Bandwidth Given a graph (V,E) where V is a set of nodes and E is a set of arcs in VxV, and an ordering on the elements in V, then the bandwidth of a node v is defined as the maximum distance in the ordering between v and any node to which it is con…
1. Introduction The Saga of Ryzom is a persistent massively-multiplayer online game (MMORPG) released in September 2004 throughout Europe and North America, localised in 3 languages so far. It has been developed by Nevrax since 2000, and was taken ov…
Time limit: 3.000 seconds限时3.000秒 Problem问题 Given a graph (V,E) where V is a set of nodes and E is a set of arcs in VxV, and an ordering on the elements in V, then the bandwidth of a node v is defined as the maximum distance in the ordering between v…
What is iPerf / iPerf3 ? iPerf3 is a tool for active measurements of the maximum achievable bandwidth on IP networks. It supports tuning of various parameters related to timing, buffers and protocols (TCP, UDP, SCTP with IPv4 and IPv6). For each test…
Bandwidth Given a graph (V,E) where V is a set of nodes and E is a set of arcs in VxV, and an ordering on the elements in V, then the bandwidth of a node v is defined as the maximum distance in the ordering between v and any node to which it is conne…
题意:给一个无向图,每条边上都有容量的限制,要求求出给定起点和终点的最大流. 思路:每条无向边就得拆成2条,每条还得有反向边,所以共4条.源点汇点已经给出,所以不用建了.直接在图上跑最大流就可以了. #include <bits/stdc++.h> #define LL long long #define pii pair<int,int> #define INF 0x7f7f7f7f using namespace std; ; ; int s, t; int path[N],…
1153 - Internet Bandwidth PDF (English) Statistics Forum Time Limit: 2 second(s) Memory Limit: 32 MB On the Internet, machines (nodes) are richly interconnected, and many paths may exist between a given pair of nodes. The total message-carrying cap…
