枝,假如任意一个桶的元素和大于了target果断return.另一个优化的点在于,如果要求能不能也就是找到一个就可以的话,那么从大到小的找可以减少回溯的次数,否则会超时.学会了一个sort函数从大到小排序的新方法.sort(nums.rbegin(),nums.rend()); leetcode不能用sort(,,cmp…

终于将LeetCode的免费题刷完了,真是漫长的第一遍啊,估计很多题都忘的差不多了,这次开个题目汇总贴,并附上每道题目的解题连接,方便之后查阅吧~ 477 Total Hamming Distance 44.10% Meidum 475 Heaters  30.20% Easy 474 Ones and Zeroes  34.90% Meidum 473 Matchsticks to Square  31.80% Medium 472 Concatenated Words 29.20% Hard…

417. Pacific Atlantic Water Flow 思路:构造两个二维数组分别存储大西洋和太平洋的结果,先初始化边界,然后从边界出发,深度优先遍历,标记满足条件的所有节点 static int[] dx = new int[]{-1,0,0,1}; static int[] dy = new int[]{0,1,-1,0}; public List<int[]> pacificAtlantic(int[][] matrix) { List<int[]> res = n…

突然很想刷刷题,LeetCode是一个不错的选择,忽略了输入输出,更好的突出了算法,省去了不少时间. dalao们发现了任何错误,或是代码无法通过,或是有更好的解法,或是有任何疑问和建议的话,可以在对应的随笔下面评论区留言,我会及时处理,在此谢过了. 过程或许会很漫长,也很痛苦,慢慢来吧. 编号 题名 过题率 难度 1 Two Sum 0.376 Easy 2 Add Two Numbers 0.285 Medium 3 Longest Substring Without Repeating C…

DFS基础 深度优先搜索(Depth First Search)是一种搜索思路,相比广度优先搜索(BFS),DFS对每一个分枝路径深入到不能再深入为止,其应用于树/图的遍历.嵌套关系处理.回溯等,可以用递归.堆栈(stack)实现DFS过程. 关于广度优先搜索(BFS)详见:算法与数据结构基础 - 广度优先搜索(BFS) 关于递归(Recursion)详见:算法与数据结构基础 - 递归(Recursion) 树的遍历 DFS常用于二叉树的遍历,关于二叉树详见: 算法与数据结构基础 - 二叉查找树…

All LeetCode Questions List(Part of Answers, still updating) 题目汇总及部分答案(持续更新中) Leetcode problems classified by company 题目按公司分类(Last updated: October 2, 2017) .   Top Interview Questions # Title Difficulty Acceptance 1 Two Sum Medium 17.70% 2 Add Two N…

源代码地址:https://github.com/hopebo/hopelee 语言:C++ 301. Remove Invalid Parentheses Remove the minimum number of invalid parentheses in order to make the input string valid. Return all possible results. Note: The input string may contain letters other tha…

终于将LeetCode的免费题刷完了,真是漫长的第一遍啊,估计很多题都忘的差不多了,这次开个题目汇总贴,并附上每道题目的解题连接,方便之后查阅吧~ 如果各位看官们,大神们发现了任何错误,或是代码无法通过OJ,或是有更好的解法,或是有任何疑问,意见和建议的话,请一定要在对应的帖子下面评论区留言告知博主啊(如果不方便注册博客园的话,可以下载下文提到的APP,在Feedback中给博主发邮件交流哈),同时也请大家踊跃地,大量地,盲目地提供各个题目的follow up一起讨论哈,多谢多谢,祝大家刷得愉快…

题目如下: 解题思路:本题是[leetcode]473. Matchsticks to Square的姊妹篇,唯一的区别是[leetcode]473. Matchsticks to Square指定了分成四个子数组,而本题分成的份数不定,作为参数输入.另外,本题的测试用例好像复杂一点,因此我过滤掉了nums中值等于avg的元素,不参与后面的DFS计算,提高效率. 代码如下: class Solution(object): def canPartitionKSubsets(self, nums,…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 回溯法 日期 题目地址:https://leetcode.com/problems/partition-to-k-equal-sum-subsets/description/ 题目描述 Given an array of integers nums and a positive integer k, find whether it's possibl…

请点击页面左上角 -> Fork me on Github 或直接访问本项目Github地址:LeetCode Solution by Swift    说明:题目中含有$符号则为付费题目. 如:[Swift]LeetCode156.二叉树的上下颠倒 $ Binary Tree Upside Down 请下拉滚动条查看最新 Weekly Contest!!! Swift LeetCode 目录 | Catalog 序        号 题名Title 难度     Difficulty  两数之…

[98]Validate Binary Search Tree [99]Recover Binary Search Tree [100]Same Tree [101]Symmetric Tree [104]Maximum Depth of Binary Tree [105]Construct Binary Tree from Preorder and Inorder Traversal [106]Construct Binary Tree from Inorder and Postorder T…

原题链接在这里:https://leetcode.com/problems/partition-to-k-equal-sum-subsets/description/ 题目: Given an array of integers nums and a positive integer k, find whether it's possible to divide this array into k non-empty subsets whose sums are all equal. Examp…

Description The left figure below shows a complete 3*3 grid made with 2*(3*4) (=24) matchsticks. The lengths of all matchsticks are one. You can find many squares of different sizes in the grid. The size of a square is the length of its side. In the…

Description The left figure below shows a complete 3*3 grid made with 2*(3*4) (=24) matchsticks. The lengths of all matchsticks are one. You can find many squares of different sizes in the grid. The size of a square is the length of its side. In the…

700. 二叉搜索树中的搜索 - 树 给定二叉搜索树(BST)的根节点和一个值. 你需要在BST中找到节点值等于给定值的节点. 返回以该节点为根的子树. 如果节点不存在,则返回 NULL. 思路: 二叉搜索树的特点为左比根小,右比根大.那么目标结点就有三种可能: 1. 和根一样大,那么直接返回根即可. 2. 比根的值小,那么应该再去次左子树中搜索. 3. 比根的值大,那么应该再次去右子树中搜索. 可以看到这就是一个递归的思路. class Solution: def searchBST(self…

LeetCode 题解 593. Valid Square (Medium) 判断给定的四个点,是否可以组成一个正方形 https://leetcode.com/problems/valid-square/solution/ bug "use strict"; /** * * @author xgqfrms * @license MIT * @copyright xgqfrms * @created 2020-11-11 * @modified * * @description 593…

Given a sequence of words, check whether it forms a valid word square. A sequence of words forms a valid word square if the kth row and column read the exact same string, where 0 ≤k < max(numRows, numColumns). Note: The number of words given is at le…

Given a positive integer num, write a function which returns True if num is a perfect square else False. Note: Do not use any built-in library function such as sqrt. Example 1: Input: 16 Returns: True Example 2: Input: 14 Returns: False Credits:Speci…

Given a 2D binary matrix filled with 0's and 1's, find the largest square containing all 1's and return its area. For example, given the following matrix: 1 0 1 0 0 1 0 1 1 1 1 1 0 0 1 0 Return 4. Credits:Special thanks to @Freezen for adding this pr…

OPEN CASCADE Gauss Least Square eryar@163.com Abstract. The least square can be used to solve a set of n linear equations of m unknowns(n >= m). The OPEN CASCADE class math_GaussLeastSquare implements the least square solution of the linear equations…