You are given two integer arrays nums1 and nums2 sorted in ascending order and an integer k. Define a pair (u,v) which consists of one element from the first array and one element from the second array. Find the k pairs (u1,v1),(u2,v2) ...(uk,vk) wit…

[LeetCode]373. Find K Pairs with Smallest Sums 解题报告(Python) 标签: LeetCode 题目地址:https://leetcode.com/problems/find-k-pairs-with-smallest-sums/description/ 题目描述: You are given two integer arrays nums1 and nums2 sorted in ascending order and an integer k…

［抄题］: You are given two integer arrays nums1 and nums2 sorted in ascending order and an integer k. Define a pair (u,v) which consists of one element from the first array and one element from the second array. Find the k pairs (u1,v1),(u2,v2) ...(uk,v…

You are given two integer arrays nums1 and nums2 sorted in ascending order and an integer k. 给你两个数组nums1和nums2,这两个数组都是递增排列的,还给你一个整数k. Define a pair (u,v) which consists of one element from the first array and one element from the second array. 定义一个pa…

题目: You are given two integer arrays nums1 and nums2 sorted in ascending order and an integer k. Define a pair (u,v) which consists of one element from the first array and one element from the second array. Find the k pairs (u1,v1),(u2,v2) ...(uk,vk)…

https://leetcode.com/problems/find-k-pairs-with-smallest-sums/ You are given two integer arrays nums1 and nums2 sorted in ascending order and an integer k. Define a pair (u,v) which consists of one element from the first array and one element from th…

You are given two integer arrays nums1 and nums2 sorted in ascending order and an integer k. Define a pair (u,v) which consists of one element from the first array and one element from the second array. Find the k pairs (u1,v1),(u2,v2) ...(uk,vk) wit…

给定两个以升序排列的整形数组 nums1 和 nums2, 以及一个整数 k.定义一对值 (u,v),其中第一个元素来自 nums1,第二个元素来自 nums2.找到和最小的 k 对数字 (u1,v1), (u2,v2) ... (uk,vk).示例 1:给出: nums1 = [1,7,11], nums2 = [2,4,6],  k = 3返回: [1,2],[1,4],[1,6]返回序列中的前 3 对数:[1,2],[1,4],[1,6],[7,2],[7,4],[11,2],[7,6],…

You are given two integer arrays nums1 and nums2 sorted in ascending order and an integer k. Define a pair (u,v) which consists of one element from the first array and one element from the second array. Find the k pairs (u1,v1),(u2,v2) ...(uk,vk) wit…

本题的特点在于两个list nums1和nums2都是已经排序好的.本题如果把所有的(i, j)组合都排序出来,再取其中最小的K个.其实靠后的很多组合根本用不到,所以效率较低,会导致算法超时.为了简便,把nums1和nums2里面的元素写成A1,A2,...,A5, B1,...,B5. 维护一个最小堆.并逐渐往里面push and pop元素. 注意以下几点:1. 如果(Ai, Bj)大于堆顶的元素,那么没有比较把(Ai, Bj)和它之后的元素Push进堆.2. 为了便于管理,解法里其实只维护…

You are given two integer arrays nums1 and nums2 sorted in ascending order and an integer k. Define a pair (u,v) which consists of one element from the first array and one element from the second array. Find the k pairs (u1,v1),(u2,v2) ...(uk,vk) wit…

You are given two integer arrays nums1 and nums2 sorted in ascending order and an integer k. Define a pair (u,v) which consists of one element from the first array and one element from the second array. Find the k pairs (u1,v1),(u2,v2) ...(uk,vk) wit…

You are given two integer arrays nums1 and nums2 sorted in ascending order and an integer k. Define a pair (u,v) which consists of one element from the first array and one element from the second array. Find the k pairs (u1,v1),(u2,v2) ...(uk,vk) wit…

［抄题］: 在一个排序矩阵中找从小到大的第 k 个整数. 排序矩阵的定义为:每一行递增,每一列也递增. ［思维问题］: 不知道应该怎么加,因为不是一维单调的. ［一句话思路］: 周围两个数给x或y挪一位, 如果hash数组没有就添加到minheap中 ［输入量］:空: 正常情况:特大:特小:程序里处理到的特殊情况:异常情况(不合法不合理的输入): ［画图］: ［一刷］: class Pair(没有参数)中要有数据类型.方法Pair(int x , int y, int val) PairComp…

UVA - 11997 K Smallest Sums Time Limit: 1000MS   Memory Limit: Unknown   64bit IO Format: %lld & %llu [Submit]   [Go Back]   [Status] Description   Problem K K Smallest Sums You're given k arrays, each array has k integers. There are kk ways to pick…

Problem K K Smallest Sums You're given k arrays, each array has k integers. There are kk ways to pick exactly one element in each array and calculate the sum of the integers. Your task is to find the k smallest sums among them. Input There will be se…

UVa11997 K Smallest Sums  题目: K Smallest Sums You're given k arrays, each array has k integers. There are kk ways to pick exactly one element in each array and calculate the sum of the integers. Your task is to find the k smallest sums among them. In…

11997 - K Smallest Sums You’re given k arrays, each array has k integers. There are kk ways to pick exactly one element in eacharray and calculate the sum of the integers. Your task is to find the k smallest sums among them.InputThere will be several…

UVA - 11997 id=18702" target="_blank" style="color:blue; text-decoration:none">K Smallest Sums Time Limit: 1000MS   Memory Limit: Unknown   64bit IO Format: %lld & %llu Submit Status You're given k arrays, each array has k…

K Smallest Sums You're given k arrays, each array has k integers. There are kk ways to pick exactly one element in each array and calculate the sum of the integers. Your task is to find the k smallest sums among them. Input There will be several test…

题目传送门 题意:训练指南P189 分析:完全参考书上的思路,k^k的表弄成有序表: 表1:A1 + B1 <= A1 + B2 <= .... A1 + Bk 表2:A2 + B1 <= A2 + B2 <= ...  A2 + Bk ....... 表k:Ak + B1 <= Ak + B2 <= ...  Ak + Bk 可以维护一个k长度的数组表示当前的前k小的数字和,当第i行的数组读入时,先push第一个,也就是最小的,然后可以更新成第二个,就是 - B[i]…

考虑一个简单的问题,两个长度为n的有序数组A和B,从每个数组中各选出一个数相加,共n2中情况,求最小的n个数. 将这n2个数拆成n个有序表: A1+B1≤A1+B2≤... A2+B1≤A2+B2≤... ... An+B1≤An+B2≤... 然后用优先队列合并成一个有序表即可.队列中需要记录两个数的和s,以及在B中的下标b, 比如Aa+Bb出队以后,应该将Aa+B(b+1) = Aa + Bb - Bb + Bb+1 = s - Bb + bb+1入队 对于书上最后的一个思考问题,merge…

题意:K个数组每组K个值,每次从一组中选一个,共K^k种,问前K个小的. 思路:优先队列处理多路归并,每个状态含有K个元素.详见刘汝佳算法指南. #include<iostream> #include<cstdio> #include<cstdlib> #include<stack> #include<queue> #include<vector> #include<map> #include<algorithm&g…

uva11997:http://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&page=show_problem&category=24&problem=3148&mosmsg=Submission+received+with+ID+13942033 题意:给你k个数组,每个数组里有k个数,然后每个数组里面取出一个数相加会得到一个数,让你求出最小的看的数. 题解:白书的分析: 分析:这题有…

来自<训练指南>优先级队列的例题. 题目链接:http://acm.hust.edu.cn/vjudge/problem/viewProblem.action?id=18702 题意:给定k个整数数组,各包含k个元素.在每个数组中取一个元素加起来,可以得到kk个和,求这些和中最小的k个值(不去重). 数据范围:k [2, 750] 思路:暴力枚举k^k不可取. “先来看问题的简化版:给出两个长度为k的数组A和B,分别在A和B中任取一个数并相加,可以得到k^2个和,求这些和中最小的k个.” 首先…

·哦,这题要用优先队列?那大米饼就扔一个手写堆上去吧! ·英文题,述大意:       输入n个长度为n的序列(题中是k,2<=k<=750).一种结果定义为:从每个序列中都要挑选一个数加起来.挑选的不同种结果含有的元素可以重复,现在你需要求出在所有的nn个结果中,找到其中最小的n个结果,然后按照从小到大顺序输出这n个结果. ·分析:      我们可以从简单情况加以考虑以得到普遍结论.      当只有1个序列时,那么就直接排个序就可以了(虽然不在数据范围里).      当只有两个序列,也…

思路 经典的k路归并问题 问题先转换为2路的有序表归并 先让A[1~k]都和B[1]相加,然后加入堆中,取出堆顶(A[x]+B[y])之后,再放入A[x]+B[y+1] 代码 #include <cstdio> #include <cstring> #include <algorithm> #include <queue> using namespace std; struct QNode{ int val,s; bool operator < (co…

题目大意 有k个长度为k的数组,从每个数组中选出1个数,再把这k个数进行求和,问在所有的这些和中,最小的前k个和. 考虑将前i个数组合并,保留前k个和.然后考虑将第(i + 1)个数组和它合并,保留前k个和. 如果暴力的话就进行就暴力枚举每一对,然后进行求和,然后再选出前k个,然而这样会TLE. 可以考虑将另外一个数组进行排序.然后可以看做是k个已经排好序的数组进行归并 {A[] + B[], A[] + B[], ...} {A[] + B[], A[] + B[], ...} {A[] +…

题面 背景 输入 输出 翻译(渣自翻) 给定K个包含K个数字的表,要求将其能产生的\( k^{k} \)个值中最小的K个输出出来 题解 k路归并问题的经典问题 可以转化为二路归并问题求解 考虑A[],B[]两个有序数组 使用堆,记录一些二元组\( (x,y) \),x表示值,y表示对应的b的下标,因为我们是把b合并到a上,所以我们能够根据记录的下标推出后面的值 然后两两合并 所以就很简单 放代码 #include <cstdio> #include <algorithm> #inc…

vjudge 上题目链接:UVA 11997 题意很简单,就是从 k 个数组(每个数组均包含 k 个正整数)中各取出一个整数相加(所以可以得到 kk 个结果),输出前 k 小的和. 这时训练指南上的一道题,这道题的简化版其实在 15 年的广东省省赛出现过,当时是以送分题的形式出现的,可我还是没能做出来,归根到底还是看书不够,接触的题型不够多. ******************************************************大白书上的讲解开始**************…