Make a deep copy of an undirected graph, there could be cycles in the original graph. Assumptions The given graph is not null DFS /* * class GraphNode { * public int key; * public List<GraphNode> neighbors; * public GraphNode(int key) { * this.key =…

Each of the nodes in the linked list has another pointer pointing to a random node in the list or null. Make a deep copy of the original list. /** * class RandomListNode { * public int value; * public RandomListNode next; * public RandomListNode rand…

Shallow copy and Deep copy 第一部分: 一.来自wikipidia的解释: Shallow copy One method of copying an object is the shallow copy. In that case a new object B is created, and the fields values of A are copied over to B. This is also known as a field-by-field copy,…

Given n nodes labeled from 0 to n - 1 and a list of undirected edges (each edge is a pair of nodes), write a function to find the number of connected components in an undirected graph. Example 1: 0          3 |          | 1 --- 2    4 Given n = 5 and…

今天在研究一个关于 Bitmap deep copy 的问题, 经过一系列的查询,在StackOverFlow上面找到了答案,遂记录下来: public static Bitmap DeepCopyBitmap(Bitmap bitmap)        {            try            {                Bitmap dstBitmap = bitmap.Clone(new Rectangle(0, 0, bitmap.Width, bitmap.Heig…

本文属原创,转载请注明出处:http://www.cnblogs.com/robinjava77/p/5481874.html   (Robin) Student package base; import java.io.Serializable; /** * Created by robin on 2016/5/11. * * @author robin */ public class Student implements Cloneable,Serializable{ private Str…

Python中对于对象的赋值都是引用,而不是拷贝对象(Assignment statements in Python do not copy objects, they create bindings between a target and an object.).对于可变对象来说,当一个改变的时候,另外一个不用改变,因为是同时的,也就是说是保持同步的. 此时不想让他们同步的话可以使用copy模块,copy.copy()浅拷贝,copy.deepcopy()深拷贝. 前者是对整个对象的拷贝,对…

在使用OpenCV的三维立体重建的库时,一个重要的步骤就是生成左右视图的差异图Disparity,而控制生成disparity的参数的类是cv::StereoBM,我们有时候需要拷贝一份cv::StereoBM,然后改变其中的参数值,但是如果用默认的等号‘=’来进行拷贝,其实是浅拷贝,如果改变拷贝项的参数值,原来的参数值也会跟着改变,所以我们需要自己写一个深拷贝的函数,如下所示: /** * Deep copy cv::StereoBM bm1 to bm2 */ void copy_bm(co…

原题链接在这里:https://leetcode.com/problems/number-of-connected-components-in-an-undirected-graph/ 题目: Given n nodes labeled from 0 to n - 1 and a list of undirected edges (each edge is a pair of nodes), write a function to find the number of connected com…

Given n nodes labeled from 0 to n - 1 and a list of undirected edges (each edge is a pair of nodes), write a function to check whether these edges make up a valid tree. For example: Given n = 5 and edges = [[0, 1], [0, 2], [0, 3], [1, 4]], return tru…

1.深复制与浅复制的概念 ->浅复制(shallow copy)概念   在SDK Guides中(搜索copy),官方给出的浅复制概念为: Copying compound objects, objects such as collection objects that can contain other objects, must also be done with care. As you would expect, using the = operator to perform a co…

题目: 找出无向图汇总的相连要素 请找出无向图中相连要素的个数. 图中的每个节点包含其邻居的 1 个标签和 1 个列表.(一个无向图的相连节点(或节点)是一个子图,其中任意两个顶点通过路径相连,且不与超级图中的其它顶点相连.) 样例 给定图: A------B C \ | | \ | | \ | | \ | | D E 返回 {A,B,D}, {C,E}.其中有 2 个相连的元素,即{A,B,D}, {C,E} 解题: 广度优先+递归,写不出来,程序来源 Java程序: /** * Defini…

Number of Connected Components in an Undirected Graph Given n nodes labeled from 0 to n - 1 and a list of undirected edges (each edge is a pair of nodes), write a function to find the number of connected components in an undirected graph. Example 1:…

一 深度优先遍历,参考前面DFS(white and gray and black) 二 根据定点以及边数目进行判断 如果m(edge)大于n(vertex),那么肯定存在环 算法如下: 1 删除所有入度小于等于1的顶点, 并且将和这些顶点相关的顶点入度减1 2 将入度变为1的顶点全部删除,重复上述动作,如果最后还有顶点那么图中存在环 具体代码如下: #include <iostream> using namespace std; #define MAX_VERTEX_NUM 128 enum…

If you learned C++ carefully, you must have known something about the copy of object. For example, I defined a class called \(ABC\),and two variable \(x\) and \(y\) are \(ABC\)s. Like this: class ABC{ public: int a,b; }; int main(){ ABC x,y; x.a=;x.b…

Given n nodes labeled from 0 to n - 1 and a list of undirected edges (each edge is a pair of nodes), write a function to find the number of connected components in an undirected graph. Example 1: 0          3 |          | 1 --- 2    4 Given n = 5 and…

NumPy学习(索引和切片,合并,分割,copy与deep copy) 目录 索引和切片 合并 分割 copy与deep copy 索引和切片 通过索引和切片可以访问以及修改数组元素的值 一维数组 程序示例 import numpy as np #索引与切片 array=np.arange(3,15) print(array) print(array[3])#数组下标为3的元素 print('\n') print(array[1:3])#取从下标1到下标3,不包括下标3 print(array[…

1. '='的赋值方式会带有关联性 >>> import numpy as np >>> a = np.arange(4) >>> b = a >>> c = a >>> d = b >>> a[0] = 11 >>> print(a) [11 1 2 3] #改变a的第一个值,b.c.d的第一个值也会同时改变 >>> b is a True >>&g…

Find the Connected Component in the Undirected Graph Find the number connected component in the undirected graph. Each node in the graph contains a label and a list of its neighbors. (a connected component (or just component) of an undirected graph i…

在用到angular.extend的时候,正好碰到一个对象,是层层嵌套的Array, 结果发现只能extend第一层,查阅官文档,确实不支持deep copy: Note: Keep in mind that angular.extend does not support recursive merge (deep copy). 在stackoverflow找到一个方案,只是好像没什么用,看了一下他的写法,原来是在自行判断是否应该进入下一层递归,因为深拷贝的原始需求就是拷贝到最底层的每一个字段,…

Object copy An object copy is an action in computing where a data object has its attributes copied to another object of the same data type. An object is a composite data type in object-oriented programming languages. The copying of data is one of the…

Deep Learning of Graph Matching 阅读笔记 CVPR2018的一篇文章,主要提出了一种利用深度神经网络实现端到端图匹配(Graph Matching)的方法. 该篇文章理论性较强,较难读懂... 论文链接 介绍这篇文章之前,需要先了解一下什么是图匹配,图匹配是干嘛的. 图匹配 图匹配简单来说就是将已有的两个图中对应的顶点关联起来实现能量函数最大.以多目标跟踪任务来说,每帧图像中的观测都可以构成一个拓扑图,希望将两帧图像中的拓扑图匹配起来以实现同一条轨迹中的观测成功匹…

今天在写代码的时候遇到一个奇葩的问题,问题描述如下: 代码中声明了一个list,将list作为参数传入了function1()中,在function1()中对list进行了del()即删除了一个元素. 而function2()也把list作为参数传入使用,在调用完function1()之后再调用function2()就出现了问题,list中的值已经被改变了,就出现了bug. 直接上代码: list = [0, 1, 2, 3, 4, 5] def function1(list): del lis…

［抄题］: Given n nodes labeled from 0 to n - 1 and a list of undirected edges (each edge is a pair of nodes), write a function to find the number of connected components in an undirected graph. Example 1: Input: n = 5 and edges = [[0, 1], [1, 2], [3, 4]…

写在前面 其实看了这么多,总结一个结论: 拷贝的初衷的目的就是为了:修改原来的对象不能影响到拷贝出来得对象 && 修改拷贝出来的对象也不能影响到原来的对象 所以,如果原来对象就是immutable的,然后用使用copy,生成的对象也还是immutable的,原来和现在的对象都是不可变的,所以就没有必要单独在内存中开辟存储空间,既生成新的对象了.所以这样生成的叫浅拷贝(shallow copy). -----------------------------------------------…

Deep copy ,Shallow copy, copy constructor,"=" Dog.h #pragma once class Dog { public: char *name; Dog(); Dog(const Dog &it); ~Dog(); void operator =(const Dog &it); }; Dog.cpp #include "Dog.h" #include<string.h> #include&l…

原题链接在这里:https://leetcode.com/problems/number-of-connected-components-in-an-undirected-graph/ 题目: Given n nodes labeled from 0 to n - 1 and a list of undirected edges (each edge is a pair of nodes), write a function to find the number of connected com…

Given n nodes labeled from 0 to n - 1 and a list of undirected edges (each edge is a pair of nodes), write a function to find the number of connected components in an undirected graph. Example 1: Input: n = 5 and edges = [[0, 1], [1, 2], [3, 4]] 0 3…

Given n nodes labeled from 0 to n - 1 and a list of undirected edges (each edge is a pair of nodes), write a function to find the number of connected components in an undirected graph. Example 1: | | --- Given n = 5 and edges = [[0, 1], [1, 2], [3, 4…

首先查看拷贝模块(copy)发现: >>> help(copy)Help on module copy:NAME    copy - Generic (shallow and deep) copying operations.DESCRIPTION    Interface summary:                import copy                x = copy.copy(y)        # make a shallow copy of y       …