list_1=set([4,5,6,7])list_2=set([4,8,9])list_3=set([4,5])list_4=set([6,7])a = (2,3)b = (2) #list_3是list_1的子集则为真:print(list_3.issubset(list_1))#b属于a则为真:print (b in a)#找出列表中元素的个数:print(len(list_2))#:a,b中没有任何相同的元素则为真:print (list_2.isdisjoint(list_3))pri…