非常考虑思维全面性的一道题,考验是否能够考虑本问题的方方面面. 题目:将一个string转换为int.实现函数atoi()的功能. 先应该明确atoi()有哪些特殊功能:(正常的正负数情况我就不列了) input output ”+1“ 1 ”   +   1“  0(error了) ”       1“ 1(前头只有空格是合法的) ”12b45“ 12(取前面的数字) 溢出 : ”2147483648“(负数情况同) 2147483647(MAX_VALUE) 类似我对atoi()的功能不熟的…

String to Integer (atoi) Implement atoi to convert a string to an integer. Hint: Carefully consider all possible input cases. If you want a challenge, please do not see below and ask yourself what are the possible input cases. Notes: It is intended f…

Implement atoi to convert a string to an integer. Hint: Carefully consider all possible input cases. If you want a challenge, please do not see below and ask yourself what are the possible input cases. Notes: It is intended for this problem to be spe…

https://oj.leetcode.com/problems/string-to-integer-atoi/ 细节题,把一个字符串转换成整数 class Solution { public: int atoi(const char *str) { if(str == NULL) ; // remove all spaces ; while(str[i] != '/0' && str[i] == ' ') { i++; } // only contain spaces if(str[i]…

Implement atoi to convert a string to an integer. Hint: Carefully consider all possible input cases. If you want a challenge, please do not see below and ask yourself what are the possible input cases. Notes: It is intended for this problem to be spe…

Implement atoi to convert a string to an integer. Hint: Carefully consider all possible input cases. If you want a challenge, please do not see below and ask yourself what are the possible input cases. Notes: It is intended for this problem to be spe…

Implement atoi to convert a string to an integer. Hint: Carefully consider all possible input cases. If you want a challenge, please do not see below and ask yourself what are the possible input cases. Notes: It is intended for this problem to be spe…

刚看到题就想用数组做,发现大多数解也是用数组做的,突然看到一个清新脱俗的解法: int atoi(const char *str) { ; int n; string s(str); istringstream iss(s); iss>>n; return n; } 代码简洁,核心使用的是istringstream C++串流输入类,该类对象能把字符串对象str读出字符并写入到自定义的各种类型变量中.…

题意:字符串转正数 原题来自:https://leetcode.com/problems/string-to-integer-atoi/ 分析: <程序员面试宝典>上出现的面试题,主要是考虑到细节. 1. 字串为空或者全是空格,返回0: 2. 字串的前缀空格需要忽略掉: 3. 忽略掉前缀空格后,遇到的第一个字符,如果是‘+’或‘-’号,继续往后读:如果是数字,则开始处理数字:如果不是前面的2种,返回0: 4. 处理数字的过程中,如果之后的字符非数字,就停止转换,返回当前值: 5. 在上述处理过…

class Solution(object): def myAtoi(self, str): """ :type str: str :rtype: int """ intMax=2147483647 intMin=-2147483648 str=str.strip() strLen = len(str) if strLen <= 0: return 0 bolNegative = False tmp = str[0] start=0 if…