--Group by State_ts "per X minutes"select to_char(state_ts, 'hh24')||':'||floor(to_char(state_ts, 'mi')/15)*15 tm, report_type, count(report_type)from PETRA_ODRC_PP_01.tru_Reg_txn_reportwhere state_ts > to_date('15-Mar-19 08.00.00 AM','DD-MON…

本作代码下载:https://files.cnblogs.com/files/xiandedanteng/LeftInnerNotExist20191222.rar 人们总是喜欢给出或是得到一个简单明了甚至有些粗暴的结论,但现实之复杂往往不是几句简单的话语所能描述.(版权所有) 下结论前,先让我们看一个对比实验. 有一张表delivery_history,表结构如下: CREATE TABLE delivery_history ( id ,) not null primary key, name…

感觉好久没有写sql语句了... 今天需要写一个统计某一天的数据时,考虑到字段的内容格式是:  2018-12-18 09:36:23 我开始写的是: select count(id) as reCount from t1 where dateValue(atTime)=" & sqlDate(theDate) 数据量在1万行记录的时候,尽然需要 3 秒+时间才能完成. 等所有代码完工后,我试着使用 Between  语句: select count(id) as reCount fro…

string sql = "select to_char(StartTime, 'yyyy')||'-'|| to_char(StartTime, 'mm')||'-'|| to_char(StartTime, 'dd')||' '|| to_char(StartTime, 'hh24')||':'|| floor(to_char(StartTime, 'mi')/15)*15 statime, sum(Count) as Counts from table where StartTime &l…

1.按小时统计数量 SELECT TO_CHAR(RECEIVE_TIME,'HH24') HOUR ,COUNT(*) N FROM PH_PRESCRIPTION P WHERE TO_CHAR(P.RECEIVE_TIME ,'YYYY-MM-DD')='2018-12-05' GROUP BY TO_CHAR(RECEIVE_TIME,'HH24') ORDER BY TO_CHAR(RECEIVE_TIME,'HH24');…

所有版本的oracle都可以使用select wm_concat(name) as name from user; 但如果是oracle11g,使用select listagg(name, ',') within group( order by name) as name from user;效率更高,官方也更推荐这种写法.…

重建scott用户@?/rdbms/admin/utlsampl.sql@--执行?--$ORACLE_HOME 字符区分大小写:SELECT last_name, job_id, department_idFROM employeesWHERE last_name = 'Whalen' ; 使用字符函数:SELECT last_name, job_id, department_idFROM employeesWHERE upper(last_name) = 'WHALEN' ; SELECT…

思路:把两个表的数据按日期整合到临时表在按日期分组,求和. 例子: SELECT t.dateTime AS '日期',SUM(t.money) AS '表1利息',SUM(t.interest) AS '表2利息' FROM(SELECT DATE_FORMAT(date,'%Y-%m-%d') AS dateTime,SUM(money) AS money,'0' AS interest FROM Table1 GROUP BY DATE_FORMAT(date,'%Y-%m-%d')UNI…

源地址:http://zhidao.baidu.com/link?url=ZgCztNzCScRI5kAqGqug1LJvf7IX311EQs6fJ0-W1kOtWaaR7MrtLoV_228Ed8Fhbk6EZQeOSfZzCDQNcBUvtq select a, count(1) from tab group by a就可以找出a有几条记录 如果要找出多余一条的重复记录select a, count(1) from tab group by a having count(1) >1…

条件如下: convert(date,a.dtClock) = convert(date,b.dtClock)…