D. Numbers time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output One day Anna got the following task at school: to arrange several numbers in a circle so that any two neighboring numbers differs…

题目传送门 /* 图论/暴力:这是个连通的问题,每一次把所有度数为1的砍掉,把连接的点再砍掉,总之很神奇,不懂:) */ #include <cstdio> #include <cstring> #include <algorithm> #include <cmath> using namespace std; ; const int INF = 0x3f3f3f3f; int cnt[MAXN]; int a[MAXN]; bool g[MAXN][MAX…

题目传送门 /* BFS:三维BFS,坐标再加上步数,能走一个点当这个地方在步数内不能落到.因为雕像最多8步就会全部下落, 只要撑过这个时间就能win,否则lose */ #include <cstdio> #include <algorithm> #include <queue> #include <vector> #include <cstring> using namespace std; ; const int INF = 0x3f3f3…

B. Students and Shoelaces time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Anna and Maria are in charge of the math club for junior students. When the club gathers together, the students be…

题意:给你一个字符串,找第k大的子字符串.(考虑相同的字符串) 题解:建sam,先预处理出每个节点的出现次数,然后处理出每个节点下面的出现次数,然后在dfs时判断一下往哪边走即可,注意一下num会爆int //#pragma GCC optimize(2) //#pragma GCC optimize(3) //#pragma GCC optimize(4) //#pragma GCC optimize("unroll-loops") //#pragma comment(linker,…

C. Statues time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output In this task Anna and Maria play a game with a very unpleasant rival. Anna and Maria are in the opposite squares of a chessboard…

Codeforces Beta Round #76 (Div. 2 Only) http://codeforces.com/contest/94 A #include<bits/stdc++.h> using namespace std; #define lson l,mid,rt<<1 #define rson mid+1,r,rt<<1|1 #define sqr(x) ((x)*(x)) #define pb push_back #define eb emplac…

Codeforces Beta Round #80 (Div. 2 Only) A Blackjack1 题意 一共52张扑克,A代表1或者11,2-10表示自己的数字,其他都表示10 现在你已经有一个queen了,问你有多少种方案,能够得到n点 题解 其实只用考虑三种情况,都考虑一下就好了,实在不行就暴力枚举-- 代码 #include<bits/stdc++.h> using namespace std; int n; int main() { scanf("%d",&…

Codeforces Beta Round #83 (Div. 1 Only) A. Dorm Water Supply 题意 给你一个n点m边的图,保证每个点的入度和出度最多为1 如果这个点入度为0,那么这个点就是水龙头点. 如果这个点的出度为0,那么这个点就是储存点. 现在让你把所有水龙头到储存点的路径都输出出来,且输出这条路径的边权最小值 题解 显然是个仙人掌图,所以直接XJB暴力就好了 代码 #include<bits/stdc++.h> using namespace std; co…

Codeforces Beta Round #79 (Div. 2 Only) http://codeforces.com/contest/102 A #include<bits/stdc++.h> using namespace std; #define lson l,mid,rt<<1 #define rson mid+1,r,rt<<1|1 #define sqr(x) ((x)*(x)) #define pb push_back #define eb empla…